3.1 Break and Continue statement in C++ Programming | Guaranteed Placement Course | Lecture 3.1

Apni Kaksha: / apnikaksha
Link to the notes and questions of this video: drive.google.c...

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Can anyone explain why in program at 7:52 , in second for loop the value of i start with i=2 rather than 0. Why cant we start it with zero? Someone please explain the concept.

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I can't understand how she is using "terminal" at last to get the result. Can anyone please help me ??

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Best way to learn any language would be actually programming on it and refer official doc of the lang if you have any issue regarding syntax of something. Also refer stackoverflow for any complicated error. Try to dive deep, underneath how it works internally, and why not it worked. Try to understand how it's compiler is working《just have a high overview》 . By only watching video you will run at the risk of forgetting it quickly.

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@@khurshidjahan9102 Even though docs are the best place to learn , they are a bit hard to understand as a beginner , so for beginners , a good video is the best place to learn . And after you get a bit familier wiht the language , you can do mini projects in it (doing mini projects involves a lot of doc searching) . And at that point , they will know what they are dealing with .

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Lol I am 12th pass and I only watch this video and do questions on my own from internet and notes question ....... I think you should watch first and try out yourself without watching any code. (I can make " hello guys " program in 36 seconds starting from blank page) Start writing codes brother..... Hope it help u ..... God bless you 🧡❤️💛💚💙💜🤎 Edit:- I can also do till loops in loops

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Sir aap aur mam bohot accha padha rahe ho aapke example kya bolu main sir maine aapke diye hue har ek porblems ko PDF main diye hue Build and run kiya hain. Aur kuch codes ko yaha pe mile knowledge se maine aapke diye hue codes ko thodasa modify bhi kiya aur woh perfectly run bhi huye. Mujhe kcuh interest nahi tha coding main lekin ab maja aa raha hain aapke vids ke sath. So much thank you sir.

[@darkshader9885]

This will work better for find prime or non prime number : #include using namespace std; int main() { int n,i; cin>>n; for(int i=2;i

[@sagarkumar138]

thanks bro I was troubled from last half an hour as prime nos were not getting printed coz inside else if i was using i==n I don't know how her code run😑

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i think mine is also right in calculating prime numbers from a to b ----------->>>> #include using namespace std; int main(){ int a, b; cin>>a>>b; for(int num=a; num

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6:35 I tried if/else statement and it worked. If/else was easy for this

[@thundersparky2559]

exactly.... thats what i was checking in the comment section too

[@sahaj-ps]

Didi in prime number you used i

[@scientificvin6197]

But by that way,answer doesn't come

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@@scientificvin6197 give supporting test case and try to dry run you will get the idea 👍👍

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good idea bro!!. thanks for a better suggestion.

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6:53 after putting i=55,565,575,584945 It gives both prime and non prime numbers

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Ok

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You don't have to iterate till n-1 for finding prime number . sqrt (n) tak hi iteration is enough !

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what?

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Videomark: break statement for nested loop - 7:17

[@ahmedghaffar5116]

5:10 here it is just checking whether it is even or not but not checking that odd is even or not if we put 21 it will give prime where it is not...

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me to But love learning C++ from sir.

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Thank you apna college, apki waja se aaj mujhe prime or non-prime ke bich ka difference samajh aya hai... 👍❤️

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Prime number different method Int n; cin>>n; for( int i =2; i

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At 06:32 How will i reach i==n when we have the max i value as i < n ( which means i must stop at n-1)

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In the Continue Break program for Neha"s trip, instead of if(pocketmoney==0 ) we can write if(pocketmoney

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when i was equal to n i think the loop didnt even run becuase of the condition i

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in my visual studio if i click run button it forever shows running but when i do it in terminal it works g like g++ prime.cpp ./a.exe

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for the prime wala question, we can directly put an else in the loop and break it na? int main(){ int n; cin>>n; for(int i=2;i

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Your efforts are really appreciating. But i would like to add something in your first code. The condition should be if(pocketMoney

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yeah you are right actually...I deducted 500 in my own code so didnt run into this problem (Always ended up with 0 exact) but Pmoney

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waiting for data structure and alog ♥

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[@mrinalsharma18]

Can we loop upto n/2 for checking prime rather than n-1 ?. Certainly it reduces the time complexity.

[@amardeepyadav9511]

It fails for the number such as 9 and 25 which are not prime but the code will show that it is a prime number I also thought that but later when I tested for such numbers I got my mistake

[@mrinalsharma18]

And can you explain why it will give me wrong answer for 9 and 25 ? If the iteration is from 2 to n/2 ?

[@amardeepyadav9511]

@@mrinalsharma18 bro i ki value 2 ke bad stop ho jayegi uske baad 3 ke liye check hi nhi hogi

[@mrinalsharma18]

Kyu nhi hogi. N=9 N/2 would be 4.5 i.e 4 And iteration would go from 2 to 3 as condition is less than n. For 2 it will not break and for 3 it will break

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Wow what a grt explanation

[@zakimurudkar7025]

Idk how but my last program is not working.

[@themihirmathurofficial]

When you explained the difference between continue and break, there is written iternation instead of iteration

[@seemagupta5914]

I am unable to understand the logic of (I ==n) in question of find a prime number

[@ralsei7170]

Look, there are two ways the loop will terminate, either by the break statement or when it completes entirely. So if the loop has terminated through the break statement, our initialised number will be smaller than the number we are checking the condition through. Hence we will know that current number is not prime. Else if loop has terminated after completing all it's iterations counter that is i will be equal to the final number which means we didn't encounter break statement and thus it means number is prime.

[@SumitShankhwarr]

@@ralsei7170 how i = n to final number when loop will run only till n-1

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@@SumitShankhwarr loop runs until the final number

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Unity

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I need Your Help

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She doesn't use any spaces to make code cleaner and that thing is killing me from inside

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Maam the way you use to check the prime no. In that way 1 will also be shown as prime which is not correct So, we can declare sum=0 and check divisibility from 1 to n and if remainder became zero we can write sum=sum+1 and if sum=2 then we can say that no. is a prime no. I known it is a bit lengthy but in this case we may eliminate any error Please correct me if I am wrong By the way thanks for this amazing course for beginners like me🙏

[@gaddamudayasri6189]

Dono sahi hai bhai

[@thattechieguy]

aman bhaiya ek improvement ka point ! 2:49 par continue ke neeche likhe hue statement me "iternation" ki jagah "iteration" hoga

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