A Nice Ln Equation

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SyberMath Shorts

SyberMath Shorts

Күн бұрын

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Пікірлер: 9
@adrianfletcher8963
@adrianfletcher8963 3 күн бұрын
Lol I need to stop doing the problems from the thumbnail. I got stuck cause I was like what are we solving? Then again, I should have known that there's 1 equation with 2 unknowns, so it's not like I could have solved for either
@forcelifeforce
@forcelifeforce 3 күн бұрын
@ SyberMath Shorts -- You should put the arguments inside of grouping symbols: ln[(a + b)/3] = [ln(a) + ln(b)]/2.
@prollysine
@prollysine 3 күн бұрын
ab/(a+b)=e , ab/(a+b)=e^2/e , ab=e^2 , a+b=e , b=(e+/-e*i*V3)/2 , a=(3e+/-e*i*V3)/2 ,
@rajeevlochan5499
@rajeevlochan5499 4 күн бұрын
Solve my problem if you are really capable of I guess IT IS AS FOLLOWS: if x^2+x=1 then x^7+34/x+1=?
@AliAlperYILDIZ-mz6bo
@AliAlperYILDIZ-mz6bo 3 күн бұрын
I'm going to call golden ratio = y in this equation. putting the -1 to left side and using the quadratic formula we get x = -y or y^(-1) Question wants you to answer (x^8 +x +34)/x Plug the answers we got in the first equation then you can find the exact value using binomial expression.
@AliAlperYILDIZ-mz6bo
@AliAlperYILDIZ-mz6bo 3 күн бұрын
Or you can use fibonacci series to find the answer If you know that trick as well.
@Anonymous-zp4hb
@Anonymous-zp4hb 3 күн бұрын
if xx = 1-x then x = (-1 +- sqrt5)/2 let k be such that: kx = x^8 + x + 34 if f[n] is the nth Fibonacci number, then it's easy to show that: (f[n] - f[n+1]x) (1 - x) = f[n+2] - f[n+3]x and since x^8 = (1-1x)^4 and 1 = f[0] = f[1] we get x^8 = 13 - 21x and so the problem becomes k = 47/x - 20 Plugging in the known values of x we get: k = (7 +- 47sqrt[5])/2 which are approx: -49.047597471245057865615581215181 or 56.047597471245057865615581215185
@danielpraise2146
@danielpraise2146 2 күн бұрын
This is not hard at all
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