Advanced Functions 6.7 Rates of Change in Trigonometric Functions

Correcting the textbook's solution to number 9 we will use this problem to find the equation of the graph, explain where the fastest and slowest rates of change occur and find an instantaneous rate of change using a centered interval.

[@BabaSphere]

Miss there's no possible way that I can express my gratitude enough! These videos have saved my grades in both functions and advanced functions and I'm so thankful!!!

[@mshavrotscanadianuniversit6234]

That’s so nice to hear!! Good for you for seeking out my channel and doing the work that it takes to be successful. 😊

[@mathyyds]

Very helpful video! You explain these concepts thoroughly and in an easily-comprehended way :) Thanks a lot!

[@mshavrotscanadianuniversit6234]

You're very welcome!

[@jonwill]

On the last rate of change question my first Y value is 20.220 (degree mode). Is your value of 21.365 (radian mode) more correct - more appropriate, or both? Is there a general rule/best practice for applying radian mode?

[@mshavrotscanadianuniversit6234]

If you are given radians in the question you should answer in radians. Not sure which question you are asking about but that is the rule.

[@jonwill]

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[@diyonfernando5667]

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[@mshavrotscanadianuniversit6234]

Glad you are having success with my lessons!

[@diyonfernando5667]

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[@mshavrot_math]

@@diyonfernando5667 that’s great to hear!!!

[@mshavrotscanadianuniversit6234]

You put the work in! Good for you!

[@meenakumar4545]

at 13:14, should the slowest IRC point not be 46 instead of 48? Is that an error? Please correct if it is. Thank you for the amazing video.

[@mshavrotscanadianuniversit6234]

Yes, you are correct. It’s pretty much impossible for me to correct small mistakes once the video has been uploaded (without redoing the entire video) so I’ll have to rely on people reading the comments. Thanks for watching! 😊

[@anishahuja537]

Hi Ms.Havrot, would the fastest IRC for every sine/cosine function be at the axis of the function and the slowest IRC be at the highest and lowest points of the function or is it different for every trig function?

[@mshavrotscanadianuniversit6234]

Yes, you have the right idea. The greatest rate of change will happen where the slope of the tangent to the function is the steepest and that does occur half way between the max and min of the function which, as you said, is where there axis is. There is zero slope at the max and min values.

[@anishahuja537]

@@mshavrotscanadianuniversit6234 ok thank you

[@maxmichet316]

Hello Ms Havrot. I was wondering if you were ever considering doing some physics lessons? Nevertheless, your videos are amazing and extremely helpful, thank you.

[@mshavrotscanadianuniversit6234]

I’ve never taught physics and I’m afraid I wouldn’t be very good at explaining it! Never too late to learn though, right?

[@maxmichet316]

​@@mshavrotscanadianuniversit6234​ That's fine! Thanks :)

[@ruhanaabdulraheem8778]

so helpful, thank you so much. I just have a question, why is it - 4.5 and not just 4.5?

[@mshavrotscanadianuniversit6234]

Please add a time on the video when you have a question to help me find it more quickly. I'm assuming that you mean at 12 min. The amplitude is - 4.5 for the sine function because if you start on the axis you can see that the function goes down first (which means that it is a negative sine function). In the normal (positive) sine function it would have to go up. Hopefully that is what you are asking. If not, let me know!

[@ruhanaabdulraheem8778]

@@mshavrotscanadianuniversit6234 ohh ok thank you so much!

[@ghalebabusneineh2148]

Where did the 3 and the 5 come from

[@mshavrotscanadianuniversit6234]

You are trying to find the rate of change at 4 so I used a centered interval.

[@nadinesereda-sass158]

miss if we are using (Y2 - Y1)/(X2 - X1) then wouldn't it look something like: (19.035 - 21.365)/(5 - 3)?

[@mshavrotscanadianuniversit6234]

Can you give a time on the video please?

[@nadinesereda-sass158]

@@mshavrotscanadianuniversit6234 16:38 where you are inputting the numbers for the IRC

[@mshavrotscanadianuniversit6234]

@@nadinesereda-sass158 same thing. You will get the same answer.

[@richeezed2k503]

ahhh thank you so much!

[@mshavrotscanadianuniversit6234]

you're most welcome! Please like, subscribe and share to increase the channel's visibility. : )