14.5b Derivation of the Integrated Rate Laws | General Chemistry

[@andreandes7485]

I suck at memorizing math. I like to prove what I’m doing. Which can Be a pain when doing general chemistry so thank you so much for this video

[@ChadsPrep]

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[@parsabehnia1281]

nice to see proof search process for formulas in Gen-Chem, a very rare thing to see :) thanks for the clearance

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[@zahraaa59676]

This made everything so easy. Thank you so much! There’s another part which I wished to see, second order with two reactants instead of one. That part is very difficult right now, and I wished to see it in this video.

[@ChadsPrep]

Glad you found it helpful. I'll keep that in mind for a future video.

[@nicoscool2333]

Yay I’m in calculus and so chem I can do this now I don’t have to remember the integrated rate laws

[@ChadsPrep]

Excellent!

[@jakyrabailey7940]

You are saving my chem grade rn.thank you!!

[@ChadsPrep]

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[@user-yl5nc6ct6l]

4:58 1/[A] integrates into ln[A], but why did you ignore the dA doesn’t that integrate into A ?

[@Sphynxx9]

It been a few years since I took calculus but I believe it just notation. You’re probably used to seeing dx which means the derivative with respect to x. In this case it’s the derivative with respect to A.

[@Crystalfieldtheory]

Great explanation!

[@ChadsPrep]

Thank you!

[@Chemcrown]

keep it up sir

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You bet!

[@aditibhatnagar2984]

Rate law for second order =-1/2× dA/dt and rate=k[A]^2

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You're my academic guardian angel 😇

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😇😇😇

[@ÇağatayDönmez-k4g]

You are a great man!

[@ChadsPrep]

Thank you - Happy Studying!

[@OnkarPawar00]

Had this derivation in our chem textbook

[@childofgod5818]

ty!

[@ChadsPrep]

yw!

[@MayaWaller]

bless you sir

[@ChadsPrep]

Thank you.

[@tobymoy84]

Thank youu

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[@evaalao1613]

Fight the good fight of faith bro 😉☺️

[@ChadsPrep]

Indeed!

[@aditibhatnagar2984]

Derivation for second order is wrong....check the rate law

[@RyanRibeiro-te3ns]

No, sir. It's correct. Finishing the integration you get to the equation of second order. Or maybe I just did not understand what part you said that it was wrong

[@peterlohnes1]

I think what you're focusing on are the negatives, but because everything becomes negative, you simply multiply both sides by negative one, and you get the integrated rate law. His one mistake was not finishing the 2nd order example to completion to show how that happens.