Acceleration down an inclined plane

[@Tenom1]

Damn just found this. This was a lot more intuitive than the other explanations I've been trying to find on the subject. Thank you.

[@ericbarbret3110]

When solving for Vf at the end you used the acceleration of gravity (9.8m/s^2) rather than the actual acceleration from the given angle which we calculated to be 2.2m/s^2 so Vf would be sqrt((2)*(2.2m/s^2)*(16.76)) =8.6m/s

[@lindo5100]

Check your limits or you can use trial and error

[@npcmaiko]

saw that as well

[@MO-lo2fe]

Agree 100% Should have been 2.2 not 9.8

[@jhononillgalvez950]

This man writes in to opposite direction. How incredible.

[@aliAlyacoub]

Its most likely that he writes in normal directions and then they flip the video when editing it

[@jmbayot]

@@aliAlyacoub Flipping the images would mean flipping the units too, which is not the case in the video. It could just be due to him being left-handed or practicing writing in this manner.

[@crazyspace6792]

@@aliAlyacoub Bit late to the party, but it's mirror magic.

[@aliAlyacoub]

@@crazyspace6792 Mirror the video in editing?

[@snowecaddel9454]

@@aliAlyacoubYep! That’s what’s happening. I still find it cool though.

[@tonesfactory5970]

U r not a just ordinary teacher sir U r extraordinary teacher. I Salute u sir. U fixed my prblm. Thnk u sir

[@yoprofmatt]

Wonderful. Glad to hear you found this helpful. Cheers, Dr. A

[@bananaall7613]

Very cool demonstration tools and explanation! Thank you.

[@bobbyjones7756]

Ah, that weren't no mistake at the end with acceleration. Just a teacher using a deft trick to see who's paying attention. Well done, Mr. A. ;)

[@manuboker1]

The best Physics teacher in the World !!!

[@yoprofmatt]

Thanks for that. I highly doubt it, but I appreciate the sentiment. Cheers, Dr. A

[@nativeafroeurasian]

I want him as my professor - the explanation my prof gave me was just incmprehensible; now I got it :)

[@oternoj]

@ 1:20, marks the wrong angle as Theta.

[@joeelliott2157]

David Klausen is correct. The angle 'theta' should be drawn between the vectors "g" and "g cos theta". Instead it is incorrectly drawn between "g sin theta" and "g". An easy error to make. I think this error would be easier to avoid if a smaller 'theta' was used in the diagram. With 'theta' not too greatly different from 45 degrees, 'theta' and it's 'complementary angle', theta' or [90 deg - theta], are too easily confused. But I do like this video that makes a good case for the acceleration down a frictionless plane as g * sin (theta).

[@kianvandenberg6364]

Why does V equal 2a X ?

[@niloybasu8030]

Why are we putting g as accn in root 2 gh

[@Teyros]

can someone please answer why he made the opposite side of the right angle gcosϴ? (when he drew the little diagram) shouldnt it be sinϴ because sinϴ is opposite the angle?

[@Teyros]

or is it gsinϴ just in relation to g?

[@yoprofmatt]

Taylor, This should help: kzbin.info/www/bejne/oGeWh2R7rbinetE Cheers, Dr. A

[@johnerickson2649]

It would appear that he accidentally put ϴ in the wrong place on the little diagram. It actually should have been used to label the 'bottom' angle on the little triangle.

[@cyrahalamag7119]

Helps a lot!

[@biucaevovo1640]

Hi teacher, i'm with doubt for Vf did you say VF = √(2 aXf , but in the calc you you show (video time 5:00) a=9.8 = √(2(9.8)(16.75) = 8.60m/s, but I try it and the answer is 18.12m/s. I try using using a=2.2 = √(2(2.2)(16.75) = 8.60m/s now the answer is the same your. a = acceleration, right? Please could you solve me this doubt. Thanks for your videos and time, I appreciate your job!

[@yoprofmatt]

Yes, typo at the 4:59 mark. Used the wrong a Thanks, Dr. A

[@niloybasu8030]

Exactly I can't understand which acc should we use

[@no000]

[@LaxmiGupta-fv4rm]

But what if the surface, on which the inclined plane is kept, is frictionless

[@yoprofmatt]

ITSME Laxmi, You're very welcome. Glad you're enjoying the videos. If it's frictionless, just let µ =0 and you're all set. You might also like my new site: universityphysics.education Cheers, Dr. A

[@LaxmiGupta-fv4rm]

@@yoprofmatt But you have not assumed any psuedo force if the incline will be movable

[@mamadoudiobetdiop3552]

If I am not wrong, the angle theta is not at the right place. However, this is a great option to use.

[@yoprofmatt]

This is the "standard" example used in physics. Theta is usually relative to the horizontal (but of course, not always). Cheers, Dr. A

[@mohammadthanni1303]

Thank you sir❤

[@sydneywilliams1536]

thank you so much

[@eraserqueen297]

Matt you look like you're filming a horror movie 💀

[@snowecaddel9454]

Physics is the demon! 😂

[@nscspeedcubing9293]

there is an error in the calculation.. your components of g are wrong

[@MO-lo2fe]

When calculating V final acceleration should have been 2.2.. not 9.8 ?!?

[@XMostaxX]

1:20 that's not his angle theta

[@error5202]

he looks spooky in the dark

[@respectable2540]

11 years ago damn

[@jhononillgalvez950]

I don't understand.🥺

[@neo.phoenix4050]

is he writing backwards or am i tweaking

[@baronstomper]

u creepy as hell but u so good at explaining physics

[@burhanmaryam]

What is the thing he's writing on

[@etienne753]

a window

[@yoprofmatt]

Eeman's World, The board is called Learning Glass. You can check it out at www.learning.glass Cheers, Dr. A

[@ceku-ge2ti]

my left ear says thanks

[@bezveze8047]

Leftie! :)

[@turquoisejpg5671]

bez veze the video was flipped to allow poeple to read the writing on the board. He is actually right handed. Sorry.

[@jeromecantong1202]

cool

[@yoprofmatt]

Jerome Cantong, Great comment, thanks. You might also like my new website: www.universityphysics.education Cheers, Dr. A

[@oternoj]

@ 5:00, puts in the wrong value for a

[@no000]

bruh

[@jeromecantong1202]

he inputed the wrong a

[@yoprofmatt]

Jerome, That sounds likely. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A