Click here to try using the method of consistent deformations to solve a 2nd degree indeterminate beam! kzbin.info/www/bejne/l6e4kIykgLVmg5o
@andresdrum17 жыл бұрын
Awesome video...clear and straight to the point!
@AFMathandEngineering7 жыл бұрын
+A DC thanks so much!
@gamolly6 жыл бұрын
This will help me so much with my computer aided analysis course!
@AFMathandEngineering6 жыл бұрын
gamolly glad to hear bud!
@korni2k7 жыл бұрын
My favourite video these days =)
@onelastsubing5867 жыл бұрын
Great video! Didnt see this subject around KZbin, plz do more hahaha
@zahraafluid53835 жыл бұрын
thank you i enjoy in this video
@karinakuyek62205 жыл бұрын
shouldn't Ybb be negative since the force is upward and the formula is for downward force.Hence sign switch?
@AFMathandEngineering5 жыл бұрын
Sign convention used here is downward deflection = negative, upward deflection = positive. Note that deflection fbb calculated due to upwards unit load instead of support is positive and delta bo is negative (downward).
@HeidiAmpore6 ай бұрын
which formula did the used formula came from?
@NK-qd7xk3 жыл бұрын
Thanks 👍
@jasmineroberts45414 жыл бұрын
Hello! Thank you so much for this video it helped me out so much. I was just wondering why 144.33 came out as positive. When I tried it on my own I got fbb = (1/6EI)*((7^3)-(3*7*7^2)) = -144.33 Thank you again and please keep up the good work!!
@AFMathandEngineering4 жыл бұрын
Thanks for the feedback, glad you're enjoying the video! The negative and positive sign are simply sign convention, we assigned downward deflection as negative and positive as upwards. You could switch them if you like as long as you're consistent. Hope that helps.
@roido4304 Жыл бұрын
I got -22,509.375/EI for Bo. w=15 a=14 x=7. did i get the values wrong?
@ชญานิษฐ์กิจเมฆ5 жыл бұрын
My country didn’t have a deflection table they use some kind of intergrade like equation BO = 0 = |m1m2ei
deflection tables are located in a number of places, if you've purchased or have a pdf of the structural analysis textbook for your course they should be in the appendix in the back. Also, the steel or concrete building code for your country will have all the relevant deflection tables, if you're in civil engineering in university you're probably obligated to buy these. If you don't have any of these, google beam deflection tables and you should find some.
@loolick83075 жыл бұрын
Just wonder if you get your By at such big value with small point load / uniform load, wouldn't Ay be negative value? I'm facing the same problem
@AFMathandEngineering5 жыл бұрын
Why are you finding Ay here?
@loolick83075 жыл бұрын
@@AFMathandEngineering After the force method, using the equilibrium equations
@AFMathandEngineering5 жыл бұрын
@@loolick8307 sorry I'm not really sure why you're confused, just take sum of forces in y and solve for Ay. Whatever Ay ends up being (negative or positive) that's what it is. Remember there's also a moment reaction at A.
@maliktayyab58845 жыл бұрын
degree 2.. i want to learn plz make video
@AFMathandEngineering5 жыл бұрын
kzbin.info/www/bejne/l6e4kIykgLVmg5o
@_GlamDiaries3 жыл бұрын
How you get fbb= 114.38/EI ?when i do with same equation i got a negative value.
How do you get those deflection equations by just formulae...... P/6EI(X3-3ax2)
@AFMathandEngineering6 жыл бұрын
You can derive them, or just use the already derived table from your textbook, which will most likely be available to you during the exam.
@eriknelson25594 жыл бұрын
What happens if you try to add in consistent deformation compatibility equations into an already statically determinate scenario? Would you wind up with more equations than unknowns and an unstable structure?
@unliwanderer29853 жыл бұрын
I think statically determinate structures already satisfies equilibrium equations.
Sign convention used here is downward deflection = negative, upward deflection = positive. Note that deflection fbb calculated due to upwards unit load instead of support is positive and delta bo is negative (downward).
@civiltutorvlogs69127 жыл бұрын
anybody tell me...does a refer to entire span or the span other than x
@AFMathandEngineering7 жыл бұрын
Knowledge Easy if you refer to your deflection tables in your code book or textbook it should be very clear which one is which.
@AFMathandEngineering7 жыл бұрын
Also, remember there are many different formula derived for deflection..you don't have to use this one. In this particular formula a refers to the length of the distributed load starting from the fixed support.
@viscourtroy4 жыл бұрын
4 unknowns?? Which unknowns?
@AFMathandEngineering4 жыл бұрын
Unknowns are referring to the reaction forces (what were trying to solve for). We have a fixed support (3 unknown reaction force) and a roller (1 unknown reaction force).
@diflection17 жыл бұрын
3 reactions, not 4 ?
@AFMathandEngineering7 жыл бұрын
+THE STRUCTURAL ANALYSIS MATRIX FORMULATION there are 4 reactions on the original beam, 3 reactions after the redundant support is removed.
@diflection17 жыл бұрын
by removing the support @B leaves two only Ra and Ma ........
@AFMathandEngineering7 жыл бұрын
Ma, Ax, Ay
@diflection17 жыл бұрын
let me tell you something Ax and Ay are component of a F vector.
@AFMathandEngineering7 жыл бұрын
+THE STRUCTURAL ANALYSIS MATRIX FORMULATION If you return to strengths of materials 1 you'll see that the reaction vector is broken up into two forces, reaction in x and reaction in y and considered two reactions when analyzing supports such as a fixed support or pinned support.
@civiltutorvlogs69127 жыл бұрын
sir your calculations are wrong
@AFMathandEngineering7 жыл бұрын
Knowledge Easy thanks for the post...which calculation is incorrect?