A Level Physics: Electricity: Mock Exam

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Burrows Physics

Burrows Physics

Күн бұрын

Пікірлер: 52
@Aleeza-r2p
@Aleeza-r2p 10 ай бұрын
This was genuinely so helpful, thankyou so much because I can never seem to find good exam questions on youtube.
@pingu8394
@pingu8394 2 жыл бұрын
Sir I love your videos!!! Thank you so much for the concise and organised explanations/model answers!!!
@bigg.grizzlybear2670
@bigg.grizzlybear2670 10 ай бұрын
1:41, Why did you use the parallel formula for the two 30 ohms resistors? Are they in parallel the two 30 ohm resistors?
@burrowsphysics
@burrowsphysics 9 ай бұрын
Yes there are 2 parallel routes taking you from X to Y. One with a resistance of 60 (30+30) and the other with a resistance of 40 (20 + 20), hence the use of the parallel formula
@kevinio
@kevinio Жыл бұрын
11:45 in the final step shouldn’t it be 3x 230^2??
@burrowsphysics
@burrowsphysics Жыл бұрын
Yes I believe you are correct! Thanks for flagging!
@Ultimatevid26
@Ultimatevid26 11 ай бұрын
In the question at 17:42 can not solve it with the E.M.F = V+Ir formula, because when I try to solve it the r comes 0 ohms?
@medinecharyyeva9313
@medinecharyyeva9313 4 жыл бұрын
in 15:09 what would happen to the reading on the voltmeter if the resistance in the variable resistor was not fixed??
@rorymoynihan9517
@rorymoynihan9517 2 жыл бұрын
It would change, making the resistance fixed allows us to revive a single answer if it wasn’t, we wouldn’t be able to get an answer as there is no value of resistance we can use
@takdirsaiful628
@takdirsaiful628 9 ай бұрын
Hi is dis for ocr a?
@burrowsphysics
@burrowsphysics 9 ай бұрын
pretty sure this is for AQA A but the electricity questions are pretty much the same in both
@qaliila
@qaliila Жыл бұрын
for qn 3 i calculated 1/120+1/500 and i didnt got 96.77 i got a different answer, i got 31/300 which is 0.0103 in decimals. what do i do wrong how did you got 96.77 ohms.
@burrowsphysics
@burrowsphysics Жыл бұрын
Did you remember to take the reciprocal once you'd added them together? Remember 1/R total = 1 / R1 + 1 / R2... + ....
@gamingwithhbgalaxylife4224
@gamingwithhbgalaxylife4224 5 жыл бұрын
On question 11 shouldn’t it be R= 3*230squared/10500 ?
@lewiswinkless
@lewiswinkless 4 жыл бұрын
Yes it should be but his answer is still right so he just put in the wrong number
@someone3706
@someone3706 4 жыл бұрын
Yes, you are right
@shoesharx7810
@shoesharx7810 2 жыл бұрын
Hi. Whilst you've stated in the comments that these are AQA past questions I do not recall ever seeing questions involving mean drift velocity (as seen in Q12). Can you clarify this please? Many thanks
@burrowsphysics
@burrowsphysics 2 жыл бұрын
If you see the publish date, it was from 2018. Highly possible that AQA have now removed this from their specification. I haven't taught AQA for a few years so I wouldn't know if they have or not! It is a useful concept to know about even if it isn't in the specification though
@megata6184
@megata6184 2 жыл бұрын
Why do you not add the percentage uncertainties together for question 3, that's what we've been told when multiplying and divide numbers,
@burrowsphysics
@burrowsphysics 2 жыл бұрын
But they aren't being multiplied or divided here. When we have resistors in parallel we add their reciprocals and then reciprocal the answer. The approach here used the fact that percentage uncertainty means that the value could be 10% higher or 10% lower. I simply figured out how much bigger than the calculated value the total resistance COULD be and found it to be about 9% different
@megata6184
@megata6184 2 жыл бұрын
@@burrowsphysics thank you very much
@megata6184
@megata6184 2 жыл бұрын
@@burrowsphysics I had the idea that since we’re having to take the reciprocal we’re basically dividing but that’s not really the case
@Nahum242
@Nahum242 2 жыл бұрын
isnt the anwser to question 8 D and not B
@burrowsphysics
@burrowsphysics 2 жыл бұрын
No you need the thermistor to have very high resistance and the LDR to have low resistance to maximise the voltmeter reading which is why D is wrong
@qaliila
@qaliila Жыл бұрын
why did you multiplied 1/120 and 1/500 with 1.1. And what does 1/R max means
@burrowsphysics
@burrowsphysics Жыл бұрын
Multiplying by 1.1 calculates the resistance if each of the resistors were 10% larger than the stated value. Using those 10% higher values calculate the largest possible combined resistance hence why Rmax is used
@LiviBea
@LiviBea 2 жыл бұрын
rock on dude
@r3ma1n36
@r3ma1n36 Жыл бұрын
Thank you so much !!
@AC-pz3lz
@AC-pz3lz 2 жыл бұрын
Can someone explain the equation used in question 8?
@burrowsphysics
@burrowsphysics 2 жыл бұрын
That's just the potential divider equation that you can use to calculate the potential difference across one of the resistors in series
@gamingwithhbgalaxylife4224
@gamingwithhbgalaxylife4224 5 жыл бұрын
I don’t understand how you got 0.8 for the percentage question 9 .
@lewiswinkless
@lewiswinkless 4 жыл бұрын
0.4%+0.4% because you are doing 0.5mx0.5m
@syds9558
@syds9558 5 жыл бұрын
im lost on question 8 tbh
@ferdousreza6907
@ferdousreza6907 4 жыл бұрын
loool truss where does ldr's come in
@primsiren1360
@primsiren1360 3 жыл бұрын
For 6 wouldn't it be A because the three resistors gives the highest resistance, and the question is asking which one dissipates (i.e wastes) the most?
@burrowsphysics
@burrowsphysics 3 жыл бұрын
High resistance doesn't mean you waste the most energy. You have to calculate the power dissipated by a resistor to do that which is proportional to current squared
@umaniperera9408
@umaniperera9408 6 жыл бұрын
COULD U HELP ME WITH THIS QUESTION PLEASE a cabel consists of 10 strands of copper wire each of cross-section area 1.1x10^-3 cm^2. Calculate (a) the resistance per meter of the cable (b) the minimum number of strands which would be required if the resistance per meter is not to exceed 0.010ohms. (resistivity of copper = 1.8 x 10^-8 ohm meter.)
@ohheho3895
@ohheho3895 4 жыл бұрын
@Yung PouriiP rude
@nawfaljafri
@nawfaljafri 2 жыл бұрын
good questions but you it woulve been better if you explained some of the concepts along the way too
@burrowsphysics
@burrowsphysics 2 жыл бұрын
Potentially but typically an exam comes after having explained concepts in class and I felt going into more detail would have simply made the video too long!
@jacobonline6994
@jacobonline6994 4 жыл бұрын
question 11 is wrong, you're meant to do 3*230^2/10500 not 2*230^2/10500
@lewiswinkless
@lewiswinkless 4 жыл бұрын
His answer is right he just put a 2 instead of a 3
@HomelessCoaching
@HomelessCoaching 3 жыл бұрын
Can someone explain question 2 please?
@burrowsphysics
@burrowsphysics 3 жыл бұрын
Essentially you have 2 parallel branches connecting X to Y. (One branch with a total resistance of 30 + 30 = 60 and the other branch with a total resistance of 20 + 20 = 40) Since those two branches are in parallel, we calculate their total resistance using: 1/R = 1/40 + 1/60
@Johnny_1090
@Johnny_1090 2 жыл бұрын
Because you can't add 2 fractions with a different denominator, we have to find the lowest common in so we x one by 2 and the other by 3
@musfiqurrahman3964
@musfiqurrahman3964 4 жыл бұрын
You're making the calculations very complicated and this is gonna confuse the students. I don't recommend this video
@macvnc9060
@macvnc9060 4 жыл бұрын
Which video do you reccomend?
@user-hq6sp
@user-hq6sp 3 жыл бұрын
As a student, I think the calculations are quite clear to understand and found this video very useful. I will be recommending my friends to watch it
@bobbyclarke591
@bobbyclarke591 4 жыл бұрын
7:50
@medinecharyyeva9313
@medinecharyyeva9313 4 жыл бұрын
in Question 1 you don't have to find the total power in parallel like we do with resistance 1/R + 1/R ???????
@aron4317
@aron4317 4 жыл бұрын
I hate uncertainty question 😕
@burrowsphysics
@burrowsphysics 4 жыл бұрын
I don't think it is anyone's favourite part of being a scientist but it is an important part of all experimental work!
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