Abstract Algebra | Properties and examples of ring homomorphisms.

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Michael Penn

Michael Penn

Күн бұрын

Пікірлер: 12
@ashishKjr
@ashishKjr 4 жыл бұрын
Hello! Can you make some videos on Orbit Stabilizer theorem, Class equation, Sylow's theorem?
@MichaelPennMath
@MichaelPennMath 4 жыл бұрын
Yes, these are already in my overall plan.
@darrenpeck156
@darrenpeck156 2 жыл бұрын
Please make these videos. I love the involved long examples; it's like story telling!!!
@JaredCai
@JaredCai 2 жыл бұрын
12:44 I think he meant there's no ring isomorphism(where he said homomorphism) from 2Z to 3Z.
@maxdickens9280
@maxdickens9280 Жыл бұрын
He didn't solve the equation correctly. In fact, n=0 is an additional solution for 6n = 9n^2. Nonetheless, this implies that the homomorphism simply maps every number to zero, resulting in a trivial homomorphism.
@darrenpeck156
@darrenpeck156 2 жыл бұрын
How do we know n has an inverse for division?
@darrenpeck156
@darrenpeck156 2 жыл бұрын
Great examples!!!
@darrenpeck156
@darrenpeck156 2 жыл бұрын
Don't we need to be in Q for n to have an inverse, but we are only in Z. It seems to be a big problem. Unless we are in Z mod 3?
@asht750
@asht750 3 жыл бұрын
Some textbooks use the additive group or subgroup as a condition to prove if a subset of a ring is ideal.
@maxdickens9280
@maxdickens9280 Жыл бұрын
At 12:44: Michael didn't solve the equation correctly. In fact, n=0 is an additional solution for 6n = 9n^2. Nonetheless, this implies that the homomorphism simply maps every number to zero, resulting in a trivial homomorphism.
@abnerandreymartinezzamudio3366
@abnerandreymartinezzamudio3366 3 ай бұрын
He did explain that n ≠ 0 because φ is injective so 0 can only map to 0
@carlosdominguez9420
@carlosdominguez9420 2 жыл бұрын
Thanks Bro
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