1K Helmholtz theorem

[@ismailhasan348]

The way he explains these crazy concepts is ingenious.

[@Ben-tf2go]

next video: kzbin.info/www/bejne/qKK9aYWeoM5jabc entire video series can be found here (about 1/3 down): kzbin.info/door/4jkPyBaPWE2Mj9xGUKkpdQvideos

[@khaledchennouf4176]

why does the channel has just a few vues for every video ??

[@ponderingprachiti]

thankyou very much!

[@LandELopez]

This is so helpful. Thank you so much!

[@AndrewKiethBoggs]

Fantastic lecture, thank you.

[@leenajohnson4533]

Where is next video..??

[@peppino2671]

is there any chance to know about the deduction or proofs about HZ theorem?

[@juliboom5692]

dope

[@murillogregorio1533]

Excuse me, professor. The expression you put up on the board at around 4:50 is not necessarily correct for any given field. How does this affect the theorem itself? I mean, the only counter-example I know is a field in a non-simply connected region, but the question is still up.

[@jasondonev7038]

Non-simply connected regions aren't within the set of fields that we're talking about in this series (we're focusing on fields that are useful for E&M, but the statements are broader than that). I don't know much about fields that aren't simply connected, so I can't meaningfully speak to them. I'm uncertain if they vanish at infinity in the way that's necessary for Hemholtz's theorem to hold.

[@murillogregorio1533]

Yeah, I stopped to think a little about it, but didn't came to any concrete conclusion. The only example of field in non-simply connected region is that of F(x,y) = -y \hat{x} / (x²+y²) + x \hat{y} / (x²+y²). See that it does vanish at infinity, but the singularity at the origin makes it not-conservative in general, although its rotational is indeed zero.

[@mingjianlu4191]

How do you manage to write in reverse order if you stand behind the window? XD

[@pankaj8745]

Sir how grad(V+c) = grad(V) leads to charge conservation

[@jasondonev7038]

That's another video...

[@adhit528]

I quit!