A great exponential equation - 3^x=x^9👍

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mathsmood

mathsmood

Ай бұрын

A great challenge. Math Olympiad Question
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Пікірлер: 4
@Arysto-Krzysztof
@Arysto-Krzysztof Ай бұрын
Based on the graphs there is second solution x≈1.151. Function x^1/x is not monotonous so you can't just say that it has to be 27. Additionally equation 3^x=x^9 has different domain than your last equation. You can't just raise everything to the power of 1/x without assuming that x is positive, so you have to check what happens when x is negative or 0.
@abendyman
@abendyman Ай бұрын
But how did you know to put it to the power of ⅓ and 3. It solves it but i dont see where youre getting those numbers without already knowing the solution?
@sofisofi-gx8te
@sofisofi-gx8te Ай бұрын
he was probably just testing ideas before getting to the solution
@abendyman
@abendyman Ай бұрын
@sofisofi-gx8te if its a trial and improvement you require the trial and improvement to be shown to show how you solved it. And how is anyone supposed to know that
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