1.3 Array Operations | Deletion from Array | Explanation with Code | Data Structure

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[@amanprajapati3417]

After seeing your last video I am able to apply deletion operation by myself Thank u mam🤗🔥

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[@nibinaugustin]

Correction in program. In the if else part the for loop condition should be. for(i=0;i

[@AnuragRawat01]

Broo it's not right Just make a dry run then you'll understand

[@justcurious1940]

@@AnuragRawat01 last element is not omitted because : a[i] = a[i+1] ----> a[i+1] is the last element .

[@joji9666]

​​@@justcurious1940 but the statement written in the loop is wrong know if i=position -1;i

[@justcurious1940]

@@joji9666 It's correct, last element is at i+1, the loop will go until the size - 2 so if i = size - 2 then i + 1 = size -1 which is the last element.

[@justcurious1940]

Thanks, so clear and easy to follow here is a version of the code using dynamic memory allocation : void delete(int *array, int *size,int pos){ for(int i = pos-1 ; i < *size-1 ; i++){ array[i] = array[i+1]; } --(*size); array = realloc(array,*size); } int main (int argc , char *argv[]) { int size ; printf("Enter the size of the array : "); scanf("%d",&size); int *array = malloc(sizeof(int)*size); printf("Enter the elements of the array : "); for(int i = 0 ; i < size ; i++){ scanf("%d",&array[i]); } int pos; printf("Enter the position of the element that u want to delete : "); scanf("%d",&pos); delete(array,&size,pos); for(int i = 0 ; i < size ; i++) printf("%d\t",array[i]); free(array); return 0 ; }

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[@vgk-lm8vl]

first thanku so much mam for this series And My code logic is: int a[30],pos,size; printf("enter the size of the array "); scanf("%d",&size); printf("Enter the element of array "); for(int i=0;i

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[@naveenar5158]

Mam ...in the previous video u took size as 5 so that the index is 4...now in for loop u took size as 4( which is the index.)..if we take size as 5...then the for loop condition will change as size-2..is that so?

[@thekhanfishing]

if(pos size - 1) but you wrote if(pos size ) beacause we are dealing with indexes not position or size so we can delete from zeroth location and cannot delete from 5th location which you wrote size.it should be size - 1 &

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[@anitsharma9950]

but how we will move value of last element of array

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[@mampisarkar1]

Very good explanation

[@CodeFlects]

At 09:35 a[3] is only assigned the value of a[4] .I might be wrong on this but is it true that a[4] still contains that value? 5

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Jenny, please do videos on some leetCode problem solving. Please explain Median of two sorted arrays

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[@JennyslecturesCSIT]

Bcoz of my busy schedule, I am not getting so much time nowadays.. but will try to upload it asap.. :)

[@adreesmughaladreesmughal3876]

Ok mam thanks..... mam 1 more thing .... heap sort me heapify tou ho jata hai but deletion me problem hota hai...plz agr ap bta skein tou...boht acha hoga..plz mam

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Had mam completed the topics of asymptotic notations, best case and worst case and time complexity??

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one video on how to find time complexity pls mam

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Mam u have forgotten to declare " i " variable at the start. But ur lectures are so understandable, thank you....

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in the for loop when i=pos the code is properly run... thank you ma'am...

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[@srijanajain7716]

great explanation ma'am but in the for(i= pos-1 ; i< size -1 ; i++) here the condition should be ( i < size ) as the code will automatically go uptill size -1 because we haven't added (

[@bigk2367]

If the size is 5 then loop will go until 4 but we don't want to go till 4, we just have to go till 3 and that's why we should write size-1 in for loop.

[@CodeFlects]

You're wrong on this unfortunate because we want to traverse till 2nd last index.and if size is 5 last index is 4 and 2nd last index is 3 so (3

[@anju7334]

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[@sunilverma-ry8yn]

Why you have taken increment of (i) on 8:19? It should be decrement?

[@thebeast_]

mam in this we didnt deleted the data from the last position , we just shifted and then only printing out size - - array. How can we actually vacant that memory ? edited: just put arr[size-1]={ }; this will put a space and an array cant have space so system will put no value and you dont neeed to decrease the size of the array

[@sm-op9zg]

Waahh...!! Thnx..

[@gayatripatidar9136]

but still in place of a[size-1] ele are present that mean 0 (zero) are there and array does not free the memory so their is also no mean to initialize zero to last index

[@anju7334]

Had mam completed the topics of asymptotic notations, best case and worst case and time complexity??

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