Leah you are saving me once again. You were my #1 source in undergrad for organic chemistry 2 and literally helped me get an A in that course. I am now studying for my MCAT and for a biochem class coming up this coming semester. I knew I could come to you for clarifications. Thank you so much for everything!
@Leah4sciMCAT4 жыл бұрын
Oh wow, so glad to hear my resources helped you with orgo, and I'm honored to continue to be a part of your journey!
@masheerulhaq24674 жыл бұрын
Watched all the amino acid series.. absolutely awesome
@Leah4sciMCAT4 жыл бұрын
Glad you enjoyed it!
@ameen-45275 жыл бұрын
Thank you. Revisiting these basics helps me a lot with my undergrad project
@Leah4sciMCAT5 жыл бұрын
I'm glad I could help!
@devvinayak58582 жыл бұрын
Leah you are good teaching language you have very simple language for teach us. Thanku
@Leah4sciMCAT2 жыл бұрын
You're welcome!
@PanPan-km5ip2 жыл бұрын
Hii miss, thank you for the video, it's really really helpful!! :) I'm very grateful that I can find your channel.. Miss, if I may ask.., in the end of your video, you gave an example if the reaction go with an acid (H3O+). The H2O atacks the C carbonil, and the one H make a new bond with N. But the result, the C carbonil only change into R - COOH form, my question is why doesn't it make R - COOH2 form..? I'm confused because the molecule that attacks C carbonil is H2O which it has two H, then why in the result, there is only one H (R-COOH), not two H?? I really hope, I can get your answer, I'm waiting for it :) Thank you..
@Leah4sciMCAT2 жыл бұрын
That's an excellent question! I didn't draw the full mechanism here, but another water molecule in solution would have to deprotonate the attacking water to regenerate the acid catalyst.
@lilipokey63873 жыл бұрын
Thank you! I learn many things
@Leah4sciMCAT3 жыл бұрын
My pleasure!
@zachmisch6128 Жыл бұрын
Can you explain Lanthionization?
@Leah4sciMCAT Жыл бұрын
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the MCAT Study Hall. For more details, visit join.mcatstudyhall.com/ or contact me through my website leah4sci.com/contact/
@janpaulbalsomo80074 жыл бұрын
hi. It would mean a lot if you could give me the stoichiometric equation if Naoh is used in the hydrolysis.
@Leah4sciMCAT3 жыл бұрын
Hey! The stoichiometric ratios of this hydrolysis reaction are all 1:1. Everything reacts and is produced in equivalent molar amounts.
@rupankarghosh32834 жыл бұрын
Can u pls answer this? If 2 proteins on hydrolysis gives identical amino acids yet why they are different?
@Leah4sciMCAT3 жыл бұрын
Sorry, I’m not sure I understand your question. By 2 proteins, do you mean a dipeptide containing 2 amino acids? And if it hydrolyzes to produce identical amino acids, they should not be different.
@moorthi2753 жыл бұрын
They are different because they differ in amino acid sequence although acid hydrolysis yield same amino acids composition for 2 proteins.
@faisalnoorfahim59216 жыл бұрын
many thnx...but how to draw 3 or poly peptide,,please give tutorial
@Leah4sciMCAT6 жыл бұрын
I'm sorry, but I don't offer tutoring through KZbin comments. For help with questions like this and more, I recommend joining the MCAT Study Hall. For more details visit join.mcatstudyhall.com/ or contact me through my website leah4sci.com/contact/
@judeocbus89543 жыл бұрын
wow. excellent...
@Leah4sciMCAT3 жыл бұрын
Thank you so much 😀
@back2back1356 жыл бұрын
No disrespect but a protonation on an amide would almost certainly not Happen on the nitrogen but rather on the oxygen. This is because the nitrogen gives away its lone elec pair for the delocalization in the amide and it is therefore not available for basic reactions
@back2back1356 жыл бұрын
Plus when the nitrogen is protonated the favourable delocalization can't Happen (obviously) thus having an energy loss. Clayden describes this particular phenomenon even with MO Diagramms
@Leah4sciMCAT6 жыл бұрын
No disrespect taken. Which point in the video?
@back2back1355 жыл бұрын
In 10:53 you say the nitrogen in the amide gets protonated. This mechanism is wrong. The carbonyl oxygen will be the species which gets protonated.
@back2back1355 жыл бұрын
Literature Reference for my Claims: Clayden, Organic chemistry Vollhardt, Organic chemistry Structure and Function