AC Load Line of BJT Amplifier Circuit

[@aerofart]

Excellent video that leads to a great understanding of how transistors do their thing when amplifying AC signals. Another way to bias without all the math is to hook up your oscilloscope and run a sinusoid through the circuit to check for clipping and min/max levels. Also, a spectrum analyzer clearly reveals harmonic distortions.

[@ozkang654]

Finally someone have more detailed explanation thanks buddy

[@DAHBLIFE]

Thanks David! I learned so much from your videos! Great review material!

[@manaoharsam4211]

Very Nice explanation.

[@klipk7296]

finally a video where it isn't someone trying to explain this stuff with a thick indian accent

[@ivyloca3443]

Excellent explanation!! I finally understand it!

[@hardikjain-brb]

Doubling isnt good there can be saturation constraints also which may reduce the Vp-p if the emitter voltage is considerably high

[@SaeedMurtaza]

nice explanation

[@nhutnguyen2909]

it's helpful for me, thank you so much.

[@ElectronXLab]

Glad to hear that

[@BenjaminK2]

At @2:53 the guy seemed to indicate that the resistor "re" was part of the actual transistor and that the transistor "E" point was on the other side, below said resistor. Is this an error right? (Those who are more familiar with this stuff may glide over such a trivial detail, but I'm hanging on to every detail to trying to follow😅). Thanks

[@ElectronXLab]

re is part of the model of the transistor while RE is the external resistor that is part of the circuit

[@TheZiggyman01]

Hi David, @7:43 Can you please explain it in a bit more detail why you can use the Icq in place of the AC collector current?

[@jasonw.2232]

I have the same question. Thanks in advance!

[@jasonw.2232]

Nevermind, it's actually explained in the example video at 5:00. Because ic can swing down from the DC Q point to 0mA (when there is no collector current), the magnitude of ic is equal to the DC current Q value found before. Beyond this, we would have clipping, and therefore distortion of the incoming AC signal. Hope this helps!

[@nevis2769]

​@@jasonw.2232legend

[@ronnachshon]

god bless you!!!

[@aditikumari3677]

What is that re in ac model ?😥

[@e_wa.n5036]

a little confusing with the way you draw your ac Vce i keep mistaking it for the root symbol. But otherwise...amazing job with the expliantion!

[@ElectronXLab]

I'm glad you got something from my explanation, but sorry about my v's. I needed a way to distinguish upper case from lower case V's, but I think my hand just can't make a very convincing lower case v.

[@likhithanakka]

nice

[@jamilhneini1002]

Why is Vce = ic Rload and not Vce = - Ic Rload?

[@yashgupta3127]

It's negetive actually see in diagram the slope is negetive

[@workspaceofduc]

Why is Ic=Vcc/(Rc+Re) not Ic=Vcc/Rc? I thought Re is in another current?

[@oneinabillion654]

@glyn hodges honestly I don't get it 😂