Complete revision for EDEXCEL A Level Chemistry. To buy the PowerPoint used in this video please visit my tes shop - www.tes.com/teaching-resource...
Пікірлер: 50
@ahmedmersal81594 жыл бұрын
Not the hero we deserve, but the hero we need
@cherrybullet4956 Жыл бұрын
You are a blessing, you’re videos manage to get me from an E to a B at the end of AS, and I’m finding a-level so much easier now thanks to your videos!!
@AlleryChemistry Жыл бұрын
You're very welcome!
@xerp76264 жыл бұрын
thank you so much , these videos are incredibly helpful as i'm learning chem a2 alone.
@elisaswaby93123 жыл бұрын
I was on a c last year in chemistry and now I am achieving A and high a stars I couldn’t have done this without you
@dhruvvarsani22474 жыл бұрын
awesome video.easily understood buffers and you made these things look very easy. thank you!!
@nirmalkerai9643 жыл бұрын
All credits to you if in my upcoming A2 exams i get an overall A
@yourleftkidney3 жыл бұрын
So um what did you get? 👀👀👀👀
@mhd84992 жыл бұрын
@@yourleftkidney he got a U
@dondada44532 жыл бұрын
@@mhd8499 😭
@vishakasivamani7649 Жыл бұрын
@@mhd8499 damm
@Ombremugofyasamal2 жыл бұрын
Your videos are amazing, they are incredibly helpful!!! Thank you
@AlleryChemistry2 жыл бұрын
Glad you like them!
@yosufali66912 жыл бұрын
how may i express my thanks. this is amazing
@elisaswaby93123 жыл бұрын
Thank you so so much I don’t think you understand how beneficial these videos are.
@AlleryChemistry3 жыл бұрын
Happy to help!
@jwyz262 жыл бұрын
u are an absolute legend.
@jackstafford62683 жыл бұрын
Your my idol. Seriously video helped so much!
@st56767 Жыл бұрын
Thank you very much Mr Harris. These are very very useful indeed. I hope you are well.
@AlleryChemistry Жыл бұрын
You are very welcome
@Dr.Freeze3 жыл бұрын
You are a legend! I'm gonna ask all my friends to sub you
@TheBest-fj4qy3 жыл бұрын
you are 'The Best' !!!!!
@mickey70962 жыл бұрын
Mr Harris you are an angel :)
@kailihuang7901 Жыл бұрын
Thank you so much!! I always use your videos, so helpful.
@AlleryChemistry Жыл бұрын
You're welcome 😊
@johnsamangschannel82322 жыл бұрын
Thank you so much for all these videos
@AlleryChemistry2 жыл бұрын
You are so welcome!
@bholedg Жыл бұрын
About to go on a journey night before my exam
@AlleryChemistry Жыл бұрын
Hope it goes well! 👍
@raisadrawss4190 Жыл бұрын
cant thank u enough for ur hard work
@AlleryChemistry Жыл бұрын
You're very welcome! 😀
@hannah14973 жыл бұрын
Thank you very much sir
@shak84833 жыл бұрын
at 29:00 isnt the conc of H+ ions = 2 x conc of acid instead of conc of acid = 2 x conc of H+ ions?
@Dark_kittens123 Жыл бұрын
Yes
@tanimahmed50572 жыл бұрын
Can you make vidoes of worked solutions of recent past papers of edexcel ial chemistry unit 4,5 and 6?
@AliArif-yq5in7 ай бұрын
Thank you so much for the video sir, It's an Absolute Life Saver. However I just have one doubt If you dont mind clearing up. At 1:22:29 Why is Dissociation of the Salt an equilibrium, Isn't it Fully Dissociating so It just be an Arrow point to the right. I'm Most probably wrong but it would be helpful if you could clear it up. Thanks alot
@shaktheesivakumar1582 Жыл бұрын
thank u
@shaunlobo713419 күн бұрын
cheers mate
@kemuelfavour9292Ай бұрын
Wow this was helpful
@aliarif43397 ай бұрын
thanks
@Hk-gn4hs22 күн бұрын
legend bruh
@grace83012 жыл бұрын
1:05:04
@stardreamix786Ай бұрын
at 41:05 shouldn't the answer for the concentration of methanoic acid be 2.96x10^-11 moldm^-3 instead of 2.96x10^-3 moldm^-3
@hanamostafa52683 жыл бұрын
1:04:08 How here in weak acids you are saying that [H+]=[acid] isn't that only applies to strong bases and acids whereas the weak acids we use the Ka like u have explained in your slide in the green box in 34:38 ? Plz help :) But thanks soo much for your video and for your massive hard work , your videos help me to a great extent :)
@stardreamix7864 ай бұрын
yeah i was stuck here too, what would you say, would you say that [H+] = sqrt(Ka * [Acid] to rearrange for H+?
@willsmurf69692 ай бұрын
my goat
@jeffreylau20102 жыл бұрын
I think at around 1:50:00 there's a typo - methanoic acid only has HCOOH, not CH3COOH - but it doesn't matter for the calculations right?