🔷11 - Gauss Jordan Elimination and Reduced Row Echelon Form

🔷11 - Gauss Jordan Elimination and Reduced Row Echelon Form
In todays video we are going to solve system of linear equations using gauss Jordan elimination and reduced row echelon.
To solve a system of equation, you represent the set of equations in a form of argumented matrix thus [A | b]
1. The elements in the leading diagonal should be 1
2. All elements should be 0
3. If a row is made up of all zeros, it should be placed at the buttom of the matrix.
After obtaining the reduced row echelon form of the matrix, the unknown variables easily found.
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[@clintonnavicha3465]

This is great and straight forward...keep up the good work brother...

[@SkanCityAcademy_SirJohn]

Thank you so much Clinton

[@siphosethundzo2650]

Sad part is that these things u work with are easy to understand but the activities I get at school are way to hard I try to do everything I just won’t get the answer but I’ll get there

[@SkanCityAcademy_SirJohn]

Yes please gradually.

[@siphosethundzo2650]

@@SkanCityAcademy_SirJohn can you help me with this one please bro 3x + 7y=21 2x + 2y + z=24 X + 3y=9

[@aS023_a]

Thanks it's so helpful 🙏 Keep it up bro

[@SkanCityAcademy_SirJohn]

Most welcome

[@ayo2975]

Please sir how do I know when to use row echelon form and reduced row echelon form?

[@SkanCityAcademy_SirJohn]

Row echelon form = Gaussian Elimination Reduced Row echelon form= Gauss Jordan

[@ayo2975]

@@SkanCityAcademy_SirJohnThank you sir

[@meserettesfaye1433]

3x+2y-z=5 x-y+3z=-15 2x+y+7z=-28 how calculate both rule please

[@PedroSiliezar-tv9qw]

You are the best!

[@SkanCityAcademy_SirJohn]

Thanks so much

[@lawrindaobokwaah7624]

Does it mean that i can use different approach to arrive at the same answer ? Like the adding and subtraction

[@SkanCityAcademy_SirJohn]

Yes, only if you are doing the right thing

[@AbibaChipura-uo9hu]

God bless you

[@SkanCityAcademy_SirJohn]

Thanks so much Abiba

[@andrewooi3648]

hello may i ask, is the final answer for x y and z is fixed?? i did manage to get all 0 and 1 in the respective slot but my answer for x y and z from your question is different

[@SkanCityAcademy_SirJohn]

Yes please, the values of x, y and z are fixed values. You might have missed something somewhere. Recheck okay... Good luck friend.

[@andrewooi3648]

@@SkanCityAcademy_SirJohn in the video 4:34, for R3= R1 -2 (R3), can i use R3= 2(R3) - R1 ???

[@SkanCityAcademy_SirJohn]

yes, you can@@andrewooi3648

[@andrewooi3648]

thank you, i will ask any question if needed @@SkanCityAcademy_SirJohn

[@SkanCityAcademy_SirJohn]

@andrewooi3648 ok

[@mensahbenjaminrabby3303]

❤

[@Akuao_]

I have a problem with a question I’m working on. Is there a way I could reach out to you?

[@SkanCityAcademy_SirJohn]

On this same Gaussian Elimination ?

[@Akuao_]

Yes

[@SkanCityAcademy_SirJohn]

@@Akuao_ kindly join my telegram group for engineers on my page, and message me directly (group) owner.

[@kamalbhatta9559]

❤❤

[@SkanCityAcademy_SirJohn]

Thanks so much for the much love

[@GillAgainsIsland12]

Just one careless mistake ruins the whole salad.

[@SkanCityAcademy_SirJohn]

Of course 😂

[@Akuao_]

Is there a specific order to eliminate?

[@SkanCityAcademy_SirJohn]

As in? Can you explain further?

[@Akuao_]

How do you know which one to eliminate first . I don’t know if this helps

[@SkanCityAcademy_SirJohn]

@@Akuao_ so the key thing is to make the entries below the leading diagonals go to zero. 1. Perform the operation on row 2, using R1 and R2 2. Do same for row 3, using R1 and R3. 3. Then lastly you perform the operation on row 3 using row 2 and 3

[@SkanCityAcademy_SirJohn]

I hope you are cool with this?

[@okoyengozi6696]

I taught you always use r1 and r2, and r1 and r3 instead of r2 anf r3

[@SkanCityAcademy_SirJohn]

You can use r2 and r3 for the 2nd forward elimination step

[@Maths103]

Meaning always when solving( 2:35 ) all the systems of linear equations using gaus jordan I always multiply the third row by 3 or how and where do I get the number that I multiply with?? Please sir help me🥺

[@Maths103]

This is on how I get my first zero on the second row now, I’m confused on where and how the number to multiply the 3rd row is got Which number from the system do I use to multiply with 🤷‍♀️🤷‍♀️🤷‍♀️

[@SkanCityAcademy_SirJohn]

@Greatness Well, it depends on the question. But these steps could help. so the key thing is to make the entries below the leading diagonals go to zero. 1. Perform the operation on row 2, using R1 and R2 2. Do same for row 3, using R1 and R3. 3. Then lastly you perform the operation on row 3 using row 2 and 3

[@SkanCityAcademy_SirJohn]

Where do you school?

[@Maths103]

@@SkanCityAcademy_SirJohn I’m a university scholar

[@Maths103]

@@SkanCityAcademy_SirJohn I’m lost? To performing the operations on row two, I got so confused when I was trying to solve this other question and I’m not getting a zero after using a second row operation Like how you stated

[@Akuao_]

Thank you for this video

[@SkanCityAcademy_SirJohn]

Thanks so much. May I know where you are watching me from?

[@Akuao_]

I’m in Florida, USA right now

[@SkanCityAcademy_SirJohn]

Wow that's great, and are you a Ghanaian 🇬🇭 or an American?

[@Akuao_]

@@SkanCityAcademy_SirJohn I’m both Ghanaian and American

[@SkanCityAcademy_SirJohn]

Oh okay. Nice

[@MarvellousOmamujevwe]

❤

[@meserettesfaye1433]

3x+2y-z=5 x-y+3z=-15 2x+y+7z=-28 how calculate both rule please

[@SkanCityAcademy_SirJohn]

Chat me here: telegram [phone]