OCR A 6.2.3 Polyesters and Polyamides

[@laurenkirsop8558]

timestamps 2:07 - the spec 2:15 - addition polymers 4:48 - condensation polymers 6:26 - polyamides 10:15 - polyesters 12:17 - hydrolysis

[@henryspooner9584]

Im doin chem, phys, bio and maths alevel so efficient revision is a big thing for me, and this channel is just what I needed to tighten up my revision for my least strong subject, so big thank you. Also its the night before an exam and this puts me at ease. Big Preesh

[@AlleryChemistry]

Best of luck!

[@luigiduprez7510]

you're not alone

[@elliesmith7518]

I'm doing chem bio and geog! Could never do 4 tho w chem too, crap that

[@bobbyjohnson9459]

What about acid and alkali hydrolysis of polyesters and amides

[@Sarah-kd7qg]

This was very helpful! Thank you for taking your time to make this video

[@ajtopchopper6884]

preciate this gangy

[@lilyambler545]

Are you able to please post the rest of 6.2 and 6.3 for OCR A? Thanks, love the rest of your videos by the way :)

[@aliananda6912]

nice way to summarise the topic :)

[@AlleryChemistry]

Thanks! 😃

[@LeahRebecca]

🙏🏾🙏🏾

[@cha0spretzel-534]

For molecules forming condensation polymers with themselves, does it matter if the amide link is drawn with the C=O before the N-H bond? Cos that’s what makes more sense imo. (Will i still get the marks?)

[@twinflame718]

Thank you so much for sharing Sir🙂

[@maheenchoudhry6611]

Thank you so much!

[@akshayanmuraleetharan2103]

this may be a stupid question but can a repeating ester molecule make a polyester?

[@sophiekrise]

how come kevlar has 2h20 eliminated but the previous example of a dicarboxylic acid and diamine did not?

[@sameulullah8757]

In the previous example, only one amide bond was made, hence 1H20. You can make another amide bond at the ends of the molecules, this would give us our 2H20. Hope that helps :)

[@MissAkua100]

king

[@ItsSapi]

12:03 should be the other way around, oh from the carboxylic acid and h from the alcohol to form h2o

[@butcherofblav1ken874]

I believe both versions are correct