18 ELECTROCHEMISTRY | OVERVOLTAGE CONCEPT | IIT ADVANCED | JEE MAIN | CHEMISTRY CLASS 12 | OLYMPIAD

[@BTMECJeetBhakta]

I am in 1st year, in NiT Nagpur still watching these lecture for midsems, awsm, pardlo juniors aage v kaam ayenge

[@malanevrekar7234]

Glad to know that! Will you please tell us your branch? Best wishes for your engineering journey, academic life and for the plethora of opportunities waiting for you ahead!

[@aravjee8982]

@@malanevrekar7234 mech eng

[@GauravG91]

I am a 1st Year student of IIST and watching this to understand the topic for the corrosion science course. Thank you sir !

[@ai_videos_for_you]

That's gazab

[@surabhi-n4l]

How can I join iist?

[@User-ex7hu]

​@@surabhi-n4l you'll have to get a good rank in JEE Adv and by good I mean under 1000 at least. All the very best!

[@bhumika2026]

​​@@User-ex7hu for iist,even under 10k will work,1k is too much.

[@IITIAN_IAS_Sahil_Kushwaha]

Veryyy veryyy nice teacher.... THANK you sir... Thank you...

[@nupur8804]

In this channel only serious students come and that's the reason of 0 dislike 🙂🙂

[@samarthkikkeri169]

but did i ask

[@AdityaSingh-ox7ni]

@@samarthkikkeri169

[@dhruvgohil2842]

youtube removed dislikes lol

[@ishaankumar4587]

​@@dhruvgohil2842watch the comment date

[@fatimazahra-sq9wy]

tysm sir👍 doubt crystal cleared🙏❤

[@pranavrana7890]

#askcompetishun is there reduction of h+ on cathode or reduction of h2o as h20 -h+ +oh- ???????

[@IITIAN_IAS_Sahil_Kushwaha]

Good explanation sir thank youu!! 💚💚💚💚

[@avinashkashyapjha2247]

Amazing lecture sir.

[@sakshampaliwal8170]

Why is it kinetically slow process please tell!!!

[@m_.bsrikanth]

Study chemical kinetics

[@vaishnavimulik3558]

Intermediate formed in the process is less stable but product formed is stable as formation of intermediate is rds of reaction thus rate is slow (according to organic chemistry logic)

[@sakethsreeni]

Thank you sir

[@SunkeriMeghanasai]

why not standard reduction potential of water = - standard oxidation potential of water

[@sakshisahu2465]

Very nice and useful lecture. Concept crystal clear. Thanxxx sir

[@iitjeeaspirantpadhaku8871]

16:24 / 24:32

[@poojapatil9834]

Great lecture 😊

[@pradeepkumarparikirala6595]

Excellent 👍

[@chanderboss975]

Sir awesome lecture

[@vishupandey-pv2dt]

At 8.33 how sir directly can write Ecell because in 2nd equation there is oxidation potential given but we find reduction potential of Ecell always

[@Its_Ari24]

i too have this doubt

[@virid69]

​@@Its_Ari24Ik I am late but E cell me srp and sop can be directly added. You can find reduction potential first the answer would come out to be same. Hope it helps.

[@ai_videos_for_you]

How to identify kinetically hindered process?

[@samarthkikkeri169]

impossible

[@niteshshrivas69]

Ye experiment fact hote h rxn dekh ke sapne me nhi aate

[@balua6781]

Thanks 😊

[@TonyStark-rq7ub]

sir in previous lecture you have given that SOP of Cl>H2O confusing sir at 3:20

[@lonamisa6128]

Nhi..kab diya tha..last class me jo order diya tha wo discharge potential based tha.. discharged potential may or may not be equal to SOP.

[@samarthkikkeri169]

what he means to say is that the concept of discharge potential is applied only when the differentiating factor is the ion itself and not the solvent molecules brother

[@niteshshrivas69]

Agar tumhara doubt clear hua ho toh mujhe samjha do

[@AbhyudaySingh-pj5xg]

ig wo last lecture waale ease of oxidation waale sequence me Overvoltage ko consider karke hii H2O

[@onlystudyjee787]

Yumm 😋

[@MohitSharma-ic8bn]

Jai Shree Shyam

[@Warlord_Megatron]

#askCompetishun Sir why overvoltage is applied? Like we know that oxidation of chlorine is favoured kinetically so it takes place. If we increase the voltage upto the voltage required for the oxidation of H2O which is clearly higher than the oxidation potential of Cl2, why would H2O get oxidised? The voltage required for oxidation of H2O is higher than the voltage required for oxidation of Cl2 so Cl2 will get oxidised nonetheless. So what's the point of overvoltage if Cl2 is getting favoured in getting oxidised with and without overvoltage?

[@samarthkikkeri169]

sorry not possible

[@andeccan]

As given in the video, overvoltage is applied in order to liberate a sufficient amount of O² gas. Well, your point can be considered but, due to overvoltage, oxidation of H²O turns out to be favourable too. Thereafter, H²O now, is, kinetically and as well as thermodynamically oxidizable greatly.

[@MohitSharma-ic8bn]

Guru Ji

[@alphaiitd1]

Thanks sir

[@Agentp_nitbhopal]

20:00

[@tanmaybhardwaj4244]

wow tasty🙃😉😋😛

[@praveenk2636]

❤ tusi dil leta ji sir 😂

[@aayush2948]

1:20

[@amarkumarlive]

Too much information 🙃

[@Sketchydude22]

But sir, Ecell= Ered- E ox .... aapne add kyu kiya

[@onlystudyjee787]

Ecell= Ered- Eoxd only

[@shreshthayaduka2672]

Ecell = Ered + Eoxd = Ered(reduction half cell) - Ered(oxidation half cell) i would suggest going through some of the earlier videos again especially the one dealing with thermodynamics related topics for a complete understanding. In essence, E is an intrinsic property. Algebraic operations can only be applied on extensive properties like ΔG. Let the ΔG of the oxd half cell be ΔG1 and that of redn half cell be ΔG2 and that of the net cell be ΔG. ΔG = ΔG1 + ΔG2 But we know that ΔG = nFEcell, Similarly, ΔG1 = nFEoxd and ΔG2 = nFEred Therefore, nFEcell = nFEoxd + nFEred The rfore, Ecell = Eoxd + Ered HENCE PROVED

[@Warlord_Megatron]

We know that Ecell = Ered(cathode) - Ered(anode). We also know that Ered = -EOxd So, Ered(anode) can be replaced by -Eoxd(anode). -> Ecell= [Ered (cathode) -(-Eoxd(anode)] Which gives us Ecell = Exod(anode) + Ered(cathode) SOP means standard oxidation potential so don't get confused by SOP and Eoxd. They're the same thing. SOP is oxidation potential calculated on standard conditions.

[@Warlord_Megatron]

But why overvoltage is applied? Like we know that oxidation of chlorine is favoured kinetically so it takes place. If we increase the voltage upto the voltage required for the oxidation of H2O which is clearly higher than the oxidation potential of Cl2, why would H2O get oxidised? The voltage required for oxidation of H2O is higher than the voltage required for oxidation of Cl2 so Cl2 will get oxidised nonetheless. So what's the point of overvoltage if Cl2 is getting favoured in getting oxidised with and without overvoltage?

[@anamikasrivastava7845]

​@@shreshthayaduka2672e cell = e rp + e op if e op is given -0.5 then we consider erp +0.5 as eop = -erp I think sir has written wrong both are erp values ig

[@arnavkumarhatai1741]

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[@ABCDE-sg8uy]

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[@sanikasuryawanshi4463]

Thank you sir

[@vaishnavimulik3558]

Thank you sir

[@samarthkikkeri169]

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[@amitsingh2782]

Thank you sir

[@muskansharda4327]

Thank you sir

[@real_asad1797]

Thank you sir