there are infinitely many mines on my island - there is no way of getting out alive! *walks to the boat* hey man, what the fuck?

I was playing dandys world and randomly watching videos and then I realized I have no idea what you are talking about

I know this is not a new video, but it seems like you are describing "entire functions" and not just "analytic functions" when you talk about the global approximation being valid. Analytic functions only require being equal to their Taylor series in a neighborhood I believe.

Demons learning ANGEL LANGUAGES than say it’s simple. 🙄! Can’t make this up. IT’s a LANGUAGE RESPECT IT AS SUCH. IF U R a Child of X=RIS (Christ) learning this I PROMISE YOU THESE IDIOTS HAVE NO IDEA WHAT IT IS they can only preach in demon form so listen and learn well from them. They don’t believe nor see it your way. THIS LANGUAGE HAS A SOUND so it is a BEING. In your gods mind it will SPEAK TO YOU so LEARN that. ENGLISH or the language u r using is TEACHING YOU HOW TO LIE. So THESE TWO forms can’t be use to UNDERSTAND EACH OTHER. words use words to see Math use math to be. It’s not scary just HAD TO BE since EVIL are using it to create WEAPONS(other children) ON EARTH to use against YOUR KIND that can fluently speak this into REALITY. Math is A WHOLE BEING and we use it TO TRADE w MOTHER NATURE. It is the hall way of DREAMS. Only some of us HAVE ACCESS TO THIS BECAUSE SOME OF US DID THE WORK AND NATURE GAVE US THIS TRUST BLOODLINE. If others want it make them work for it, don’t let them TRICK U. 🙄🇭🇹

we can interpret fractional calculus as made up. i mean literally made up.

20 hexagon +12 pentagon; F=20+12=32; V=(20*6+12*5)/3=20*2+4*5=20*3=60; E=(20*6+12*5)/2=90; V-E+F=2; (So it is possible).

I think yes because you can always fine a 1/x such that it lies in between the last 1/x and infinity 1/x gap.

One of the very few problems that can be solved analytically.

Oiler ☝🏻

animations got weird mom

5;40 the ellipse looks like an eye when the axle moves

I dig the videos. Please content away.

24:31 Ah yes, the Voldemort fractional derivative, also known as Differius. Don't forget it's integration counter part Avada Integra

Taking the gamma function inside looks a lot like a sampling / convolving behavior, and the derivagral acting on non-local information... sounds a lot like gravity. Hmmmm.

My intuition is that even though the two are oscillating infinitely many times and don't have a limit, they are still staying between 1 and -1. In a sense, the limit is the range from -1≤y≤1, and that works from both sides. So if we fill in all of those values at x=0, we have all the values the limit could be, and since the range -1 to 1 is obviously connected, that necessarily connects the two ends of the function. That's obviously not rigorous at all, and is even probably poorly worded. But it is how I first thought of it.

square club approved

You assumed that at each vertex there meet three hexagons. You don't need to assume this: by double counting you find 2E = 6F, or F=E/3. Put this into Euler's formula: 2 = V-E+F = V-E-E/3 = V - 2/3*E and by rearranging (and using handshaking lemma) we find that the average degree is avg-deg = 2E/V = 3 - 6/V. But each vertex has degree AT LEAST 3. And so this cannot be.

7:00 cool ish road

some gears are designed to have jerky movement, for most cases, these arent used

I love this theme in my studies of math!

The only thing I'm confused on is taking the imaginary part in the final formula. (Never had any complex analysis so forgive me if this is a dumb question) Does it just simplify to y'(t)/y(t) since those are the only parts that had an i? Or would we compute everything out and then take the imaginary part? How does that work if you end with one complex expression over another? I feel like I'd need to see an example to understand/ see how it's useful. ><

is Euler formila ok to be used with a sphere?

A proof for why the sum of powers of 2 converges to -1 is as follows: Let's think in binary. The powers of 2 in binary are 1, 10, 100, 1000, etc. The sum of these powers is a number with infinitely many digits, all of which are 1. We'll call this ∆. If we add 1 to ∆, we get 0, since we continuously add 1 + 1 to get 10, writing 0 and carrying the 1. Therefore, ∆ + 1 = 0, or ∆ = -1.

21:00 is it just me or does it seem like the fractional derivatives are some how related to the rate of change within the function? And now that I think of it isn't that what integer Derivatives do anyway? Like Y=X toes to 1 because it grows at a constant rate. Where as Y=X2 grows at a rate Y=X + Y=X. Y=X^2 grows at a rate of Y=X2 + Y=X2. I'm not sure if I'm explaining this very well.

26:44 ahh yes, good old Croissant(uxv) 🙏👍

so for the fundamental theorem of integral calculus i can always take the derivative of an integral function but it doesn’t guarantees it twice, why can you take two derivatives? 12:47

"it all comes down to oiler's formula"

I was expecting eigen-stuff but not convolution!

but you can make a Moebius Strip ;)

why is there always 12 pentagons in balls nomatter how big it is

Bruh, imagine dual number integrals 😂😂😂

Why are you calling it a sum it is an integral

i see. so, the dark wizard Euler the Baller enchanted all spheres' area to be equal to 2.

This is why Serpulo has pentagonal sectors

I didn’t know Euler was pronounced like that, i thought it'd be "you-ler" and not "oiler"

Hyperbolic space?

I thought all of the are hexagons😮 i didn't look at the black

So that's why my soccer ball drawings always sucked

Can be done with derivatives too! (Not this but using Leibniz rule instead! Is pretty cool)

Maths is lovely.

But…but hexagons are the bestagons…

Do a circle

*This is…* read more

Another reason hexagons are not the best

Damn, I actually never noticed this hexagon-pentagon pattern on footballs

14:48 the theory of relativity...

You can make 1 ball with 1 ball shape

Hah! Not the bestagons!

There is no O in Euler!