AC Example-Complex Power

[@yujustin2980]

very nice video and the only video i can find on youtube!! by the way for anyone confused about average Power=1/2V(I)(Pf), since Vrms is V/sqrt(2) and Irms is I/sqrt(2), u time them together u get 1/2V(I)(Pf)

[@avaaa980]

I have been searching for something like this all day. This is a perfect example to study for my exam, thank you!

[@patriciabuckley2633]

Thank you sir. You just prevented many tears and mental breakdowns on the verge of panic attacks. 🙏 Truly and amazing service to the struggling university community

[@Vekna666]

S=V(rms)I*(rms) but he is using PEAK values and must divide BOTH V and I* by the square root of 2. When multiplied that gives you S=1/2V(peak)I*(peak)

[@doruksen9941]

at the beginning i thought the value of the voltage is given as rms value but then he did some calculations to find i phasor and impedance, after whole equation when he get to complex power calculation he divided into 2 the peak voltage (which i thought was rms value as i said) so it possibly gave the wrong outcome i believe.

[@tristanc6967]

You are a godsend. Thanks for the clear example, and useful insights!

[@TheAdlcn]

i'm watching your videos with *2 speed :)

[@predict-woo]

And it's still slow

[@a.m.k__9883]

thank you son much I have an exam tomorrow and I didn't know what the complex power meant now I do

[@Dpfpv1]

isnt the equation for complex power S=VI* ?

[@InuyashaITB]

Thank you very much for the instructional video. Have my test tomorrow. Wish me luck.

[@Concefacts]

Reactive power is nothing but the power oscillations in the circuit due to inductors and capacitors present. It is really confusing when we are studying reactive power only with the phasor diagram, I have explained the concept with the help of fundamental waveforms. Also explained why reactive power compensation is necessary, how we can compensate.

[@dannyrodriguez299]

Hi Darryl, is there any way you can do videos on second order RLC circuits?

[@MCShadesz]

How do you do the parallel calculation without using WA?

[@samudra4640]

was about to answer this but its 8 years ago XD

[@innermachinations4999]

@@samudra4640 better late than never

[@michaelmatheson2279]

Power factor needs more info. I think it needs a sign, like +ve or -ve? And "leading"or "lagging" ?

[@AArcher10]

how can I convert those problems without using wolfram alpha??

[@donaldt2846]

TI-89 Calculator

[@sbonelobonengcongo2262]

you a life saver thanks a lot sir everything is clear

[@sbonelobonengcongo2262]

any can help please sometimes when we calculating an apparent power we not introduce that halt sometimes we do eish im bit confused

[@UltimaWeaponz]

Hi Darryl, I read on your main site that you got from inspiration from Khan. Just wanted to say that I personally think you make much better content than him. I often find he goes off on tangents too often and doesn't cover advanced material very often. Good Job and keep it up :)

[@jakosnopp]

In wich video do you define the complex power S?

[@danalex2991]

Excellent video

[@Monerekobita]

polariy in ac source?

[@hithere8541]

Why is complex power equal to voltage times complex conjugate of current? Why is the current not taken as it is?

[@adityasahu96]

hi there! see conjugate comes because angle of current is being minus to angle of voltage or angle " between " voltage and current

[@hithere8541]

thanks Aditya Sahu!

[@ridzfeels9250]

nice video..really helpful..thank u very much sir..

[@winghungyip4107]

This video helps me a lot. Thank you.

[@KassemSaad-m8t]

thx it was so useful....

[@foxsteve5233]

u can pls ecplain apparent n passive power from trigonometri pls

[@tsunami1215]

should S be equal to V(eff)I*(eff) where v(eff) is V/square root of 2... do 170/square root of 2

[@abekim7]

i think you did this wrong. the 170 volts and 13.3 amps are not the max value but the effective value. Which makes S = Veff*Ieff. The source I looked at was my circuit analysis book,

[@padoucette1]

S=VI* not S=1/2(VI*)

[@juanhurtadollano8037]

do you know any place ( videos, lectures ), where I can study and learn power 1 for an electrical engineer?

[@32sstokes]

No

[@lexsonsamson6099]

Sir, you would better convert those numbers practical here... because the difficult part here to convert those numbers...

[@BRiCKY401]

170V is your RMS value

[@tsunami1215]

my bad got same results... was confused... was my first attempt though

[@dougouk]

Thank you.

[@MH-dk8oo]

Thank you

[@dhanabandot]

Thank you!

[@xxhkoom614]

thanks

[@kapilansatkunanathan4257]

thank you!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!life saver

[@secbgzn]

I can use wolfram at exam. Ty

[@foxsteve5233]

man its 170 angle 0 multiply by 1/root2

[@padoucette1]

My bad. Magnitude, not effective value. S=1/2(VmIm*)

[@jawadbinrashid9705]

tnk u sir

[@NitishChauhan1]

I have a feeling you screwed up a lot in this video

[@SakarPudasaini10]

No he hasn't. watch carefully!!!!!

[@SakarPudasaini10]

Just take a look the value of inductance is 0.04H and the value of omega is 377. So, to get the impedance, impedance= j*omega*inductance = j*377*0.04 (ohm) = 15.08j (ohm) You must have mistaken 0.04 as 0.4

[@bassmastapr]

don't sound so tired bro, it makes me tired

[@SmoothChino]

yeah, he gets tired from explaining you how to do your homework. ungrateful creature.

[@Necrodoxious]

You need a blanket too? Spoon fed information isn't enough these days.

[@jibrankhalil4837]

Vocal fry.

[@mandisa7356]

more enthusiasm in your voice please

[@FilipMaric00]

Thank you!

[@MohamedSaied-hf4lr]

thank you!