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@KeithBoehler
@KeithBoehler 14 күн бұрын
Love when good math videos end up in my recommendation feeds.
@rattyoman
@rattyoman 22 күн бұрын
actually sad that you stopped uploading since I only just found your channel and I think the content is extremely good, your way of speaking and animation style remind me of a channel called "Lines That Connect" and he uploads so infrequently but I love his content. the same is now true for you ;^^
@rattyoman
@rattyoman 22 күн бұрын
damn, 5 years and still a banger
@danieleaccardo2217
@danieleaccardo2217 Ай бұрын
Bel video
@frankdearr2772
@frankdearr2772 Ай бұрын
great 👍
@jorisdemuytere7400
@jorisdemuytere7400 Ай бұрын
Small error at timestamp 4:15. You correctly mention dv equals ethaprime times dx, however you write ethaprime without dx....
@sameerkiron
@sameerkiron 2 ай бұрын
could someone explain why S1= S2 at 1:07
@redpepper74
@redpepper74 4 ай бұрын
0:27 “This isn’t because the values don’t exist, but because they’re not real.” Hmmm okay mister
@elreturner1227
@elreturner1227 4 ай бұрын
This always seemed obvious logarithms are just roots for when x is the exponent instead of the base just like square root of -1 except a bit fancier
@РайанКупер-э4о
@РайанКупер-э4о 5 ай бұрын
Letting the log have multiple values doesn't break the math.
@Effect_channel
@Effect_channel 5 ай бұрын
0:38 this identity isnt actually eulers but still but the TRUE eulers identity is (sigma n=1 to ∞) (1/n²)=π²/6
@nothing29717
@nothing29717 5 ай бұрын
Thanks this was helpful
@liubo8147
@liubo8147 5 ай бұрын
The only question i think is the prime of j(e=0)=0 implies that the "principal of least action",which means the path will choose the stationary point of j (tangent line), so the prime of j(e=0) is equal to 0
@سلمانيوسف-ر5خ
@سلمانيوسف-ر5خ 7 ай бұрын
thanks.. that was amazing
@TheOriginalDeaf
@TheOriginalDeaf 11 ай бұрын
e^(I*pi) = -1 Ln both sides Pi*i = ln(-1) Pi = ln(-1)/i I proved that pi is rational in the complex plain, is this true or did I do a wrong step?
@Cyrenalux
@Cyrenalux 4 ай бұрын
π = ln(-1)/i π = iπ/i π = π 🤷
@mayabaalbaki6904
@mayabaalbaki6904 Жыл бұрын
This is the best explanation of variable calculus so far on the internet
@johnspivack6520
@johnspivack6520 Жыл бұрын
it would also be good to have more explanation of why there is a total derivative wrt x instead of a partial derivative
@johnspivack6520
@johnspivack6520 Жыл бұрын
a few mistakes in the integration by parts spoil this video unfortunately.
@vigneshbalaji21
@vigneshbalaji21 Жыл бұрын
What is the intuition behind hyperbolic trigonometric functions?
@sydneymakombe3726
@sydneymakombe3726 Жыл бұрын
you actually need to do a series of calculus of variation and optimal control theory. Thank you very much
@sarkarsubhadipofficial
@sarkarsubhadipofficial Жыл бұрын
😮
@josemartinho424
@josemartinho424 Жыл бұрын
😊very clear! Brilliant!
@otonanoC
@otonanoC Жыл бұрын
I waited and waited for the narrator to say that f(z)=ln(z) is literally the inverse function of f(z)= e^z . But he never got there.
@nicogehren6566
@nicogehren6566 2 жыл бұрын
very nice question
@ycombinator765
@ycombinator765 2 жыл бұрын
Loved it
@shivangmishra2642
@shivangmishra2642 2 жыл бұрын
Beautifully explained...
@user-mg6fb7ix1q
@user-mg6fb7ix1q 2 жыл бұрын
If the angle was measured from the top would it be R(cos(t)-1)?
@prediccionescountryballs893
@prediccionescountryballs893 2 жыл бұрын
6:43
@RoboMarchello
@RoboMarchello 2 жыл бұрын
Thanks💖
@mastershooter64
@mastershooter64 2 жыл бұрын
now optimize multivariable functions on manifolds
@るるん-n6n
@るるん-n6n 2 жыл бұрын
Awesome video! Note: The domain shown at the end isn't really standard, because you can't define a continuous version of Log on all of C. If you make both inequalities at 3:26 sharp, it will become holomorphic, which is much nicer in proofs and calculations.
@lambda2693
@lambda2693 2 жыл бұрын
thats is not a good enough proof. doing functional analysis you have to take into account for the domains and range, you have not put up condition. if you said f is continuous over all R then your statement would be considered true, but for example if the function blows up to infinite at the specified point and is obviously not continuous and differentiable then your proof would be wrong. All in all nice video but you took a pretty general case and did not specify the generality
@markgoretsky766
@markgoretsky766 2 жыл бұрын
Excellent job, Xander! Thank you
@va9if
@va9if 2 жыл бұрын
u run so fast that I can't keep it up but awesome!
@pratyaksh1729
@pratyaksh1729 2 жыл бұрын
Actually your result is wrong. Logarithm of a negative value is a multivalued function. That means it can have multiple values. For example: 3i*pi is also a solution.
@1495978707
@1495978707 4 ай бұрын
He specifically addresses this if you keep watching...
@mathematicalmuscleman
@mathematicalmuscleman 2 жыл бұрын
So this is how Pure Mathematicians developed the construct of a Complex Logarithm Mapping. Maybe this is the process that Euler used.
@navilistener
@navilistener 2 жыл бұрын
Thank you for this video, it provides a clear derivation of the Euler-Lagrange Equation. However, to be rigorous, at 4:18 du should be equal to d/dx (∂F/∂ȳ') dx = (∂F/∂ȳ')' dx and not equal to d/dx (∂F/∂ȳ'). What I mean is that du is not the derivative of u, but is instead the differential of u, which, by definition, is given by du = u'(x) dx = (du/dx)dx. Similarly, dv should be η' dx and not η'. Despite these innacuracies in the screen at 4:18, we can see that u, v and du are substituded correctly in the next screen at 4:31, so the proof of the Euler-Lagrange Equation is not compromised. en.wikipedia.org/wiki/Differential_of_a_function#Definition I also have a suggestion regarding the presentation. I think you should add some visual queues in the screens where only expressions appear when reading out loud the contents of the expressions, so that the narrator's voice is followed in the image as well while possibily inserting additional information. For example, in the screen at 4:31, it would help a lot to add some colored brackets below each part of the expression stating each element of the integration by parts formula (u, v and du) and make them appear in the screen as you are reading the formula. Apart from these details, great work with this video! I hope you continue doing more videos :)
@highereducation8382
@highereducation8382 2 жыл бұрын
Amazing👍👍👍👍👍
@JDC2890
@JDC2890 2 жыл бұрын
(1 + 2n)Pi*i, where n is an integer?
@menot5039
@menot5039 2 жыл бұрын
that's what i was looking for
@jasonbroadway8027
@jasonbroadway8027 2 жыл бұрын
Going nowhere? If y is a curve, does J then just depend on x? Confusion
@jasonbroadway8027
@jasonbroadway8027 2 жыл бұрын
When you say "nowhere", you mean that f does not go up or down? I can work some of the problems in Mary Boas' book, but I found this lecture to be heavy-going.
@armando-rpg
@armando-rpg 2 жыл бұрын
This channel's gonna blow in 3,2,1...
@REEMAN_
@REEMAN_ 2 жыл бұрын
U R amazing!
@lamaiyad9596
@lamaiyad9596 2 жыл бұрын
شكراً جزيلاً 🤍
@anwarh.joarder8644
@anwarh.joarder8644 2 жыл бұрын
Kindly speak allowed and in a slow paced way for non- natives.
@hansstephani5869
@hansstephani5869 2 жыл бұрын
Cool Video!
@georgesadler7830
@georgesadler7830 2 жыл бұрын
Thank you for a fantastic derivation of Hyperbolic Functions.
@bruzote
@bruzote 3 жыл бұрын
What is the intended audience for this? Is it people trying to watch a mathematical equivalence between a starting equation and final equation? Certainly, the pace combined with the formulas suggests it does not matter WHY this is done. Just as Einstein earned a Nobel Prize with a three-page paper but my 80-page thesis was not worth printing except to get me an advanced degree, I perceive this video as testament that someone likes to talk a lot. WHAT is the goal of the video? What IDEAS guide you to the goal? I don't see the latter question being answered. Rather, I see someone showing how mathematical equivalence works during manipulation of equations. Call me disappointed - by almost every Lagrange video that I am finding.
@turkserisi1979
@turkserisi1979 3 жыл бұрын
find the optimum of J=int[x'^2(t)-2tx(t)]dt please