A tricky math problem for 10th Graders | Can you solve?

[@X00000370]

Another good start of the day. Thanks.

[@whodoesntcare]

This made me a little bit confident, thanks

[@pilulaster]

After doing y=2**x, factor 130=2*5*13 and test which combination gives proper y**2+1 and y values, leading to y=5.

[@Maths_Se]

Excellent ❤❤❤❤❤❤

[@RealQinnMalloryu4]

{1.50+65}=2.15 10^20^15 10^2^10^3^5 2^5^2^2^5^3^5 1^1^1^2^1^3^1 23(x ➖ 3x+2).

[@randomprince]

Awesome..👌🏽, I am from India 🇮🇳

[@FernandezBismarck]

Stop raping

[@paulerhard1252]

Beautiful! Just one question: when you write “Log”, do you mean “Ln”?

[@paulerhard1252]

Obviously, not “Ln”, when you write “Log5, base2”.

[@whodoesntcare]

From when exactly are you talking about

[@richardl6751]

For the final part, Ln5/Ln2 also equals 2.3219281.

[@paulerhard1252]

@@whodoesntcare: In general …

[@FarthingMark]

Doesn’t matter so long as all logs are to the SAME base.

[@prollysine]

x=log5/log2 , x^2+5x+26=0 , x=(-5+/-V(25-104))/2 , x=(5+/-i*V79)/2 , x=(5+/-i*V79)/2 ,

[@eng954]

logarithmic equations dont accept negative and complex roots? do i remember correcetly?

[@prollysine]

@@eng954 Yes, that's right, the complex solutions here are the power exponents, which can usually be checked with a computer. There is no negative prohibition on negative exponents.

[@zimmermanlandscape9287]

Bro it’s obviously between two and three. Just use s scientific calculator and try 2.5, then 2.25, then 2.37 then work it down to the final answer. If it takes ten minutes you’re doing it wrong

[@Sumit77661]

Great ❤❤❤❤❤❤