A Golden Exponential Equation

[@The_Commandblock]

The title gives it away 😂

[@kevinmadden1645]

Very much so .

[@GreenMeansGOF]

8:42 In general, would we not have y^2 = y+1+2πni? I believe all solutions are of the form e^((1+r)/2) where r is a square root of 5+8πni. If n=1, one solution is approximately -0.4+11.7i but that doesn’t seem to match the picture at the end.🤔

[@marzipanhoplite17]

Congratulations,both methods are equally fine.By the wayyou are doing very well by symbolizing natural logarithm with ln and not log

[@scottleung9587]

I used the first method.

[@barakathaider6333]

👍

[@Nothingx303]

6:00 it's a golden ratio isn't??

[@Cray_Science]

It is

[@giuseppemalaguti435]

lnx=(1+√5)/2….lnx=(1-√5)/2

[@Tommy-tx4dx]

I cannot seem to find my error in this approach: x^lnx = e × x ln(ln(x)²) = ln(e×x) ln(ln(x)²) = ln(e) + ln(x) ln(ln(x)²) = 1 + ln(x) e^ln(x)² = e^1+ln(x) e^ln(x)² = e × e^ln(x) e^ln(x) = e x = e