Can You Solve A Nonstandard Equation?

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[@scottleung9587]

I got x=1 by inspection.

[@renesperb]

The solution x= 1 is obvious. The function x*e -e^x has the maximum 0 at x=1 ,therfore , x=1 is the only real solution.

[@tunistick8044]

The table of variations is a little off because you haven't set 0 and drawn under it a double line to indicate that's it's neither differentiable nor defined in that point. f' will still be negative in ]-∞;0[ and in ]0;1[ thus requiring to calculate the limits in 0^- and -∞ since it decreases in ]-∞;0[. After studying such variations, it appears that f decreases from 0^- to -∞ hence f(x)

[@benardolivier6624]

I took the W path and got x = -W(-1/e) before realizing that -1/e = (-1)*e^(-1) so W(-1/e)=-1 and the solution was x=1... 🤦‍♂

[@Drk950]

Trivial Solution: x=1 Interesting thought --> Taylor Series

[@yusufdenli9363]

e^x /x = e x / e^x = 1/e x. e^(-x) = 1/e -x. e^(-x) = -1/e W(-x. e^(-x)) = W(-1/e) -x = W( -1. e^(-1)) -x = -1 x=1

[@SALogics]

By inspection x = 1 👍👍

[@giuseppemalaguti435]

x=-W(-1/e)=1

[@yakupbuyankara5903]

X=1

[@FredJehomiah]

Greetings, Chief Sybermath pls kindly check the math problem below Find A, B and C, cr[cr(2) - 1] = cr(A) + cr(B) + cr(C) Where cr means cube root

[@vladimirkaplun5774]

4,2,1

[@SyberMath]

Check this out: kzbin.info/www/bejne/mobceYFrj9F6Zsk

[@SyberMath]

those numbers do not work! Check this out: kzbin.info/www/bejne/mobceYFrj9F6Zsk

[@KyyTyy]

😢

[@claudelebourlegat]

So obvious,boring