1/0≠∞, and the correct expression is lim(x→0)1/x=∞. This means that when x approaches 0 as much as possible, the "limit" becomes infinite: ∞. Since "0×∞≠1", even though "0×(anything)=0" is written in front of it, it makes no sense to ignore "0×∞=0" and force the calculation.
@Noname1650. Жыл бұрын
At last , when you are putting x=0 then, √2x+1 +1 = x √2(0)+1 +1 = 0 √1 + 1 = 0 At this moment, the value of √1 is ±1 (as we know) so, here , in order to balance the equation the value of √1 is taken as -1 -1 + 1 = 0 0=0
@Moodycandraw Жыл бұрын
0× 1/0 = undefined B'coz we can't allow division with 0 If we do the all algorithm of maths get collapse
@Itz_Booyah Жыл бұрын
Both are same i.e Infinity ×0+infinity ×0=2(infinity ×0)
@Moodycandraw Жыл бұрын
We can't say 0 × infinity = 1 B'coz tendency of 0 to make the solution tends to 0 ... And tendency of infinity to make the solution tends to infinity ... So it's an 0× infinity form we can't say the exact value or answer if any equation is in 0× infinity form we can solve it by limits
@Wiqq122 Жыл бұрын
When you want to prove your maths teacher youre right: