A Harvard Entrance Exam question| Can you pass this exam| algebra

A Harvard Entrance Exam question. Step-by-step guide on how to solve this type of algebra question . #harvard #algebra #entranceexam

[@francisamewode233]

Very interesting lectures. Thank you for the lectures my beautiful tutor

[@JJONLINEMATHSCLASSchannel]

Rhanks

[@devonwilson5776]

Greetings. Thanks always for sharing. I think you made a mistake in the end by disregarding the divisor 2 in the last two solutions. You wrote X=3+i(15^1/2) and X=3-i(15^1/2), instead of X=[3+i(15^1/2)]/2 and X=[3-i(15^1/2)]/2. Your solution method was quite simple. However, that approach would require knowledge of cubic identities and the difference of two squares. I am knowledgeable about those identities but frankly speaking didn't recognize the fact that they could have been utilized to solve the problem and had already solved the problem by dividing X^3-X^2+12 by X+2 to get X^2-3X+6 for (X+2)(x^2-3x+6)=0 and (X+2)=0 and X^2-3X+6=0. When X+2=0, X=-2 and when X^2-3X+6=0, X=(-3)^2 plus or minus the square root of (-3)^2 minus 4 times (1)(6) all divided 2(1) to get X = [3 +(9-24)^1/2]/2 and [3-(9-24)^1/2]/2 for [3+i(15)^1/2]/2 and [3-i(15)^1/2]/2. Blessings.

[@kenitra.west.6389]

Merci madame.

[@pas6295]

Method Equation is X^2-X^3=12. By Solving you get X^2(1-X)=12.If X is -2. We have the equation as(-2)^2(1-(-2). You get 4×3=12.

[@RyanLewis-Johnson-wq6xs]

X^2-X^3=12 X=-2 X=1.5±0.5Sqrt[15]i=(3±Sqrt[15]i)/2

[@rogeraak7281]

You forgot to divide the complex answers by two.

[@عبدالواسع-س8م]

Thank you so much!

[@JJONLINEMATHSCLASSchannel]

You're welcome!

[@pas6295]

X is Minus2

[@pas6295]

X=-2