A Non-Standard Equation | Math Contests

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SyberMath

SyberMath

Күн бұрын

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Пікірлер: 25
@lawrencejelsma8118
@lawrencejelsma8118 7 ай бұрын
As you showed by each function (1/2)^x or 2^(-x) is a decreasing function meeting with the linear line functiom (1)(x + 6) that increases in the same intervals. The play with W Lambert function on the ratio to the power eaualling the linear line was interesting! ☺️👍
@user-qr5gy2kp7e
@user-qr5gy2kp7e 7 ай бұрын
I taught high school math for 35 years so I recognize an excellent teacher. Over the past year or so I am so impressed with your ability to explain complex ideas in an easily understood fashion. Yes I should join your site because I try a lot of your questions and then watch your approaches to the solutions. I particularly like your multiple solution approaches with a graphical approach at the end. I am a math major and must admit I never heard of Lambert's function before seeing you applying it. Very cool.
@ZipplyZane
@ZipplyZane 7 ай бұрын
I was glad to see you work out what W(n) was without Wolfram Alpha. With x being an integer, I knew there had to be a way. One thing about how my brain works: I would have just divided ln16/ln2 = log_2(16) = 4. Probably because I never knew about being able to move log down until I started warching your videos. I passed freaking Calculus without ever using ln(2^x) = xln2.
@SyberMath
@SyberMath 7 ай бұрын
Glad to hear that! Thanks for your comment
@giuseppemalaguti435
@giuseppemalaguti435 7 ай бұрын
x=(W(64ln2)/ln2)-6=4-6=-2
@mcumer
@mcumer 6 ай бұрын
I found x=-2 and it is the only one solution because y=x+6 is an increasing funcion while y= 1/2 is a decreasing funcion
@eureoma578
@eureoma578 7 ай бұрын
this was very beautiful
@SyberMath
@SyberMath 7 ай бұрын
Thank you!
@robot8324
@robot8324 7 ай бұрын
On the first look of it I used -2 😆
@scottleung9587
@scottleung9587 7 ай бұрын
I also got -2 as the only solution.
@michaelbaum6796
@michaelbaum6796 7 ай бұрын
Very nice equation- thanks a lot👌
@SyberMath
@SyberMath 7 ай бұрын
Glad you liked it
@farhansadik5423
@farhansadik5423 7 ай бұрын
Awesome!
@SyberMath
@SyberMath 7 ай бұрын
Thank you! Cheers!
@Mehrdad_Basiry-fj4rl
@Mehrdad_Basiry-fj4rl 7 ай бұрын
So amazing... learn alot...❤❤❤.
@SyberMath
@SyberMath 7 ай бұрын
Thank you so much 😀
@walterwen2975
@walterwen2975 7 ай бұрын
A Non-Standard Equation: (1/2)ˣ = x + 6; x = ? (1/2)ˣ = 1/2ˣ = x + 6, 2ˣ(x + 6) = 1; x < 0 Solving the exponential equation using Trial-and-error math: x = - 1: 2ˣ(x + 6) = (- 1 + 6)/2 = 5/2 > 1 x = - 3: (- 3 + 6)/8 = 3/8 < 1; - 1 > x > - 3 x = - 2: 2ˣ(x + 6) = (- 2 + 6)/4 = 1; Proved Answer check: (1/2)ˣ = x + 6; Confirmed as shown Final answer: x = - 2
@sunny_25
@sunny_25 7 ай бұрын
X=-2....is the only solution... Verified graphically
@reckless_r
@reckless_r 7 ай бұрын
Geographycally
@rakenzarnsworld2
@rakenzarnsworld2 7 ай бұрын
x = -2
@johnpinckney7269
@johnpinckney7269 7 ай бұрын
nice
@SyberMath
@SyberMath 7 ай бұрын
Thanks
@reckless_r
@reckless_r 7 ай бұрын
Lnlnlnlnlnlnlnlnonlnlnknonlnlnlnlnlnlnlmpbknlnlnlnlnlnlnlnlnlnlnlnlmlnlnlnlnlnlnlnnllnlnlnlnlklnljlnlnlmnklnnlmnnllnnnlmnnklnnnnnnnnnnnnnnnnnnnnnnnlllllllllllbbnnnnnnmnm
@SyberMath
@SyberMath 7 ай бұрын
😮😜😁
@marwansal4175
@marwansal4175 6 ай бұрын
Most important lesson here: manipulate equations but NOT people 🤗😔
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