The Basics on Factors in R | Learn R
12:18
Getting Started with R | Learn R
19:38
Monte Hall Problem Explained
8:18
2 жыл бұрын
Most Dangerous Setting in R | Learn R
11:23
Install R and R Studio | Learn R
16:35
Completely Randomized Design (CRD)
10:00
Regression: F-tests
15:35
3 жыл бұрын
One-way Analysis of Variance (ANOVA)
14:35
Regression diagnostics in (base) R
20:52
Simple Linear Regression
26:07
4 жыл бұрын
Пікірлер
@xavier32421
@xavier32421 26 күн бұрын
Love your work
@srijanbanerjee7658
@srijanbanerjee7658 Ай бұрын
Epic explanation ngl.
@omnamahshivaya-n3w
@omnamahshivaya-n3w Ай бұрын
sir can you make a video on how to arrange data on excel for 2 factor rcbd for analysis on r studio.
@jaradniemi
@jaradniemi 29 күн бұрын
that's an interesting idea. I've often thought about doing videos on using excel for sophisticated analyses. I'll keep the suggestion in mind...but I'm guessing you need an answer before I will get to a video.
@sonnetpodder8967
@sonnetpodder8967 Ай бұрын
I do this in the same way, Sir
@zoehaan
@zoehaan Ай бұрын
Can you spell that package for me..
@jaradniemi
@jaradniemi Ай бұрын
I don't believe there is any package mentioned in this video.
@ioewrcgeomaticsengineering5457
@ioewrcgeomaticsengineering5457 3 ай бұрын
Thankyou
@richtutors
@richtutors 5 ай бұрын
Thank you so much!
@sofiarubinc
@sofiarubinc 6 ай бұрын
Thanks a lot!! I was really afraid starting with R but your video helped me see it clearer
@leticiagarcia8108
@leticiagarcia8108 7 күн бұрын
❤ it
@nayanvats3424
@nayanvats3424 10 ай бұрын
What is the reason for using the "small y" as the "number of success" of success when we are already using "capital Y" as the script for the "random variable". Is it not confusing. What can go wrong if we use some other script.
@maintainyoursanitywhenbein6660
@maintainyoursanitywhenbein6660 11 ай бұрын
useful - thanks
@marcobarberomota1671
@marcobarberomota1671 Жыл бұрын
What if the groups are the same. Meaning, you got two binomial distributions from two models based on the same data that might be in two different representations. In that case the distributions to be compared are correlated. I know DeLongs method for example does a correction in terms of AUROC, is there something similar for binomial distributions? Thanks
@andelnicasio5047
@andelnicasio5047 Жыл бұрын
Excellent video! Thank you!
@domenicoscarpino3715
@domenicoscarpino3715 Жыл бұрын
Hello, thanks for the video. I was just wondering if replication would increase accuracy, precision or both. In control charts it's possible to distinguish systematic error from random error. I was trying to understand if replication helps to solve for systematic error in design of experiments.
@kottelkannim4919
@kottelkannim4919 Жыл бұрын
given: Y~U(0, 1) ==> F_Y(y) = y @ [0, 1] and F_X( x ) = g( x ) @ [0, 1] assume: X=g^-1( Y ) @ [0, 1] F_X( x )=P( X < x ) = P( g^-1(Y) < x ) = P( Y < g(x) ) the rightmost equality is justified since g(X) is a distribution function, i.e. monotonic and non-decreasing ==> F_X( x )=P( Y<g(x) ) = F_Y( g( x )) = g( x ) since F_Y( y ) = y @ [0,1]
@kottelkannim4919
@kottelkannim4919 Жыл бұрын
10:52 The comparative PMF plot shows Bin(n = 5, p = 0.01)and Po(lambda= 0.05).
@Mr.NotNotSoWrong
@Mr.NotNotSoWrong Жыл бұрын
Are neural networks like CNNs hierarchical models?
@sheilaabukayo5237
@sheilaabukayo5237 Жыл бұрын
This is an awesome lecture. Thank you
@scarlett7250
@scarlett7250 Жыл бұрын
😂
@kottelkannim4919
@kottelkannim4919 Жыл бұрын
9:03 subtitle says "posterior for the mean".
@jaradniemi
@jaradniemi Жыл бұрын
Definitely should say "posterior for the variance" thanks for pointing this out.
@kottelkannim4919
@kottelkannim4919 Жыл бұрын
2:51 Title says: Gamma CDF
@jaradniemi
@jaradniemi Жыл бұрын
Thanks! It should say "Student's t CDF". KZbin chapter has been updated, but I can't fix the slide without uploading a new video.
@kottelkannim4919
@kottelkannim4919 Жыл бұрын
Trying to summarize my understanding. P-value is the probability of getting the sampled data (and more extreme data) given it was sampled from null hypothesis H0 distribution. The alternative (Ha) distribution does *not* play any role in calculating the p-value. Next, the author simulates a quantity that resembles the point probability, P(H0 is true given |y-P95| < epsilon), where epsilon is some arbitrary nonzero constant that defines the neighborhood of P95 percentile of H0 distribution. This quantity *does* depend on the alternative Ha distribution (12:25 Bayes theorem). This is done by randomly picking H0 P95 percentile samples from either H0 or Ha distributions (according to prescribed relative frequencies of H0 and Ha) and calculating P(H0 is true given |y-P95| < epsilon) . P(H0 is true given |y-P95| < epsilon) increases: a. as P(Ha) decreases b. as |E(Ha)-E(H0)| increases
@kottelkannim4919
@kottelkannim4919 Жыл бұрын
1:36 Normal-->Binomial
@vesk4000
@vesk4000 Жыл бұрын
Thank you that was very useful!
@kishorkishu11
@kishorkishu11 Жыл бұрын
😅😅😅😅😅😅
@karlygashnuketayeva4948
@karlygashnuketayeva4948 Жыл бұрын
Hello! Thank you for the video! What if I have two vertical lines in my scatterplot when I do the linearity check? IV is gender and DV is continuous ... Looks weird :)
@jaradniemi
@jaradniemi Жыл бұрын
I'm not sure exactly what you mean by linearity check, but any plot with predicted/fitted values on the x-axis will have two vertical lines. This is completely expected since your IV only has 2 levels.
@karlygashnuketayeva4948
@karlygashnuketayeva4948 Жыл бұрын
@@jaradniemi Hello! Thank you! I meant testing the assumption for a linear relationship between IV and DV. Do we test that with the two-level categorical variable at all, such as gender? There are not too many sources on linear regression with such IV's..
@jaradniemi
@jaradniemi Жыл бұрын
​@@karlygashnuketayeva4948 The "linear" assumption occurs when the IV is continuous rather than categorical/binary. So, no you don't check the linear assumption when you have a categorical/binary variable. But you can check all the other assumptions: normality, independence, and constant variance. The reason there are not too many sources on linear regression with binary IVs is because this model is equivalent to the model used for a t-test. Thus, most people just say they are using a t-test. At 8:35 in the video, I point out that these two models are equivalent.
@lucianamicaelajaimecano4705
@lucianamicaelajaimecano4705 Жыл бұрын
Hello, I'm trying to figure out if i can use LPM if I have a binary outcome and a binary explanatory variable (my # obs is less than 5000). I'd be really thankful if you could help me please. Also, i'm thinking about recursive bivariate probit, but i don't know which one is more adequate
@jaradniemi
@jaradniemi Жыл бұрын
I wouldn't use a linear probability model (LPM) because you need to think carefully to ensure that probabilities stay between 0 and 1. I would use logistic regression (kzbin.info/www/bejne/rpC9hXZrrMuEftE) or a probit model instead. Recursive bivariate probit is a model you can use when you have two binary variables and you want there to be a relationship between these two binary variables. In recursive bivariate probit, you would also have additional explanatory variables. So which one you should use will depend on what variables you have and what your scientific goal is.
@lucianamicaelajaimecano4705
@lucianamicaelajaimecano4705 Жыл бұрын
@@jaradniemi Thank you! The main problem that arises when i want to do a simple probit is that my binary explanatory variable is endogenous. So in stata the code iv probit is just for endogenous continuous independent variables. The only code i could find for my situation is rbiprobit, but i only have one explanatory variable, so it would be wrong to use thar?
@TheShackhorn
@TheShackhorn Жыл бұрын
Thank you very much! This was very helpful :)
@manwhofumbles
@manwhofumbles Жыл бұрын
Great Vid!
@drstevemarson
@drstevemarson Жыл бұрын
I have been searching online and my few nonparametric textbooks but cannot find and answer. In the social science literature, we see a pattern of conflicting results. There are 101 articles that conclude one point, while 175 articles conclude the exact opposite. I have conceptualized 101 and 175 as n’s for two different distributions. The null hypothesis might be “there is no size difference between the n’s.” The n’s are frequencies of two opposite results. Do you know of any nonparametric statistic that can assess this null hypothesis? It sounds as if some kind of binomial test would be appropriate. I have done any statistics for about 30 years. Do you have any videos addressing this issue?
@养兔大户
@养兔大户 Жыл бұрын
nice video, thx!!!
@xinglinli9874
@xinglinli9874 Жыл бұрын
Saved your STAT 587 series, thanks for sharing.
@sanjaythorat
@sanjaythorat Жыл бұрын
I am a little confused about your explanation after 10:20. Could you please provide additional resources and pointers to understand this better?
@sanjaythorat
@sanjaythorat Жыл бұрын
At 03:52, could one more reason for incompatibility be that data could have a different variance (irrespective of constancy of the variance)?
@sanjaythorat
@sanjaythorat Жыл бұрын
Your second statement (08:15), doesn't mention the null hypothesis. Do you think mentioning null hypothesis as well would help communicate complete information?
@sanjaythorat
@sanjaythorat Жыл бұрын
Between 04:50 and 07:00, you mentioned multiple hypothesis tests which different values for the mean of the null hypothesis. (i.e. data sample is fixed and the null hypothesis is variable and probably that's why you are saying that this is the inverse of hypothesis tests.) 1. Are you suggesting using the exact same observed data sample for each of these hypothesis tests? If yes, it seems you are not explicitly expressing that (probably it's obvious for experts). 2. I am assuming that here you are trying to construct a confidence interval for the observed data sample. (I am still trying to get a good grasp of confidence intervals and your answer here will help me confirm my assumptions).
@sanjaythorat
@sanjaythorat Жыл бұрын
@Jarad Niemi At 07:20, in the expression for Tow-sided p-value, shouldn't the inequality be reversed?
@chrisorji1
@chrisorji1 Жыл бұрын
clutchh
@NIHILSTAY
@NIHILSTAY Жыл бұрын
Thank you for the video!! very helpful
@happylearning2982
@happylearning2982 Жыл бұрын
thanks
@catcen9631
@catcen9631 Жыл бұрын
very clearly explained! thank you!
@mohammadaasifkhaja1892
@mohammadaasifkhaja1892 Жыл бұрын
Sir any reference please
@jaradniemi
@jaradniemi Жыл бұрын
The Statistical Sleuth (3rd ed) section 10.2
@nicolenew1708
@nicolenew1708 Жыл бұрын
SUPER INCREDIBLE
@saleemabid3757
@saleemabid3757 Жыл бұрын
Good lecture on contrast
@nebrahimi3509
@nebrahimi3509 Жыл бұрын
How can figure out the expected value of Y_bar_{1..} for this model?
@yaqinguo8971
@yaqinguo8971 Жыл бұрын
Hi Dr. J before I do this analysis, do i need to test my data for normality and homogeneity?
@jaradniemi
@jaradniemi Жыл бұрын
Generally I am not a fan of tests. But yes, you should evaluate your data relative to all model assumptions including normality and constant variance of the errors. Typically I utilize graphical approaches based on residuals, i.e. estimated errors, as discussed in this video kzbin.info/www/bejne/oqbZnZx5ppuEq7M
@yaqinguo8971
@yaqinguo8971 Жыл бұрын
@@jaradniemi Thanks!
@yaqinguo8971
@yaqinguo8971 Жыл бұрын
Thanks a lot for these useful hints!
@TheRenekruse
@TheRenekruse 2 жыл бұрын
Ok It has been a day now, I wanted to give you that bit of time to respond to what I said before I presented you the truth. If the question is as original in Ask Marilyn, the question asked by Craig F. Whitaker's as follows "Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?" The correct answer is no as your odds are 33.3% and that does not change as the question does not have any mention of the host always opening a door after you picked one nor that you knew before hand that the host would do so, which means you also do not know the motives for the opening of the door nor the option to change your pick of doors and as such the opening or the door and the option to pick the other door does not change your odds at all. Here is where you and everyone else who has been taken in by the deception fails, you see, It is not the opening of the door by itself nor the option given to change your choice, it is the knowledge that you will always be shown a door that has a goat and then be asked if you want to pick the other door, that gives you the 66.6% odds. Without the knowledge your odds will always remain 33.3%. So in short if you want the answer to change the door to be correct you first do what Marilyn did when she was confronted by her mistake, which is misrepresent the question, lie about what the question was.
@farkler4785
@farkler4785 2 жыл бұрын
Yes, the fact that knowing he will always open a door with a goat is what makes switching better, are you claiming that the original problem did not include that knowledge? If so cite your sourve
@TheRenekruse
@TheRenekruse 2 жыл бұрын
​@@farkler4785 I literally cited the original source, almost at the very beginning. " If the question is as original in Ask Marilyn, the question asked by Craig F. Whitaker's as follows " So stop trying to deflect and admit your mistake.
@farkler4785
@farkler4785 2 жыл бұрын
@@TheRenekruse here is the original quote: “Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?” The key quote here where you’re getting confused is “the host, who knows what’s behind the doors, opens another door, say No. 3, which has a goat”. You’re getting confused by the use of a non-essential clause (the words between two commas, in this case “, say No. 3,”) which as the name suggests is non essential; the sentence doesn’t change meaning without it. Thereby, if we remove it we’re left with “the host, who knows what’s behind the doors, opens another door which has a goat”.
@TheRenekruse
@TheRenekruse 2 жыл бұрын
@@farkler4785 what the host knows does not give you better odds, you are the one who needs to know of the hosts pattern to get the better odds, nothing in the original question implies any such knowledge. You are the confused one, little arrogant one.
@farkler4785
@farkler4785 2 жыл бұрын
@@TheRenekruse if you know that the host will always open a door with a goat behind it then your odds are 66%, this is clearly stated in the original problem, “the host opens another door which has a goat”
@TheRenekruse
@TheRenekruse 2 жыл бұрын
I watched your video and like all the other videos I have watched today after I first heard of the "Monty hall problem" you are wrong. I am the most intelligent man I know to exist, I know you will find that arrogant and I am fine with you mistaking my confidence for arrogance. You will no doubt doubt that I am correct in you being wrong, but I know it to be a fact and I would not blame you for that mistake as I have become aware that most the world, that know of the "Monty hall problem" Seem to have fallen for this and don't seem to see the flaw in the claims they make.
@saifhasan4631
@saifhasan4631 2 жыл бұрын
great
@mojde9010
@mojde9010 2 жыл бұрын
The video is so informative and helps to understand the topic deeply