Zero

0 iska answer

0😊

Ek bhi nhi wo sab kha jayega 😅

0

0

It shall be 532 banana. 1- 200km x 1000, to and fro expense 400, remained 600 banana. 2- 200km x 1000, to and fro expense 400, remained 600 banana. Total = 1200. 3- 200km x 1000, only one way, expense 200, remained 800 banana. Total 600+600+800. 4- 334km x 1000, to and fro, expense 668, remained 332 banana. 5- 334km x 1000, only one way, expense 334, remained 666 banana. Total 332+666=998 banana. Distance covered 200km+334km=534km. 6- Remaining 466km x Remaining 998 banana, only one way, expense 466, remained 532 banana. Max 532 banana can be sent.

0

Yato phir 0 Or yato 2000

Answer zero

He never reached to the destination

3

I love how you take 1 Shlok from Geeta and explain it clearly in Hindi. Please keep doing this series... ❤️

3000

2000

It actually works

1000

0

We can transfer only 1 banana at a time then it will be 3 banana

534 bananas easy

0 because he can carry only 1000 banana at a time

3

0

335 ही केला पहुंचा पायेगा

250 bananas maximum

❤❤❤❤

0

0 is the right answer

1 🍌banana

😂😂 great idea

0

😮😮😮😮

Good idea😅

Zero

At right moment of my life krishna send some of his teachings to guide me on my way& it is one of them .

Beautifully explained sir❤

0 🎉

Use every 1/2 kilometer and come take other 1000 banana so all banana will make its destination 3000 bananas

🙏🙏👌👌🙌

1Km-1banana

999😊

If the camel carries 1000 bananas for 1000 km and eats 1 banana after 1 km, he will eat all 1000 bananas after 1000 km. so the answer is zero

1

Bdaa wala heeeellloooooo Sir. Vikash from jharkhand Sir aap toh logo ke social or mental well-being ke liye kitna kuch krte h. Unko apne life ko samjhne ke liye new new perspective sikhate h. Toh mera sawal ye h aap se apke life koi esa problem h jo apko v apke life m problems create krta ho.

666

raghav-yadviyam , vainkata dhwari

If anyone is looking for answer, here it is - 833. Here is detailed solution. (3 step) Step 1 - He will take 1000 bananas and travel 333 kms. Then he will leave remaining 667 bananas there and return back. He will do this 3 times. So in total he will have 2001 bananas at 333kms from starting point. Step 2 - Then he will take 1000 bananas and travel 500kms(i.e. 833 kms from starting point) and leave remaining 500 bananas there. Repeat this 2 times as there was 2000 bananas remaining. As a result he will have 1000 bananas at 833kms from start. Step 3 - take remaining 1000 banans and travel remaining 167 kms.

If anyone is looking for answer, here it is - 833. Here is detailed solution. (3 step) Step 1 - He will take 1000 bananas and travel 333 kms. Then he will leave remaining 667 bananas there and return back. He will do this 3 times. So in total he will have 2001 bananas at 333kms from starting point. Step 2 - Then he will take 1000 bananas and travel 500kms(i.e. 833 kms from starting point) and leave remaining 500 bananas there. Repeat this 2 times as there was 2000 bananas remaining. As a result he will have 1000 bananas at 833kms from start. Step 3 - take remaining 1000 banans and travel remaining 167 kms.

250

Maximum 1 Banana