An Amazing Algebra Challenge | Can You Crack This?

[@pramodkumarsrivastava1651]

great

[@RashmiRay-c1y]

Given x^4+1/x^4=527, x^2+1/x^2= 23, x+1/x=5 and x^3+1/x3=(5)(22). So, x^5+1/x^5= (527)(5) - (x^3+1/x^3) = (5)(525) = 2525. Again, E=x^5+1/x^5-1. So, E = 2524.

[@АндрейПергаев-з4н]

Неверно Если (х+1/х)^2=25, то х+1/х=5 или х+1/х=-5

[@RashmiRay-c1y]

@@АндрейПергаев-з4н But x is assumed to be positive. It should have been stated at the onset but unfortunately, was not.

[@潘博宇-k4l]

E=2524.

[@shrikrishnagokhale3557]

My answer is 2524

[@Shobhamaths]

E=(x^9+1/x^6) /x^4+1/x= (x^5+1/x^5) -1=2525-1=2524👍 x^2+1/x^2=23; x+1/x=5 x^3+1/x^3==110 x5+1/x^5=110*23-5=2525 E=2524

[@shrikrishnagokhale3557]

Is it correct?

[@RyanLewis-Johnson-wq6xs]

X^4+1/(X^4)=527 ((X^9+(1/(X^6))/((X^4)+(1/X))=2524 E=2524

[@Quest3669]

X +(1/x)= 5 for +ve x .hence ?= X^ 5+ (1/x^5)-1=2525 - 1= 2524