This should be the ideal way to teach these concepts! Amazing explanation and presentation--hats off to you, sir.
@LALontoc5 күн бұрын
Thank you for posting these videos. They're totally helping me out in my school work.
@marq45 күн бұрын
I see why 4k||10k but wouldn't the result be in series with the 2k resistor? ((4||10)+2)
@jen-hungfang54377 күн бұрын
so good!
@naturetoday65317 күн бұрын
3.60 3.70 3.80 3.90 3.95 Please share resister value in voltage devider
@m.decock-perreman574110 күн бұрын
The correct answers are 3.23A for I1 and 3.54A for I2. Because you want proof of these answers. 7*3.23 - 3*3.54 = 11.99V and -3*3.23 + 5*3.54 = 8.01V. Your answers give for the second equation -3*4.38 +5*6.23 = 18.01V. This should be 8V and not 18V. You filled in the wrong voltage for the second equation. You also use a rather strange form of Cramers rule for I2.
@MarzNet25611 күн бұрын
Well explained.
@Aggregator_12 күн бұрын
for some reasons, the current rises from negative to zero instead of falling from 1.5 mA to Zero, which isnt the typical charging function of the Current in a Capacitor... its the discharge function. i dont get why the Current function is delayed like that. what did i forget?
@johncmitchell494114 күн бұрын
Other calculations have wanted an efficiency rating as on a motor's tag. This suggest I can use the resistance and perhaps derive the reactance and use those numbers to size a cap.
@abdellahtvtube882316 күн бұрын
Respect to you sir 🎉
@theblackowl623316 күн бұрын
Thank you very much! This video helped me a lot
@rtl7819 күн бұрын
❤
@flaviong885619 күн бұрын
Thanks!
@ASDERTORETRY20 күн бұрын
how to find Vc and Vbc
@ElectricalEngineeringApp20 күн бұрын
Thank you sir...
@richardgyamfi457420 күн бұрын
Thanks Sir ❤
@arashyusefi188925 күн бұрын
🙏 Thanks 🙏👍
@CarolineHuang-p8g26 күн бұрын
thanks so much. your website is amazing
@LovelyChewe27 күн бұрын
Good lecturing
@MohamedSaied-hf4lrАй бұрын
i love you
@hanchenchang9596Ай бұрын
don't know if i'm wrong, but how come the next state of 1010 is 0000
@MakSaabАй бұрын
Anyone from nutech electric 23
@JohnLeski-np4iyАй бұрын
It would be helpful if you refer to the spec sheet for transistors. how do you know what I(sat) is? spec sheet for a 2n2222 doesn't show I(sat). Otherwise it is a very good tutorial. makes me remember what I for got.
@firasb-ck1djАй бұрын
Thanks so much , very well explained
@theoryandapplication7197Ай бұрын
thanks
@j0mell0Ай бұрын
I have a simple question, and it may depend on its application. But what if we supply(Vin) to the negative(-) input instead while the positive(+) terminal is tied to Vout. I believe this configuration is also Vout = Vin ? It's more common to supply the positive input... why is it ?
@liamhorth756Ай бұрын
Can you please make a video with a example question where the capacitor voltage is higher than the source voltage
@manaoharsam4211Ай бұрын
Very Nice explanation.
@FourTwenyАй бұрын
"Like and subscribe if you do that sort of thing" 😂, I've never heard that one
@swaroopmuralidharan525Ай бұрын
Thank you!
@TeddyPhiri-uc9wpАй бұрын
From now you are my teacher. Easy to understand and explain well thanks.
@user-fx8oy1kd1v2 ай бұрын
Sir, I did not learn a bit. I have in fact learned A LOT. Thank you so much for this explanation. My finals are in a few days, and you have accelerated my learning.
@bangtanedhoe41072 ай бұрын
I love how you explain your answer for this problem. I hope you can create more example problems concerning different theorems (Branch current, maxwell, kcl/kvl, nodal analysis, superposition, thevenin and norton's).
@j.m42682 ай бұрын
Voltage divider rule?
@nhlanhlambuyazi75362 ай бұрын
I don't see jack
@borispasternak23562 ай бұрын
Amazing, thank you for having two alternatives for getting to the final equation, it was very helpful.
@borispasternak23562 ай бұрын
Was hard to find people who cared to explain how we arrived at this formula, thank you for doing that, sir.
@toinspireyou56392 ай бұрын
Wouldn’t ZL be at -90 degrees and ZC at 90 degrees, according to the ELI and ICE acronyms saying that the current of inductors lags the voltage and that the current of capacitors peaks before the voltage (on a phasor diagram)?
@larsthomsen64342 ай бұрын
easy to follow, worked
@virt1one2 ай бұрын
THANK YOU for demonstrating a single power supply schmitt trigger, I had to look around quite a bit to find your video. everyone with an op amp in their hand tunnel-visions thinking you MUST have a dual power supply if you're using an op amp.
@nicobriceno7322 ай бұрын
Awesome video. I would note that you can get an easier and quicker answer to solving the circuit by doing KVL in each loop and solving for currents 1 and 2, Since these elements are assumed to be behave linearly. By getting currents 1 and 2, you can solve the corresponding voltages across the resistors. I solved it this way and i got the same answers. Knowing this, i am just confused as to what came first and how to connect these ideas. Does KVL incorporate superposition through the currents ? OR is it better to think about these ideas separately?
@rauldebrouwer29632 ай бұрын
where AC source from thumbnail?
@mahmad85882 ай бұрын
justtttttttt Excellent, beautifully explained
@kiellandbrwn12 ай бұрын
Thank you sir 🙏🏾
@chocolatelasagna33282 ай бұрын
great resource, thanks for sharing
@4pharaoh2 ай бұрын
FYI “watch your p’s and q’s “ comes from the days of typesetting. In those days you set the mirror image of text you were setting using separate little metal characters. It was easy to confuse or flip a letter upside down. So the p, q, d and b always required extra attention as they were all easily mistaken. (Crap I’m old!)
@palashmondal792 ай бұрын
Sir you made mistake When you written C1 4.7MF but when finding capacitive reactance that time you use C2 value
@md.sabirhussain2372 ай бұрын
What will happen if we eliminate the 3 ohm resistor?as in practice,no resistors are used in series with the load.
@PraxZimmerman2 ай бұрын
You know, i've been beating my head against this problem for years. I work on batteries for a living and so was always assuming the voltage stays constant throughout the entire discharge