13.6 Ring Opening of Epoxides | Organic Chemistry

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[@ChadsPrep]

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[@rajikarobinson122]

Thank you so much! This was the best lecture on ring opening of epoxides that I've ever seen.

[@ChadsPrep]

You're welcome, Rajika Robinso - glad it helped!

[@amalgregory4375]

Thank you so much! I've been scratching my head for an hour with two different textbooks but this sorted it all out clearly. Ur amazing!

[@ChadsPrep]

Glad you found the channel and the video so helpful, Amal Gregory - Happy Studying!

[@emiliolarrazabal5360]

This is the best breakdown of epoxide reactions online

[@ChadsPrep]

Glad to hear it, Emilio!

[@DallinPlatt]

Idk what it is about these videos but they make so much sense

[@ChadsPrep]

Glad they do!

[@Vinayak_Nair]

You explained this concept so well! Thank you.

[@ChadsPrep]

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[@gabrielsu7205]

great stuff as always

[@ChadsPrep]

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[@ccoppola11]

this was so helpful! great video

[@ChadsPrep]

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This is the video that made me subscribe

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[@target__iit]

Absolutely worth it 👍

[@ChadsPrep]

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[@ADPL-tn5ix]

Amazing lecture sir, thank you

[@ChadsPrep]

You're welcome and Thank You.

[@suyashdave9642]

I LOVE THIS GUY MAN

[@ChadsPrep]

Thanks!

[@kanchanmotwani4305]

Thank you-this helped me so much!

[@ChadsPrep]

You're welcome, Kanchan. Thank you for the feedback.

[@isakfisher8233]

Could you give an example of where Acids are more reactive to primary Carbons in an epoxide than secondary Carbons? Thanks!

[@marleyrae8779]

Love you!

[@ChadsPrep]

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[@borzoo]

thank you very much for great lecture

[@ChadsPrep]

You're welcome.

[@yeaitsjustme8928]

the OCH3 that is now dashed, since it is inverted, does that mean it is going away or coming toward you? i cannot tell where the point of the dash is headed. Thank you.

[@rickyl7442]

I have a question, so idk if this is just a professor preference thing but for acid catalyzed ring opening my professor has the CH3OH on the top and then HCl (cat) on the bottom. So I was wondering of the placement of this means anything at all or if it doesn’t matter. Because your way makes a lot more sense.

[@ChadsPrep]

Do you mean above/below the arrow? There is no set rule, but the reagent tends to be written above the arrow and anything else, solvent etc below.

[@WomannequinReviews]

What would happen with the methyl group during the ring opening if it was neither dashed nor wedged from the start? Would it remain unchanged at the end of the reaction or would it become dashed or wedged?

[@thedarkknight1865]

Thanks 😃💖 you're best 😎👍

[@ChadsPrep]

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[@laavanyarajan4444]

The best, thank you sir...

[@ChadsPrep]

You're welcome!

[@eseegs]

Why would the positively charged pronated epoxide not first lose the bond to the carbon to become neutral and causing a full carbocation on the tertiary carbon. Then the weak nucleophiel could attack either side like a typical SN1 reaction. Why does this not happen?

[@ChadsPrep]

Hey there, I mention a few times in the video that it can occur in an SN1 type reaction, where the O-C bond on the more substituted side will be longer and weaker than the other side (as if the ring were starting to open in that way before the nucleophile attacks) leaving a more positive tertiary carbon.

[@isaacotto3202]

Thanks alot sir!

[@ChadsPrep]

Very welcome.

[@stephennguni1145]

Great video keep up

[@ChadsPrep]

Thanks, Stephen!

[@rf9674]

YOU ARE AMAZING WOW

[@ChadsPrep]

THANKS!

[@zcarinareimuyargas5793]

hi! what happen to the H2SO4 number 2 example?

[@matthewclaveria8348]

It was just used to protonate the alcohol (CH3-OH)

[@verisa19]

I’ve a doubt, what happend with H2SO4?

[@matthewclaveria8348]

H2SO4 was just used to protonate the alcohol (CH3-OH), I assume it can also activate the epoxide without having to protonate the alcohol first but both scenario works.

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[@ChadsPrep]

Welcome back and Happy Studying!

[@laura5878]

My exam is coming up, can I rub your head for good luck?

[@ChadsPrep]

If you mean by rubbing my head that you watch every video 3 times, then GO FOR IT! 🙂