14:58 is the Reyneld Number ReL (rho*V*x)/mu where x is the length of the turbulent section?
@daraghosealbhaigh109115 күн бұрын
This is class all makes sense now
@aqibazmee953415 күн бұрын
Thank you for your impressive explanations. Could you make a series on aerothermodynamics and supersonic aerodynamics?
@ВадимСавенков-з2юАй бұрын
Is this scheme works well with tapered wings, or even wing with 0 taper ratio?
@jagrutpandya07Ай бұрын
Excellent video
@akarshshetty9262Ай бұрын
In the gravity driven flow scenario, I am confused as to why the dP/dX term does not go to zero as the flow is being primarily driven by the action of gravity. What is the reason for this assumption ?
@mokiboyАй бұрын
Could Froude have tried to scale using the two Reynolds and Drag coefficient matching instead to just scale one model? Or did he have to use Froude since it's his namesake? 😂
@Jeez-up8fvАй бұрын
Do you do practice problems?
@Jeez-up8fvАй бұрын
I wish you wrote notes a little slower, I have to pause the video 1000 times for one video. I like how you explain though
@prof.vanburenАй бұрын
Glad you like the explanations! Ultimately, I try and have these videos go at conversation speed, not writing speed (less lecture-style). You could try and watch them at a slower playback speed, or potentially have the PDF of the notes open on the side?
@mathijeba5375Ай бұрын
Did you just reply to everyone😮
@prof.vanburenАй бұрын
I try to!
@ArunachalamS-ir8spАй бұрын
This lecture is very useful for me as a mechanical engineer. However, I still have some doubts. At 4:29, you mentioned the pressure distribution over a cylinder. My question is, at the stagnation point, the velocity will be zero. I have studied that pressure is inversely proportional to velocity, so at the stagnation point, the pressure should be at its maximum. Is that correct?
@prof.vanburenАй бұрын
The pressure will be the stagnation pressure at the point where the fluid stops, which is typically the highest pressure point in the flow (you have traded all the bulk kinetic energy of the fluid for internal energy).
@59vijaiyaaravindthsr39Ай бұрын
thank you Prof.GOD!
@prof.vanburenАй бұрын
haha I'm glad you enjoyed it
@59vijaiyaaravindthsr39Ай бұрын
@@prof.vanburen yes 100% .whlle studying the working of Cd nozzle i came across a doubt. at second critical pressure when normal shock is at the end of the Cd nozzle the exit pressure which is the downstream pressure of the normal shock and at third critical pressure at which the normal shock has completely gone away form the CD nozzle so between second and third critical pressure there is a sudden huge drop in exit pressure (is my understanding right Prof?)
@59vijaiyaaravindthsr39Ай бұрын
hi sir, in rayleigh flow,during addiion of heat why should the static temperature drops to increase the velocity in high subsonic speed (above M = 0.845) till Mach 1 ? and how does cooling of supersonic flow results in increse of velocity sir??
@59vijaiyaaravindthsr39Ай бұрын
i can understand the process by looking at the enthalpy specific volume graph, but i cant understand the fundamentals sir
@michaellangone702Ай бұрын
thanks so much
@prof.vanburenАй бұрын
No problem!
@mahmutsemihdemirciАй бұрын
mixing humor and education... i really got it, thanks to you!
@prof.vanburenАй бұрын
I'm glad you got it!
@arnavroy57042 ай бұрын
Great video! Thank you so much!
@prof.vanburenАй бұрын
I'm glad it helped!
@reubenmatthew34422 ай бұрын
This helped me a lot. Thank you so much!!
@prof.vanburenАй бұрын
No problem! Happy it helped
@cakestronaut22052 ай бұрын
why would you not recommend integrating the pressure?
@prof.vanburenАй бұрын
Excellent question! Generally, the pressure data is pointwise and discretized along the surface, so fitting a function to it that you can then integrate is prone to errors. Certainly not impossible, and it has been done a bunch in the past. A particular favorite of mine is an experiment by GI Taylor, famed fluid mechanician, who flew an aircraft and simultaneously took pictures of a manometer in the cockpit that represented the pressure distribution over the wing in flight back in the early 1900s.
@ethankirk-harding41102 ай бұрын
I am looking to do automotive design at university but aerodynamics is really interesting to me so i cant wait to pit this on my personal statements
@prof.vanburenАй бұрын
Best of luck in your studies!
@suheladesilva29332 ай бұрын
Hello professor, thanks a lot for your video. I have one question, how would you determine the value of Gamma nought for an elliptical lift distribution. Thanks in advance.
@prof.vanburenАй бұрын
No problem! When Gamma(z) is arbitrary, the way to find it is a guess and check method (see around 19:28 in the video). You would start with guessing a Gamma distribution, then through a series of steps you can solve for the lift distribution which gives you a new Gamma. Plug this Gamma back into the beginning, and do that iteratively until Gamma converges. The video might be more clear!
@suheladesilva293328 күн бұрын
@@prof.vanburen thanks a lot for the reply.
@gamingCulture-lz5ne2 ай бұрын
Best Explanation of Flow variables and how they play a part in generating forces at Molecular level.
@prof.vanburenАй бұрын
Aw thanks!
@Uhhhhh-b1l2 ай бұрын
this was so fun to watch and interact with thank you !
@prof.vanburenАй бұрын
Glad you liked it!
@BeginningStarDarrenYKim2 ай бұрын
You should do more subjects man. I would watch them!!!
@prof.vanburenАй бұрын
I'd love to! I am sure I will eventually have to teach another class for uni, at that point more videos would be needed. Do you have any recommended courses?
@arashasadiabadi60132 ай бұрын
Thank you for your video!
@prof.vanburen2 ай бұрын
No problem!
@helllv93 ай бұрын
you're the best
@prof.vanburen3 ай бұрын
Thanks!!
@Dortmunder21513 ай бұрын
I want to learn so much about Aerodynamics 🎉😮
@prof.vanburen3 ай бұрын
This is a good place to start I hope!
@Dortmunder21513 ай бұрын
Thank you very much this and your other Videos help so much 😮🎉❤
@prof.vanburen3 ай бұрын
I'm glad they helped!
@RichardKCollins3 ай бұрын
Bad handwriting too hard to read. Use a computer, not a pen
@prof.vanburen3 ай бұрын
Thanks for the feedback!
@RichardKCollins3 ай бұрын
Bad handwriting, use a computer. There are about 5.4 Billion people using the Internet now. Step up your presentations to match, not down to a hypothetical or organization driven "captive class room". Your visualization are decent, but lack substantially because your drawing skills are not that great. Start with energy and the models, then talk about phenomena with data in hand. Not dribble it in vaguely when you happen to remember while talking. You use words too much where real world images would be better. Even Wikimedia images are better than writing words in English. Animations can be standard symbols of things, once learned and easy to generate, they become tools and reminders of what is possible. There are thousands of languages in the world, and hundreds written and used on the Internet. Most anyone might have seen the images, and never heard or seen the thousands of names people use. You did not link to the background. Like writing a book or paper with no references or index. When you seriously face billions of Internet users, do it consciously and professionally, or at least with some serious intent to talk to and show billions, not thousands. The world has changed and you can be a drag, throwing minds in many vague directions, or you can at every moment and movement reduce momentum, energy and acceleration losses. Turbulence is intimately tied to invisibility and inability to see and anticipate. So show everything, clearly and succinctly, and have everything at hand to bring to bear whatever might be lacking or wanting. It is possible. In many cases it is the difference between dying and survival in conflicts or complex pathways. Hypervelocities are already with us, but you are teaching methods that barely work for steam engines and fossil fuels. Filed as (The world needs complete, dynamic, anticipatory tools and methods, where speed matters) At 10,000 subscribers, KZbin and many other sites will monetize. Add $Thanks and make it easy for people to thank you. You are good, but with effort and intent you could be better. Richard Collins, The Internet Foundation
@TheAguiar683 ай бұрын
fascinating job! Very intuitive. What's the next step to go beyond and be prepared to work on aeronautics? Engineering College gives the background, but what can one do by self-learning to expertise at aeronautics?
@prof.vanburen3 ай бұрын
Thanks! I would start to explore projects you can DIY with open-source tools like XFoil (a vortex panel method solver), Simscale (a full CFD solver), and design tools like OpenVSP from NASA. This will get you designing and testing the flow over various objects you find interesting,
@MouyadOsama3 ай бұрын
I'm a high school student and I want to be an Aerospace Enginner, I know fluid mechanics and aerodynamics are important, I have the basic knowledge in math and physics and understand a higher level a bit, how can I learn and understand Fluid Mechanics and Aerodynamics well? Thanks for the video Prof!
@prof.vanburen3 ай бұрын
I think this is a good place to start if you have the math and physics background already, though maybe I would do Fluid Mechanics then Aerodynamics. There are a ton of online resources to learn, specifically NASA has a few learning modules that are open to everyone and very approachable.
@fanBladeOne4 ай бұрын
The recaps at the end are a real strengthening tool.
@prof.vanburen3 ай бұрын
I think so too!
@Moonlight-gg3nf4 ай бұрын
Thank you so much for a great effort in explain.
@prof.vanburen3 ай бұрын
Most welcome!
@iurijohnbolzan99044 ай бұрын
Your videos are amazing, man!!!! Congrats!! Your explanations are very clear and make the subject even more interesting!
@prof.vanburen3 ай бұрын
Aw thanks!
@ThomasHaberkorn4 ай бұрын
great video, but how does the starting vortex take shape in this line of reasoning?
@prof.vanburen3 ай бұрын
I'm not sure what you mean. Are you referring to the vortex initiated at the start of the flow---as in when the airfoil first accelerates?
@ThomasHaberkorn3 ай бұрын
@@prof.vanburen yes, exactly that
@ThomasHaberkorn4 ай бұрын
How does the airfoil shape produce rotation?
@prof.vanburen3 ай бұрын
Do you mean generally how a foil might turn the flow downwards, producing the circulation that is the footprint of lift? Or how in reality the no-slip boundary leads to a boundary layer full of rotational flow?
@ThomasHaberkorn3 ай бұрын
@@prof.vanburen the latter. I think this validates the Kutta condition
@Auday3654 ай бұрын
Great video thanks for sharing
@prof.vanburen3 ай бұрын
Thank you for watching!
@Veevercraft5 ай бұрын
I'm not a student and i want to study aerodynamics for my rocket thank's
@prof.vanburen3 ай бұрын
You're welcome, good luck in your studies!
@aqibazmee56535 ай бұрын
I absolutely loved watching your video. You're an amazing teacher 👍🏻
@prof.vanburen3 ай бұрын
Ah thank you so much!
@kadircanss5 ай бұрын
thanks for your extraordinary labor, it was perfectly helpful to understand the main concept. But fortunately, ı couldn't get the point when it comes the similarities. İs there any more precise definition about why Cp are equal for different scaled shapes. Or is there any resource that may help me in that subject. Thx again
@prof.vanburen3 ай бұрын
My pleasure! I looked through the video again because I wanted to be sure, I am not sure where Cp (which is sometimes pressure coefficient) pops up, but I suspect you mean Cl instead, as in the lift coefficient? If so, I should say first that Cl does not *perfectly* stay the same at different scales. Other concepts like turbulence and Reynolds number come into play here. However, for the most part, it is sufficiently equal across a wide range of different scales. This is because take into account all the variables that impact lift when we scale the problem. A bigger airfoil would produce bigger force at the same air speed, but lift coefficient takes that into account by scaling with the area. Does this help at all? Otherwise, I think the text by Anderson might be helpful here. Otherwise, my video in fluid mechanics on non-dimensional numbers more completely goes over these concepts in a way that is not restricted to aerodynamics.
@vgamer87075 ай бұрын
What a brilliant video, thank you very much!
@prof.vanburen3 ай бұрын
Thank you!
@Arsh-g6f5 ай бұрын
Thank you so much I’m a new student in aero space engineering and this helps me a lot I watched all of this whilst completing some assignments
@TITAN_26085 ай бұрын
Hey hi , I'm also doing aerospace engineering ( first year) and the college starts July 10 . I'm more passionate to learn about space shuttles , and i want to self learn . Is you can suggest me on how to self learn ? Thanks a lot ❤
@prof.vanburen3 ай бұрын
I am glad they helped!
@prof.vanburen3 ай бұрын
@TITAN_2608 Rocket science! I am not sure of any good references in this specific area---it's not really my area of expertise. I know NASA has a ton of good online resources, that's probably where I would start.
@TITAN_26083 ай бұрын
@@prof.vanburen thanks a lot
@flth10405 ай бұрын
Explanation at 10:30 is a bit wrong. We are riding on the wave front, fluid on the right seems to move towards us with speed a and on the left, it seems to move away from us with speed a-dv.
@prof.vanburen3 ай бұрын
Thanks for clarifying!
@flth10405 ай бұрын
There is an error in integral calculation in 15:28. Bounds of integral must be from pi to 0 otherwise lift force will be negative.
@prof.vanburen3 ай бұрын
Thanks for clarifying!
@flth10406 ай бұрын
fantastic. thanks for your effort to explain the concepts
@prof.vanburen3 ай бұрын
Thank you, I really appreciate you going through the videos so closely and catching my (many) goofs!
@flth10406 ай бұрын
You explained lots of misconceptions but forgot one which is Venturi effect. This effects is also wrong according to Nasa glenn research center but you base your idea on this concept. Anyway it is a good try.
@prof.vanburen3 ай бұрын
Thanks, but we will have to agree to disagree on this one. While I think the folks at NASA can be brilliant, I have seen the explanation you are referring to you and I don't find their rebuttal of the idea complete. And I think that's okay, because this is a very hard problem that doesn't get a simple answer! If flow passes by curvature---like one wall with a hill or the leading edge of an airfoil---it needs to react. If things are slow, the fluid just entirely (up to effectively infinitely away from the surface) moves up and over the curve and it is happy. This does not lead to the Venturi effect which is generally used to explain contracting enclosed systems. However, if it is moving rapidly by this curvature, shifting upwards takes time, and the flow might not have that time to react due to compressibility. So, if it can't get out of the way in time (and conservation of mass needs to be obeyed otherwise the world explodes) the flow can can do things like increase in density or speed up in this 2D approximation. Why is speeding up not an option for mass conservation? Would this not be a "virtual" contraction, where the "top wall" of the Venturi is really just reaction time? I know NASA in that reference discusses the flat plate as evidence, but the flat plate also leads to flow fields with curved streamlines that behave like more curved surfaces. Also, it talks about the bottom-side of the airfoil but there curvature is not nearly as rapid. Furthermore, the speed up explanation in this video is specifically attributed to traditional airfoil shapes and is only a smaller part of the big picture. It is this effect in combination with the others that lead to the supreme lift of airfoils. I am not sure my explanation is any more convincing, but I also don't see where in the aeronautics series from NASA that they explain the acceleration of flow around the curvature at the top of the airfoil, which certainly happens. It seems that course online just leads to "Euler equations are complicated". Yes they are. I have seen other explanations that include consideration of angular velocity and centrifugal things, but they didn't resonate with me (or perhaps I just didn't understand them well enough). Anyway, thanks for getting me to think about it more deeply!
@flth10406 ай бұрын
14:40 that is not the chain rule, that is the definition of the total differential😊
@prof.vanburen3 ай бұрын
Haha I have a mathematically talented grad student who also won't let me live this down. You're very correct here...but it certainly looks like a chain rule 🤔
@gabedarrett13016 ай бұрын
I finally understand! Thank you!
@prof.vanburen3 ай бұрын
My pleasure!
@ilovetitanium6 ай бұрын
THIS IS AWESOME man thank you SO MUCH for making these!!