#23 C Pointers | C Programming For Beginners

[@programizstudios]

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[@AbhiramDeshpande-fe1vi]

#include int main() { // Write C code here double salary = 25000; double* ptr=&salary; printf("adress:%p ",ptr); printf(" value :%.2lf",*ptr*2); return 0; }

[@anommaharjan3005]

I never really understood what pointer was, but my doubts and confusions were cleared out by this video. Thank you team Programiz for the wonderful and well-explained video.

[@3dohd]

Same - For some reason seeing the memory location printed on screen made a light bulb go off for me

[@tshedzanembilwi4572]

Thank you team Programiz I understand so much now that I’m going through these tutorials

[@anonymouszn4978]

Answer : Option C (*p = a)

[@zindycangaming9851]

Correcto!

[@kharlopena7512]

This is most cohesive explanation of pointers I've seen online. Thank you!

[@nihatdonmzov4166]

The programming task: #include int main(){ double salary; printf("Enter the salary: "); scanf("%lf", &salary); double* var = &salary; printf("%.1lf", *var); *var = 2 * *var; printf(" The new salary is %lf", *var); }

[@gamerxx6344]

it should be double* var = salary; and *var =2*var;

[@yashjewdhun7689]

@@gamerxx6344 no

[@kaseemkhan3919]

This C programming playlist is helping me so much to learn all this concepts in very easy and adaptive manner ! Thank you programiz for this

[@shuvadeepsil2513]

I was totally confused while learning pointers in C. Other KZbin videos on this topic were not easy and comprehensive enough for me to understand. After watching this video all of my doubts regarding pointers were cleared. Thank You Programiz!!! ❤

[@user-nt4nm4fb3u]

Hats off for this wonderful explanation on the topic Pointers which I so badly wanted to know how it works. Thank you

[@chinenyeumeaku9262]

#include int main() { double salary = 25.60; double* ptr = &salary; printf("Salary is : %.2lf", *ptr); double Newsalary = *ptr * 2; printf(" New salary = %.2lf", Newsalary); return 0; }

[@tibish]

Why make a Newsalary variable? The scope is to change the initial value through the pointer.

[@zeadalkssas9698]

thank you so much, i was unable to understand my baugette eating teacher explaining this. THANK YOU, YOU SAVED MY LIFE.

[@rainfeel_]

#include int main(void) { double salary; printf("Enter salary : "); scanf("%.2lf", &salary); double* p = &salary; *p = 35; printf("Your salary is changed to %.2lf", salary); return 0; }

[@rajiv_khanal]

Nice explanation didi. Balla clearly bujey. Thank you

[@freehug071]

#include int main(void) { double salary = 250.45; double* ptr = &salary; printf("the salary is %.2lf", *ptr); double newsalary = *ptr * 2; printf(" %.2lf", newsalary); return 0; }

[@anuskasthapit7285]

Very informative. Best tutorial for beginners! Waiting for more videos!!👍

[@sanketnimbrayan1948]

Hlo anuska where are you from?

[@tibish]

#include int main() { double salary = 5000.00; double* s_pointer = &salary; *s_pointer *= 2; printf("%.2f", salary); return 0; }

[@yourgray303]

the ans is #include int main(void) { double salary; double* pointer = &salary; scanf("%lf", pointer); //DONT* cuse scanf puts value INTO &salary(memory address of salary), but POINTER IS ALR ADDRESS OF IT printf("%lf", salary); }

[@Danyal-vt8dp]

so pure mam.... A lot of Respect For u

[@Aspire-ml4nr]

#include int main () { double salary = 2000; printf("Address: %p ", &salary); double* ptr = &salary; printf("Value: %.2lf ", *ptr); *ptr *= 2; printf("Salary: %.2lf ", salary); return 0; }

[@armandofilho7759]

Is so much better thx !!!

[@BigSmoke-r9w]

Great explanation! You have a new subscriber! Thank you!!

[@i-n_ph]

thanks, this is helpful 😊

[@shrur3527]

Tq so much 🙏🙏❤️❤️ Very well explained 🙏🙏❤️❤️

[@PedroLopes-k5f]

#include int main (){ double salary = 1000.23; double* ptr = &salary; *ptr = salary; printf("Salary = %lf", *ptr); salary = salary * 2; printf(" Salary doubled = %lf", *ptr); return 0; }

[@davidbraide6647]

I need to route this to memory

[@countrysideshowyaigrock4689]

#include int main() { double salary; double* pointer; printf("Enter your salary: "); scanf("%lf", &salary); pointer = &salary; printf("%.1lf", *pointer); *pointer = 2 * *pointer; printf(" %.1lf", *pointer); return 0; }

[@bbek300]

#include int main() { double salary; scanf("%lf",&salary); double* ptr = &salary; printf("Salary:%.2lf ",*ptr); *ptr = *ptr * 2 ; printf("New salary:%.2lf",*ptr); return 0; }

[@kisilujustus]

You are doing a good work

[@juliusjnr_]

Great explanation!

[@jordanholmes1366]

#include int main(/*the answer is C*/){ double salary; printf("enter your salary: "); scanf("%lf", &salary); double* ptr = &salary; printf("%.2lf ", *ptr); *ptr *= 2; printf("your new salary is %.2lf", *ptr); }

[@mohammadrezajavadi3498]

Excellent Explanattion

[@neeteshmaharjan4429]

#include #include int main() { double salary ; printf("enter salary: "); scanf("%lf",&salary); double* ptr= &salary; printf("your salary:%lf ",*ptr); double newsalary =*ptr*2; printf("your double salary:%lf", newsalary); return 0; }

[@programizstudios]

Q. Which of the following is valid for variable a and pointer p? A. *p = &a B. p = a C. *p = a D. p = *a

[@renuga.k7473]

D

[@Portagas.D.Ace75]

I belive it's option D , where p is the variable and *a is the address to that variable(my guess)

[@davidkecskes2573]

I think C... Because we open the location, what is stored in the pointer "p" and overwrite or upload the value with the value of variable "a".

[@s.karthikeyan2747]

A is right

[@hardikbindal740]

It's C because '*' Indicates the value of p which is equal to the value of a

[@perf5656]

really good stuff!!!

[@linbz2784]

its helping me a lot

[@MHJ-93]

Nice and simple introductory tutorial to pointers.👍

[@Ech-chatouiMohammed]

merci beaucoup

[@shireldadon-l2t]

#include int main(void) { double salary; printf("please enter salary "); scanf("%lf", &salary); double* ptr = &salary; printf("value of salary is %.2lf ", *ptr); *ptr = 2 * *ptr; printf("new salary is %.2lf", *ptr); return 0; }

[@bennyhuang2014]

Learning this before my final rahh

[@behailus-tube5024]

programming task #include int main() { double salary = 77.5; printf("%p ", &salary); double* ptr = &salary; printf("value: %f ", *ptr); *ptr = 155; printf(" %f", salary); return 0; }

[@lawrenceanekwe9318]

Lovely video.

[@CarolMccann-xg9zi]

Thank you!

[@sushilgbp]

thank u so much it really healful .tqs alot.

[@alameensaleem4158]

nice video

[@orochimaru1253]

your app is really good with that style of interface and layout 👍

[@light-warrior]

TASK: #include int main() { double salary; printf("Enter your monthly salary: "); scanf(" %lf", &salary); double* ptr = &salary; //assigning the adress of salary to the double pointer *ptr = salary; //assigning the value of the salary to the value stored in the pointer printf(" Your salary before change: % lf", *ptr); *ptr = 2 * salary; printf(" Your new salary after the salary increase: %lf", *ptr); return 0; } C is the correct option because *p shows us the value stored in pointer and a is also showing us the value of the variable.

[@johnnytherabbit291]

Very clear !! Thanks

[@JeongWoonKim-i4j]

#include int main() { double salary; double* ptr; printf("Enter the salary: "); scanf("%lf", &salary); ptr = &salary; printf("Last salary: %.2lf ", *ptr); *ptr = *ptr * 2; printf("New salary: %.2lf", *ptr); return 0;

[@sandeepyadav3766]

c is right.

[@mohammadrezajavadi3498]

Thank you

[@sahibaansari4450]

Thanks u so much mam , your way of explanation was awesome 👌 and i just learned pointer very easily

[@kalu-kelechi-kalu]

Crystal clear

[@jaysanga5981]

Answer is only c bcz *p=&a ; means dereference of p is cant store address , p=*a its wrong and *p =a; means it store value in address of what a had so address remain same but it change value in that address

[@Manikanta-wz2rl]

#include int main() { double sal; double* ptr = &sal; printf("enter the salary:"); scanf("%lf",&sal); printf("salary:%.2lf",*ptr); double sal1 = sal * 2; printf(" Double_Salary:%.2lf",sal1); return 0; }

[@allthingsmoney7089]

Very helpful. Thank you.

[@b7sh_b7sh]

amazing teacher😍😍

[@NantongoLindah]

I am in need of help abt the exercise given

[@prajwal_bagewadi]

very awesome video very very enlightening ❤❤❤❤❤❤❤❤🙏

[@interneter]

Great !

[@Jarawain_Kharpran]

Thnx

[@Ech-chatouiMohammed]

c'est très utile

[@zawnaing344]

thanks

[@thiagaodavez5465]

tankis madam

[@annapopova3221]

perfect

[@sushilgbp]

thank u

[@endeavored]

/* Program to change value of a variable using pointer. Instructions: Get input value for a double variable named salary, Assign the address of salary to a double pointer. Use pointer to print value of salary, increase salary by 2 times and print new salary. */ #include int main() { double salary; printf("Enter Salary: "); scanf("%lf", &salary); double* ptr = &salary; printf("Salary = %.1lf ", *ptr); *ptr = salary * 2; printf("Salary doubled = %.1lf", *ptr); return 0; }

[@more_harsh]

seems correct to me atleast

[@nsfw_metaMorph21]

Could have given salary in the last printf() as the value is already changed

[@karamking6404]

thanks for your explanation but what is the best way to learn c programming?

[@t3bld846]

practice leetcode daily bro

[@AFCOE]

Practice

[@godswillnnachionu]

Great

[@ssentamualvinjacob1191]

hey would really hope to see a code to calculate CGPA

[@livehopeskul1157]

Option C

[@sejalbansal486]

there will be no error coming by using *ptr instead of * ptr, she write %d that why the value came instead of address

[@qarikhalidwaheed1643]

Yeah, you're correct

[@daireosullivan1193]

#include int main() { double salary; printf("Enter your yearly salary: "); scanf("%lf", &salary); double *ptr = &salary; printf("Salary = %.2lf", *ptr); *ptr = 2 * salary; printf(" New salary = %.2lf", *ptr); return 0; }

[@morex288]

love this

[@poornachandraj2417]

c is option

[@dankorwack8598]

Ur so brown

[@andreiacampos7111]

Your soft's cool btw

[@kareemtawfik2886]

double salary; double*psalary=&salary; scanf("%lf",&salary); printf("%.1lf ",*psalary); printf("%.1lf ",*psalary*2);

[@V1ctorinos]

double salary = 39.500; double* ptr; ptr = &salary; printf("The salary is %.3lf ", *ptr); salary = 50.000; printf("The new salary is %.3lf", *ptr);

[@DCSDilshadAhmad]

Option (c) is correct.

[@rajumalekar]

Thank you for the app

[@vishalkirthik9148]

#include int main(){ float a; printf("Enter the salary"); scanf("%f",&a); float* ptr=&a; printf(" The value of salary is %f",*ptr); *ptr=*ptr*2; printf(" The value of salary is %f",*ptr); return 0; }

[@bryanborigas380]

nice

[@lzii9127]

c is the correct answer i guess

[@imveryscawed]

I didn't know there is a app, that's good for mw

[@deepakkushwahaji3109]

English में तो सब study करवाते है हिंदी में भी करवा दीजिये,, हम हिंदी मीडियम लोग भी programing करना चाहते है

[@akshaybagalkotkar7833]

Tumse na ho payega, tum bhais charao.

[@lemichael2004]

#include int main (){ double *pointer ,salary,newSalary ; printf ("Enter your salary: "); scanf ("%lf",&salary); pointer = &salary; printf ("Value of salary =%.2lf",*pointer); newSalary = salary*2; pointer =&newSalary; printf (" Value of new Salary =%.2lf ",*pointer); return 0; } Answer of the quiz : C because *p is value , a is value so --> value =value . Thank you so much for your free lesson

[@hammadraza9018]

I end up over stimulating myself

[@vishnupriya8910]

Option: c

[@erl2nd]

Great instructions

[@innocentibeto7733]

the correct option is C

[@054vijayakumark4]

❤️❤️❤️❤️❤️

[@jaredwynnepadron3000]

#include int main() { double salary; printf("Enter salary: "); scanf("%lf", &salary); double* ptr = &salary; printf("Your salary is: %lf", *ptr); *ptr *= 2; printf(" New salary: %lf", *ptr); return 0; }

[@codeforcoder1]

10:45 (C) *p = a

[@dankorwack8598]

Chats up

[@thaaranisivakkumar7967]

Option c

[@abdirahmaanabdirashiid]

#include #include int main () { double salary= 350.57; double* ptr=&salary; *ptr=salary*2; printf("NEW SALARY: %.2lf",salary); return 0; }

[@madhusmitamahapatra5181]

Option C is d right answer

[@Clog17]

#include int main() { double salary; double* ptr; double new_salary; double* newsal; printf ("Please enter your salary: "); scanf("%lf", &salary); ptr = &salary; printf("%lf ", *ptr); newsal = &new_salary; new_salary = (salary)*2; printf("%lf", *newsal); return 0; }

[@ayeshaali6462]

I didnt understand the dufference int* ptr and int *ptr? int age=24; int* ptr=&age; printf("%p",&age); printf(" %p",ptr); printf(" value%d",*ptr); //24 int *ptr1=&age; printf(" value1 %d",*ptr1); //24 return 0; it gives same result above for both syntax

[@abdulmateenalabi6063]

int* ptr = &age; ----- is the correct way to do it as int* is making ptr a pointer. While int *ptr = &age ------ is wrong for pointing to the address because *ptr is to access the value of a variable and not address. With what you did you assigned a value variable to an address which is wrong, but since you used a value variable you will get a value instead of an address and from your last code if you try accessing your address you will not get the address.

[@ananducs5622]

@@abdulmateenalabi6063 will get address

[@tibish]

there is no difference from the compile's stand point. both will be seen in the same way. From a code clarity perspective there is a big difference. For example, if you see this line: int* ptr1, ptr2, you would tend to think that both are pointers, but you would be wrong as only ptr1 is a pointer, ptr2 is just a simple int. On the other hand if you see this line: int *ptr1, *ptr2 it is immediately clear that both ptr are pointers.

[@Azizam-j3c]

//Solution. #include int main() { double salary; printf("enter the salary: "); scanf("%lf", &salary); double* salptr = &salary; printf("the value of the salary pointer is: %0.2lf ", *salptr); *salptr*=2; printf("the new value is: %0.2lf ", *salptr); }

[@formodapk]

use dark mode 😭😭😭

[@NantongoLindah]

8:13 8:15 8:32

[@yogithabale]

opt 3