14.5 Integrated Rate Laws | General Chemistry

[@peybak]

Hey Chad, this kinetics series has been BOSS! Specially when you showed how to derive the rate law a few days ago. That was really helpful. So thank you!

[@ChadsPrep]

Glad it was helpful, Peyman!

[@jbmu4644]

I wanted to stop by and say thank you for your brilliant explanation. You were clear, concise, and straight to the point. Keep up the great work!

[@ChadsPrep]

Thank you - appreciate all the feedback!

[@UniqueUsername01]

Thank you so much for making these videos! I can not tell you how confused I was about this section and watching your video really cleared things up and clicked ideas into place. I look forward to watching the rest of the series. Again thank you, thank you, THANK YOU!!!!

[@ChadsPrep]

That is great to hear - You are welcome and Thank you.

[@pranaya7405]

You are the best chemistry teacher i have ever watched. The way you slowly and orderly explain things is very helpful.

[@ChadsPrep]

Thank you!

[@sarahdada1284]

I just discovered your channel right before the gen chem 2 final, and I feel like I am finally understanding the content! Please make ochem videos, these will be a lifesaver next semester!!!

[@ChadsPrep]

Glad you found us. You should check out my playlists...already have ochem videos! Happy Studying!

[@lynne6973]

I undated easily than @organic chemistry tutor 😂i really like the way chad teaches

[@ChadsPrep]

Glad to hear it!

[@bryannabustamante7440]

Thank you for these videos and making them easy to understand !! I have my midterm exam and I was so lost before watching your series haha. God bless you

[@ChadsPrep]

You're welcome - glad the channel is helping you and hope you excel on your midterm!

[@zahraaa59676]

This video was extremely helpful! Thank you for the amazing effort and making things easier!

[@ChadsPrep]

You're very welcome!

[@deepakreddy813]

First things, these vedios require a lot more attention. And also thank you so much for making this so easy by your explanation. Huge respect

[@ChadsPrep]

You're welcome and Thank You - glad you found us.

[@skylardean4540]

Your videos, as always, have greatly helped me understand the concepts at hand. Thank you.

[@ChadsPrep]

Excellent - thanks for saying so!

[@michellemwasumbi6534]

I cannot thank you enough for all of your content! It has been incredibly helpful for my semester!

[@ChadsPrep]

Excellent!

[@amy6810]

Thank you Lord for Chad!! 🙌🏼

[@ChadsPrep]

Thanks for saying so!

[@thokgamopelontle4584]

Thank you for the information Sir

[@ChadsPrep]

You are welcome!

[@lovelyasefri8220]

I like your teaching so much…yo are the best teacher in the world

[@ChadsPrep]

Glad to hear it - Thanks for saying so!

[@jesusamadorflores2242]

Yooo what a chad!!! I really appreciate your from of teaching!

[@ChadsPrep]

Glad the channel is helping you.

[@BlessingKunda-o8o]

This is brilliant thank you very for this wonderful explanation

[@ChadsPrep]

You're very welcome!

[@tia6279]

watching this right after the superbowl for a test and hearing him at 4:25 is hilarious

[@ChadsPrep]

Hope you do well on your test!

[@MollyTownsend-un8ep]

thank you so much for this

[@ChadsPrep]

Very welcome

[@MatthEgede]

Thanks so much....I am really getting some facts that were confusing

[@ChadsPrep]

Glad the channel is helping you - Happy Studying!

[@adelaidejoilugnasin989]

Hi, i'm just a little confused on how you get the constant rate k=0.001 reply ASAP 3:10

[@retrosapien1]

i think its given in the question

[@LisaKaplan-g3z]

This guy is the goat

[@ChadsPrep]

Happy Studying!

[@zahraaa59676]

In our lecture, the teacher represented 0.693 as ln(2). That is a much easier way to remember it!

[@ChadsPrep]

Excellent!

[@pitrader4208]

anyone get a diff value for integration problem on second order?

[@buffylloyd1860]

Gréât explanation!

[@ChadsPrep]

Thank you!

[@jeffersondavis6618]

Hey Chad, thanks for the Clarity provided on these different orders of reaction. But I'm somehow confused on deriving ln e-

[@Octopus-moose]

you are amazing 😊

[@ChadsPrep]

Thanks!

[@achiriu1987]

How did you get 0.44 for the zero order?

[@rohan7722]

Thank you so much

[@ChadsPrep]

You're welcome.

[@Obamnaz]

Thanks so much !

[@ChadsPrep]

You're welcome!

[@lethabomolesh2604]

Hy can you share the link for the video where you do derivations

[@alexkirby4502]

kzbin.info/www/bejne/j3nVqpesZth9mbc

[@valv1377]

I don't understand how he went from .753 to .47M. I don't know how to find the e^ on the calculator.

[@valv1377]

I figured it out I was leaving off the negative!

[@em9420]

@@valv1377 but how did you use the e i cant find it either

[@modesterchaga7655]

Practical of chemical kinetics

[@CloudslnMyCoffee]

I swear chemistry isn't science, its just math

[@ChadsPrep]

You could see it that way