A Challenging Exponential Equation | Can You Solve This?

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My Math Tutor

My Math Tutor

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@DougDougGoose9
@DougDougGoose9 5 күн бұрын
This is incorrect. By exponent rules, a^m^n =a^mn. Your answer works because you changed the base from 2 to 3 (random coincidence for this problem). The problem can be simplified to 2^12x = 2^9. x=3/4 or .75. Check with a calculator.
@slother93
@slother93 6 күн бұрын
x = log4(log3(log2(512)))
@supeskrim
@supeskrim 5 күн бұрын
2^10 = kibi = 1024, 2^20 = mibi = 1024 * 1024, 2^30 = gibi. So 512 = kibi/2 = 2^9.
@gspaulsson
@gspaulsson 5 күн бұрын
512=2^9. 3^4=81. 2^81^x=2^9, 81^x=9. 81=9^2 so 9^2x=9. sqrt(9^2x)=+/-9^x=sqrt(9)= +/-3. x=1/2.
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