How to prove that Strings are immutable in Java? | Strings in Java | ABC

In today's Episode, learn How to prove String is immutable in Java & Why String is immutable in Java.
About the trainer: Mr. Manjunath Aradhya, a technocrat by profession, a teacher by choice and an educationist by passion. Under his able leadership, ABC for Technology Training which is a National brand enabling the creation of thousands of careers annually in the IT Sector. He has extensive experience working as a Business associate with Wipro Technologies. He has also served as a corporate trainer to many other leading software firms. He has been providing technical assistance to placement cell of various Engineering colleges. He has also authored numerous hot selling engineering and other textbooks which are published by Pearson Education, an internationally acclaimed publication house headquartered in London. Other renowned international publishers such as Cengage Learning headquartered in Boston, United States, have published books authored by him. C Programming and Data Structures book published by Cengage India Private Limited authored by a profound scholar Mr. Manjunath Aradhya is the prescribed book in Dr. Hari Singh Gour University which is the Central University and the oldest university in the state of Madhya Pradesh (MP), India
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[@nagesh007]

Thanks for coming to KZbin

[@nagesh007]

I was ur student , engineering batch : 2007 -2011

[@sanilwadakar4581]

Sir sorry my doubt might be silly,but I want to ask When we use just string we use concat & when we use stringBuffer we use Append.. Why can't we use concat method only?

[@shivankgarg1692]

x = x.concat(y); System.out.print(x); Output :ABCTECH You had not stored the value of concatenated string in any variable that's why it was not getting concatenated

[@ABCforTechnologyTraining]

ABC appreciates your efforts. But you must understand that when you say x=x.concat(y), then you are actually creating a new string ABCTECH and making reference x to refer to the new String. The original string ABC would still be unchanged or immutable. A copy of the original ABC is taken and TECH is concatenated with it and x is made to refer to it. While if you use StringBuffer or StringBuilder class, it’s the original ABC that gets altered. Hope you get it.

[@mcreyfonacier1982]

you reassinged the x to a new value not changed it, so string class is not mutable.

[@nagesh007]

Super sir.

[@adarshsagar8]

By having a programming knowledge(Java or Python), is it possible to get a technical job without a College degree..? Sir please answer me..?

[@srajsekhar4061]

Well it's possible only in Bangalore . There are some campany they won't ask u any degree certificate and they only see the knowledge

[@ganeshaitha664]

Then what makes differ between stringbuffer and stringbuilder...? By both we can create mutable objects

[@ABCforTechnologyTraining]

It makes a lot of difference in a multi-threaded environment.

[@chukkadhanalakshmi4853]

tq sir your explanation is very nice but it is not clear sir

[@ABCforTechnologyTraining]

We regret the lack of clarity. Can you please be more specific as to what isn't clear?

[@SubelalPal]

String s="abc" ; s="xyz" ; Output is coming xyz It is changing why????

[@ABCforTechnologyTraining]

That's right. Please understanding the meaning of immutable strings, in this example, you're NOT modifying the original string "abc", it would remain unmodified. In the second instruction, you're creating a brand new string called "xyz" and re-assigning the string reference variable to this new string. In simple words, this is just simple reference type assignment, the address of new String object is re-assigned to the reference variable 's'. Because of this re-assignment, the original String object "abc" will not have a reference pointing to it, hence it would be garbage collected.