AC Load Line of BJT Amplifier Circuit

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ElectronX Lab

ElectronX Lab

Күн бұрын

Пікірлер: 28
@ozkang654
@ozkang654 4 жыл бұрын
Finally someone have more detailed explanation thanks buddy
@DAHBgraphy
@DAHBgraphy 8 жыл бұрын
Thanks David! I learned so much from your videos! Great review material!
@aerofart
@aerofart Жыл бұрын
Excellent video that leads to a great understanding of how transistors do their thing when amplifying AC signals. Another way to bias without all the math is to hook up your oscilloscope and run a sinusoid through the circuit to check for clipping and min/max levels. Also, a spectrum analyzer clearly reveals harmonic distortions.
@klipk7296
@klipk7296 4 жыл бұрын
finally a video where it isn't someone trying to explain this stuff with a thick indian accent
@ivyloca3443
@ivyloca3443 Жыл бұрын
Excellent explanation!! I finally understand it!
@manaoharsam4211
@manaoharsam4211 6 ай бұрын
Very Nice explanation.
@hardikjain-brb
@hardikjain-brb 11 ай бұрын
Doubling isnt good there can be saturation constraints also which may reduce the Vp-p if the emitter voltage is considerably high
@BenjaminK2
@BenjaminK2 11 ай бұрын
At @2:53 the guy seemed to indicate that the resistor "re" was part of the actual transistor and that the transistor "E" point was on the other side, below said resistor. Is this an error right? (Those who are more familiar with this stuff may glide over such a trivial detail, but I'm hanging on to every detail to trying to follow😅). Thanks
@ElectronXLab
@ElectronXLab 10 ай бұрын
re is part of the model of the transistor while RE is the external resistor that is part of the circuit
@TheZiggyman01
@TheZiggyman01 7 жыл бұрын
Hi David, @7:43 Can you please explain it in a bit more detail why you can use the Icq in place of the AC collector current?
@jasonw.2232
@jasonw.2232 7 жыл бұрын
I have the same question. Thanks in advance!
@jasonw.2232
@jasonw.2232 7 жыл бұрын
Nevermind, it's actually explained in the example video at 5:00. Because ic can swing down from the DC Q point to 0mA (when there is no collector current), the magnitude of ic is equal to the DC current Q value found before. Beyond this, we would have clipping, and therefore distortion of the incoming AC signal. Hope this helps!
@nevis2769
@nevis2769 Жыл бұрын
​@@jasonw.2232legend
@nhutnguyen2909
@nhutnguyen2909 3 жыл бұрын
it's helpful for me, thank you so much.
@ElectronXLab
@ElectronXLab 3 жыл бұрын
Glad to hear that
@aditikumari3677
@aditikumari3677 5 жыл бұрын
What is that re in ac model ?😥
@SaeedMurtaza
@SaeedMurtaza 5 жыл бұрын
nice explanation
@jamilhneini1002
@jamilhneini1002 6 жыл бұрын
Why is Vce = ic Rload and not Vce = - Ic Rload?
@yashgupta3127
@yashgupta3127 5 жыл бұрын
It's negetive actually see in diagram the slope is negetive
@workspaceofduc
@workspaceofduc 4 жыл бұрын
Why is Ic=Vcc/(Rc+Re) not Ic=Vcc/Rc? I thought Re is in another current?
@oneinabillion654
@oneinabillion654 3 жыл бұрын
@glyn hodges honestly I don't get it 😂
@e_wa.n5036
@e_wa.n5036 3 жыл бұрын
a little confusing with the way you draw your ac Vce i keep mistaking it for the root symbol. But otherwise...amazing job with the expliantion!
@ElectronXLab
@ElectronXLab 3 жыл бұрын
I'm glad you got something from my explanation, but sorry about my v's. I needed a way to distinguish upper case from lower case V's, but I think my hand just can't make a very convincing lower case v.
@likhithanakka
@likhithanakka 5 жыл бұрын
nice
@ronnachshon
@ronnachshon 5 жыл бұрын
god bless you!!!
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