Solving A Non-Linear Differential Equation

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[@theelk801]

if you do u=y^2+x you end up with a separable equation

[@florianbuerzle2703]

Please more differential equations 😊

[@barberickarc3460]

Your method was more complicated than needed. This is a bernuli equation, if you put it in the form y' - y = x*(y^-1) Bernuli happens when you have a y^1 term and y^n term You do the sub u=y^(1-n), in this case y^(1- (-1)) or u=y^2 From this du/dx = 2y dy/dx Now just multiply the original equation by our u and you get 2y* dy/dx '- 2y^2 =2x Notice the diff we did earlier so sub in du/dx = 2y dy/dx We now have du/dx - 2u =2x This is a linear in u, the integration factor ends up being e^(-2x) and when we clean up we get u*e^(-2x) = 2* the integral [ x*e^(-2x) ] dx Do int by parts then substitute back in u=y^2 and the final result is y = ± sqrt[A*e^(2x) - x - ½]

[@wafflaaar1067]

u' - 2u = 2x looks like a situation to use integrating factor, with I = e^-2x - wonder if we arrive at the same conclusion. granted we would have to do integration by parts on the RHS.

[@jamescollis7650]

When that alarm went off thought you'd added cool outro music to your video 😊

[@holyshit922]

At the first sight I see Bernoulli equation Bernoulli equation has its own integrating factor mu(x,y) = exp((1-r)Int(p(x),x))y^{-r} so it is not necessary to reduce it to the linear equation Procedure for solving Bernoulli equation is similar to this which is used for solving linear equation

[@SyberMath]

Too complicated! 🤪😁

[@scottleung9587]

Cool!

[@michaelbaum6796]

A cool substitution 👍

[@SyberMath]

Glad to hear that

[@user-lu6yg3vk9z]

@@SyberMathtry this problem Find a function where the derivative is equal to its inverse f’(x)=f^-1(x)

[@mcwulf25]

I thought you were about to do a W at the end there.

[@spfc20052008]

what is the height of a fluid inside a sphere when it occupies 1/4 of the sphere? ​

[@shmuelzehavi4940]

Calculate it.

[@thegiganerd395]

How do we know this is the only solution?

[@tarunmnair]

@4:50 I think the usage of D is right but the common part is not, I think it should be (D-2)u=0, thus, we can replace D with r to get homogeneous equivalent equation... but somehow the solution arrived was the same... 😅😅😅

[@SyberMath]

Ooopsies! 😂

[@mikoajpatera2660]

do you know ( or anyone that read this comment) know any programs I can have graphs of x,y and Im at the same time? on the internet its called phantom graphs

[@theCzechoslovak]

Are we ever gonna run out of problems to solve?

[@SyberMath]

Probably not