A student focuses the image of a candle flame, placed at about 2 m from a convex lens of

A student focuses the image of a candle flame, placed at about 2 m from a convex lens of focal length 10 cm, on a screen. After that, he moves gradually the flame towards the lens and each time its image on the screen. (a) In which direction does he move the lens to focus the flame on the screen? (b) What happens to the size of the image of the flame formed on the screen ? (c ) What difference is seen in the intensity (brightnees) of the image of the flame on the screen ? (d) What is seen on the when the flame is very close (at about 5 cm) to the lens ?

[@user-cl3kc6mu4z]

Are wah itna achha sikhaya ki,.......... ......kuch bhi samaz nahi aaya😅

[@leimran6278]

Minus common liya to f pe minus kyu nhi lagaya

[@arnabyt2452]

Are kuch samjh nhi aaya

[@khushipant8903]

Needs more improvement

[@commentkarloyaaiit.goandst9309]

Really.

[@mohammadadilansari5924]

Wrong explanation. Please contact me. I will give you correct explanation. When you move lens to left because v is increases. Then at that u also decreases because distance between lens and object is also decreases when you move lens towards the object. That is left side

[@krrish304]

plz tell correct explanation

[@javeen3583]

4.56: isnt focal length - 10? not +10?

[@Vikash25676]

Image is formed on a screen so it is real and inverted image. And moreover it is a convex lens so it is positive

[@divyanshikashyap8480]

Thanks

[@bijubordoloi5052]

Thank you

[@shashank9726]

Thankyou sir

[@gamingbhai4205]

Very nice explaination

[@murlidharchaturvedi7109]

Question no. 4 Ka answer Nahi bataya Aapne sir