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AVERAGE MOLAR MASS | MOLE CONCEPT |Physical Chemistry By ALK Sir | IIT JEE Main and Advanced #admission_online_offline_batch_7410900901 #Competishun
This is Lecture 3 of Mole concept which covers average molar mass and relevant Jee Problems The detailed explanation of the lecture with timestamp-:
00:00 - 02:02 Average atomic mass /Average atomic mass -17Cl35 (75%) and 17Cl37(25%) So average molecular weight of chlorine M avg=35.5g/mol.
02:03-06:12 Isotopes are atoms of same element with same atomic number but different mass number. For e g :1H1,1H2,1H3 and C12 , C 14.Formula for average atomic mass Mav=(Total mass of all the atoms in the sample)/(Total number of atoms ) or (Total mass in g)/(Total number of moles) in g/mol
06:13 - 08:16 Calculation of average atomic mass when % by mol abundance of isotopes is given E g A+B is given Let A is x% and B is (100-x)% by mol or by number M avg=x*M-A+ (100-x)*M-B/100 M avg=x1M1+x2M2+x3M3.... /100
08:17 - 12:17 Note: In a mixture % by mol of a component need not to be same as % by mass of that component .E g A+B A-x% and B-(1000-x)% by mol % by mass of A=% by mol of A*M-A/M avg
12:18 - 14:12 Dry air (O2+N2) O2 is 20% and N2 is 80% by mol: (i) M avg = (20*32+80*28)/100 =28.8 g/mol (ii) % by mass of O2=20*32 /28.8=22.22%
14:13 - 19:50 Explain which is denser : Dry air or moist air under same pressure & temperature conditions'=n R T , PV=W/M*R*T : PM=W/V*R*T PM= density of gas *RT .At same pressure and temperature density of gas is directly proportional to average mass .If CO2 is introduced in place of H2O then density will increase.
19:51 - 23:39 When molar ratio of isotopes is given A+B in the ratio m:n molar ratio , then M avg =(m*M A+ n*MB)/(m+ n).M avg=Total mass/total moles and for a closed system ,Total mass is constant M avg is inversely proportional to total moles. There will be a rectangular hyperbola between M avg and total number of moles
23:40 - 25:04 A vessel contain equal mass of H2,He & CH4.Find M avg Solution :Let masses of H2,He and CH4 are W then number of moles will be W/2,W/4 and W/16 mol then M avg=(W+W+W)/(W/2+W/4+W/16)
25:05- 26:31 A vessel has 1 mol of O2 and 3 mol of SO3.Find M avg M avg=(1*32 + 3*80)/4 = 32+240/4 = 272/4 g/mol
This is the 3rd lecture in the mole concept chapter for class 11 Physical chemistry .It is very important for JEE Mains and Advanced .This lecture covers all the concepts of average atomic mass ,isotopes and relevant examples. This lecture is important for science students who are preparing for IIT JEE Mains and Advanced .This lecture has cleared all the basics of calculation of atomic masses
AVERAGE MOLAR MASS,
MOLE CONCEPT,
AVERAGE MOLAR MASS
ALK Sir,
MOLE CONCEPT ALK Sir,
Chemistry By ALK Sir,
IIT JEE Main and Advanced,