1:57 - не по правилам! (x+1)(x³+x+1)=0. x=-1 ∨ x³+x+1=0.
@SALogics18 күн бұрын
Very nice! ❤
@jedrzejczyzkowski857719 күн бұрын
My stupid ass immiedietely thought of 1
@LTG_Lanny19 күн бұрын
It’s one of the answers though, right?
@coolvijay512819 күн бұрын
I thought of the same answer just after seeing the thumbnail
@1234larry117 күн бұрын
Yes, it’s a “trivial” answer, sort of like: You’re going into an important board meeting and you ask your friend, “ what do I do after I get in the room ? “ and he says, “close the door.”
@wes962719 күн бұрын
Euler made this problem easy by noting that 1=e^{2ijπ}, where e is Euler's number, π is the ratio of circle circumference to diameter, i=√(-1), and j is any integer. For x^n=1=e^{2ijπ}, n any positive integer, the n roots would be given by x_j=e^{2ijπ/n}=cos(2jπ/n)+i*sin(2jπ/n), j=0,1,...,n-1 For x^5=1=e^{2ijπ} we have x_j=e^{2ijπ/5}=cos(2jπ/5)+i*sin(2jπ/5), j=0,1,...,4, which are easily evaluated using a pocket calculator.