Sine rule in ADC 3/sin(theta) = DC/sin(2theta) Cosine rule in ADC 3^2=(DC)^2+5^2-2DC*5*cos(theta) Cosine rule in ABC x^2=(2DC)^2+5^2-2(2*DC)*5*cos(theta)
@soli9mana-soli49539 ай бұрын
Thank you for the sin(3α) formula I didn't know. My methos is very similar to your second one, the only difference is that once I found with sines law that DC = 6*cos α I applyed the cosine law on ADC doing: (6 cos α)² = 3² + 5² - 2*3*5*(2cos²α - 1) (being cos 2α = 2cos²α - 1) finding cos α = √ 6/3 and then cos 2α = 1/3 with those values you can find DC and X with cosine law