Method of Consistent Deformations to Solve a 1st Degree Indeterminate Beam (Force Method)

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AF Math & Engineering

AF Math & Engineering

Күн бұрын

Пікірлер: 53
@AFMathandEngineering
@AFMathandEngineering 7 жыл бұрын
Click here to try using the method of consistent deformations to solve a 2nd degree indeterminate beam! kzbin.info/www/bejne/l6e4kIykgLVmg5o
@andresdrum1
@andresdrum1 7 жыл бұрын
Awesome video...clear and straight to the point!
@AFMathandEngineering
@AFMathandEngineering 7 жыл бұрын
+A DC thanks so much!
@gamolly
@gamolly 6 жыл бұрын
This will help me so much with my computer aided analysis course!
@AFMathandEngineering
@AFMathandEngineering 6 жыл бұрын
gamolly glad to hear bud!
@korni2k
@korni2k 7 жыл бұрын
My favourite video these days =)
@onelastsubing586
@onelastsubing586 7 жыл бұрын
Great video! Didnt see this subject around KZbin, plz do more hahaha
@zahraafluid5383
@zahraafluid5383 5 жыл бұрын
thank you i enjoy in this video
@karinakuyek6220
@karinakuyek6220 5 жыл бұрын
shouldn't Ybb be negative since the force is upward and the formula is for downward force.Hence sign switch?
@AFMathandEngineering
@AFMathandEngineering 5 жыл бұрын
Sign convention used here is downward deflection = negative, upward deflection = positive. Note that deflection fbb calculated due to upwards unit load instead of support is positive and delta bo is negative (downward).
@HeidiAmpore
@HeidiAmpore 6 ай бұрын
which formula did the used formula came from?
@NK-qd7xk
@NK-qd7xk 3 жыл бұрын
Thanks 👍
@jasmineroberts4541
@jasmineroberts4541 4 жыл бұрын
Hello! Thank you so much for this video it helped me out so much. I was just wondering why 144.33 came out as positive. When I tried it on my own I got fbb = (1/6EI)*((7^3)-(3*7*7^2)) = -144.33 Thank you again and please keep up the good work!!
@AFMathandEngineering
@AFMathandEngineering 4 жыл бұрын
Thanks for the feedback, glad you're enjoying the video! The negative and positive sign are simply sign convention, we assigned downward deflection as negative and positive as upwards. You could switch them if you like as long as you're consistent. Hope that helps.
@roido4304
@roido4304 Жыл бұрын
I got -22,509.375/EI for Bo. w=15 a=14 x=7. did i get the values wrong?
@ชญานิษฐ์กิจเมฆ
@ชญานิษฐ์กิจเมฆ 5 жыл бұрын
My country didn’t have a deflection table they use some kind of intergrade like equation BO = 0 = |m1m2ei
@pasindupiumal9368
@pasindupiumal9368 3 жыл бұрын
Structural analysis basics kzbin.info/door/fZBo0T5G0W_rGYHAXfYIRwvideos
@ace0886
@ace0886 6 жыл бұрын
where do you find the table of deflections
@AFMathandEngineering
@AFMathandEngineering 6 жыл бұрын
deflection tables are located in a number of places, if you've purchased or have a pdf of the structural analysis textbook for your course they should be in the appendix in the back. Also, the steel or concrete building code for your country will have all the relevant deflection tables, if you're in civil engineering in university you're probably obligated to buy these. If you don't have any of these, google beam deflection tables and you should find some.
@loolick8307
@loolick8307 5 жыл бұрын
Just wonder if you get your By at such big value with small point load / uniform load, wouldn't Ay be negative value? I'm facing the same problem
@AFMathandEngineering
@AFMathandEngineering 5 жыл бұрын
Why are you finding Ay here?
@loolick8307
@loolick8307 5 жыл бұрын
@@AFMathandEngineering After the force method, using the equilibrium equations
@AFMathandEngineering
@AFMathandEngineering 5 жыл бұрын
@@loolick8307 sorry I'm not really sure why you're confused, just take sum of forces in y and solve for Ay. Whatever Ay ends up being (negative or positive) that's what it is. Remember there's also a moment reaction at A.
@maliktayyab5884
@maliktayyab5884 5 жыл бұрын
degree 2.. i want to learn plz make video
@AFMathandEngineering
@AFMathandEngineering 5 жыл бұрын
kzbin.info/www/bejne/l6e4kIykgLVmg5o
@_GlamDiaries
@_GlamDiaries 3 жыл бұрын
How you get fbb= 114.38/EI ?when i do with same equation i got a negative value.
@pasindupiumal9368
@pasindupiumal9368 3 жыл бұрын
Structural analysis basics kzbin.info/door/fZBo0T5G0W_rGYHAXfYIRwvideos
@manikantagodi3239
@manikantagodi3239 6 жыл бұрын
How do you get those deflection equations by just formulae...... P/6EI(X3-3ax2)
@AFMathandEngineering
@AFMathandEngineering 6 жыл бұрын
You can derive them, or just use the already derived table from your textbook, which will most likely be available to you during the exam.
@eriknelson2559
@eriknelson2559 4 жыл бұрын
What happens if you try to add in consistent deformation compatibility equations into an already statically determinate scenario? Would you wind up with more equations than unknowns and an unstable structure?
@unliwanderer2985
@unliwanderer2985 3 жыл бұрын
I think statically determinate structures already satisfies equilibrium equations.
@pasindupiumal9368
@pasindupiumal9368 3 жыл бұрын
Structural analysis basics kzbin.info/door/fZBo0T5G0W_rGYHAXfYIRwvideos
@pzab7022
@pzab7022 5 жыл бұрын
Hey I think your fbb should be negative
@AFMathandEngineering
@AFMathandEngineering 5 жыл бұрын
Sign convention used here is downward deflection = negative, upward deflection = positive. Note that deflection fbb calculated due to upwards unit load instead of support is positive and delta bo is negative (downward).
@civiltutorvlogs6912
@civiltutorvlogs6912 7 жыл бұрын
anybody tell me...does a refer to entire span or the span other than x
@AFMathandEngineering
@AFMathandEngineering 7 жыл бұрын
Knowledge Easy if you refer to your deflection tables in your code book or textbook it should be very clear which one is which.
@AFMathandEngineering
@AFMathandEngineering 7 жыл бұрын
Also, remember there are many different formula derived for deflection..you don't have to use this one. In this particular formula a refers to the length of the distributed load starting from the fixed support.
@viscourtroy
@viscourtroy 4 жыл бұрын
4 unknowns?? Which unknowns?
@AFMathandEngineering
@AFMathandEngineering 4 жыл бұрын
Unknowns are referring to the reaction forces (what were trying to solve for). We have a fixed support (3 unknown reaction force) and a roller (1 unknown reaction force).
@diflection1
@diflection1 7 жыл бұрын
3 reactions, not 4 ?
@AFMathandEngineering
@AFMathandEngineering 7 жыл бұрын
+THE STRUCTURAL ANALYSIS MATRIX FORMULATION there are 4 reactions on the original beam, 3 reactions after the redundant support is removed.
@diflection1
@diflection1 7 жыл бұрын
by removing the support @B leaves two only Ra and Ma ........
@AFMathandEngineering
@AFMathandEngineering 7 жыл бұрын
Ma, Ax, Ay
@diflection1
@diflection1 7 жыл бұрын
let me tell you something Ax and Ay are component of a F vector.
@AFMathandEngineering
@AFMathandEngineering 7 жыл бұрын
+THE STRUCTURAL ANALYSIS MATRIX FORMULATION If you return to strengths of materials 1 you'll see that the reaction vector is broken up into two forces, reaction in x and reaction in y and considered two reactions when analyzing supports such as a fixed support or pinned support.
@civiltutorvlogs6912
@civiltutorvlogs6912 7 жыл бұрын
sir your calculations are wrong
@AFMathandEngineering
@AFMathandEngineering 7 жыл бұрын
Knowledge Easy thanks for the post...which calculation is incorrect?
@isabellagarcia3875
@isabellagarcia3875 7 жыл бұрын
I HATE THIS SUBJECT!!!
@liagitado_0294
@liagitado_0294 6 жыл бұрын
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