Thank you so much for your kind words! I'm really glad you found the video helpful. I'll keep creating more content to help you and others!

check this out: kzbin.info/www/bejne/eHOtkquDiNFjo5Isi=2cgTbMpci5F8ccfe

You're very welcome! Glad you found it helpful!

Thanks for your feedback! Most of these equations can be solved using scientific calculators or online tools. I try to focus on explaining the concepts and the overall process behind the equations as going through every step of the mathematical calculations could make the videos too long.

Thanks for your kind words and support! I really appreciate your encouragement, and I hope the videos reach more people too! Feel free to share if you think someone might find them helpful!

I used similar triangles relationships. Maybe watching this video will help: kzbin.info/www/bejne/eHOtkquDiNFjo5Isi=3Is7iyc8Nl2n8REa

Sure. Will post more videos on this topic!

Good luck on your finals 😁💪🏽

Thanks for your feedback. I'm glad it was helpful!

Which two moments are you referring to?

​@@CivilEng_Amir oops, the support moment of 216 and the external moment of 40, in the diagram they are opposite directions but in the moment graph they are both negative I might be understanding it wrong though I'm new to the topic

@@chiefbeef6047 No, that's a great question actually, and sorry for the confusion. The support moment of 216 is negative, and the external moment of 40 is positive. At an x slightly smaller than 10 (for example 9.99999), your internal moment using the second function (8x-120) will be approximately equal to negative 40, and then at x=10, you have a positive external moment of 40. Now if you add that positive external moment of 40 to the negative internal one, you'll be back again at M=0. That's why we have that vertical line at the end. I'll try to solve more problems like this and explain it better!

@@CivilEng_Amir That explained it perfectly! thank you :)

@@chiefbeef6047 You're very welcome! I'm glad it made sense.

The total length of the beam is 10 ft, and we cut the beam at a distance x from the left end; So the length of the right segment will be 10-x.

@@CivilEng_Amir thanks sir.

@@CivilEng_Amir plz upload more videos on cut sections of beam

@@CRICKETEDITZ326 will do, stay tuned!

If you’re very deep below the surface, you might consider whether the surcharge effect has “dissipated” due to the soil’s behavior at depth. This is generally more relevant for point loads or localized pressures, which spread out and become less concentrated as depth increases. For broad, uniformly distributed surcharges, however, this effect is negligible at most practical depths, and the surcharge stress stays effectively constant. So we assume that the effect of a uniform surface load (like a surcharge) is distributed equally throughout the soil column below it. This assumption comes from the mechanics of materials and how uniform pressures propagate within a material under certain conditions. To summarize: the increase in effective stress due to the surcharge load remains constant with depth. A surcharge load, like a uniformly distributed load applied at the surface, adds a uniform pressure to the soil column. This surcharge load impacts the entire depth of soil with the same added stress.

Thanks a lot for your support! I've had a busy couple of weeks, but I'm grateful for your patience. I'm thrilled you liked the new content!

Thank you Amin!

Thanks Nick!

Of course! Good question. The strain in each direction depends not only on the stress in that direction, but also on the stresses in the two other directions as well as the change in temperature. So in this example where σz and ΔT are zero, εy will be negative with any σy value smaller than 0.33σx. For example if σx was +10 and σy was +3, εy would still be negative. I hope that makes sense.

@@CivilEng_Amir Gotcha, thank you!

Thanks for your feedback, glad it was hopeful 🙌🏽

Glad to hear! Thanks for your support ❤️

Thanks a lot!

I appreciate your kind words! Your support inspires me to keep improving. Stay tuned for more great content! 🙏😊

If you look at figure "a" again, you'll notice that the axial stress is decreasing from C to B and also from D to A. This results in a clockwise moment around the y-axis, which has a negative sign.

@@CivilEng_Amir I see, that makes sense now. Thank you!

@@SarahGilmour-dz3it No worries!

Thanks, glad you liked it!

Correct! It can handle a load more than three times greater than what the diagonal lap joint splice can bear (in this question)!

Thanks a lot 😊

You're very welcome!

Thanks, glad you think so!

You are very welcome!

Glad it was helpful, thanks for the feedback!

So nice of you!

Glad to hear it. Thanks for your feedback!

I tried to explain it so it'd make sense for everyone, haha! Thanks for your support!

Thanks for your support!