Looks like youtube mislabeled your section on Hilbert's Nullstellensatz. Great video!
4 жыл бұрын
Hey Daniel, great video! :-) At 13:50 the important thing why Grothendieck used prime ideals is not that he wanted to go more general but its because max Ideals are just not the right object. mSpec wont be a functor in that case.
@lalaskustabaskus90266 жыл бұрын
Wow just stumbled on this by accident. Please keep up this great work. You can be the more advanced (older brother) version of Wildbergers Math channel! Keep posting videos!!!
@NoNTr1v1aL3 жыл бұрын
Amazing video!
@robinbalean9582 жыл бұрын
Very nice lecture!
@mactorresmo5 жыл бұрын
Fabulous teachings! Thanks Daniel!
@levkruglyak7 жыл бұрын
What a fantastic lecture. Thank you very much
@douggwyn96567 жыл бұрын
Audio needs boosting.
@gidi57796 жыл бұрын
Great video! Thank you very much!
@lelandreardon78446 жыл бұрын
A bit subtle at ~18:00. We're talking about "closed points" of Spec(Z), but we're determining if they're closed as subspaces of Z under the Zariski Topology? Nevertheless they're merely points in Spec(Z), correct? I.e. they're trivially closed sets of Spec(Z), but that's not the point being made?
@DanielChanMaths6 жыл бұрын
Some points are not closed. The prime ideal 0 in particular, is not closed in Spec (Z) since it is not of the form V(I) for some ideal I. The closure of the singleton set {0} is actually the whole of Spec(Z)!