an easy radical right triangle problem

A radical right triangle problem! Solve for c when we have the sides of a right triangle being sqrt(3), sqrt(4), and sqrt(c). Of course, we will use the Pythagorean Theorem but we have to be careful when we cancel the square and the square root.
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"Just Algebra" (by blackpenredpen) is dedicated to helping middle school, high school, and community college students who need to learn algebra. Topics include how to solve various equations (linear equations, quadratic equations, square root equations, rational equations, exponential equations, logarithmic equations, and more), factoring techniques, word problems, functions, graphs, Pythagorean Theorem, and more. We will also cover standardized test problems such as the SAT. Feel free to leave your questions in the comment!
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#justalgebra

[@JavSusLar]

What about an intermediate case, such that 3^x + 4^x = 6^x? Solve for x...

[@militantpacifist4087]

Have you ever done Olympiad equations on any of your channels? If not, could you do some please? Thanks.

[@Raed-lakhdar]

He did

[@thomy2562]

Interesting video to ask this question under lol

[@SuperYoonHo]

@@Raed-lakhdar yeah dont >>> 👇👇👇 ????????????? i think???

[@niconiiniconii]

love the voice crack at 0:29

[@tnkhasan]

New frontiers in euclidian geometry & algebra . You should be granted an honorary phd from stanford

[@Zenzicubic]

Cool, reminds me of radicals in algebra :) Good video, and nice problem.

[@teelo12000]

0:50 you heard it here, the Red Sea is sqrt(c)

[@RubyPiec]

I also learned from this video that the Black Sea is 7.

[@wristdisabledwriter2893]

It looks like and I might be wrong when a b and c are all square roots in a right triangle the answer for c would be a + b I mean like rt(a) plus rt(b) =rt(c) c=a+b. Correct me if I’m wrong

[@Firefly256]

rt(a) + rt(b) does not equal rt(c) (rt(a) + rt(b))^2 a + b + rt(4ab) (rt(c))^2 = c For rt(a) + rt(b) to be equal to rt(c), rt(4ab) must be equal to 0, So either a has to be equal to 0, or b has to be equal to 0

[@wristdisabledwriter2893]

@@Firefly256 remember a b and c are sides of a right triangle. I double checked to make sure I said right triangle. Regular algebra it doesn’t work

[@Firefly256]

@@wristdisabledwriter2893 You’re saying that rt(a) + rt(b) = rt(c) implies that a + b = c, which is wrong. The correct one should be (rt(a))^2 + (rt(b))^2 = (rt(c))^2 implies a + b = c

[@wristdisabledwriter2893]

@@Firefly256 your right but I was saying that solely with right triangles which means I had to square every side

[@Carlos-qz7ul]

Didactic and elegant 🙏

[@aidarosullivan5269]

Now prove that 3+4=7 without Peano arithmetic

[@user-wu8yq1rb9t]

Hello dear Teacher And ... Thank you ❣️

[@tabiatbekcisi5841]

right triangle a= sin x b= cos x c is hypotenuse c=? a^2+b^2=c^2 (sinx)^2+(cosx)^2=1 c=1 complex number a=i b=1 c is hypotenuse c=? a^2+b^2=c^2 i^2+1^2=0 c=0

[@perzeo1795]

The "lenght" of the i is 1. You need to use modulus to actually use the Pythagorean theorem. | i |² +| 1 |² = (√2)²

[@richardgratton7557]

At 1:29, « there is no controver C » ;)

[@PremjitTalwar]

What's with ball?

[@dalibormaksimovic6399]

When solution is so easy, makes you think it's wrong.

[@aldiyatmataufiq1075]

Not just like that.....the problem is you cannot take a square of root in seperate way.....you have to take that both because the equation is not deal with one number to one number....so we get the root of 3 and 4 in the same line.

[@tbg-brawlstars]

BRUH I literally thought you are gonna do some "scientific thing" and I clicked this video 🤦🏻

[@MichaelRothwell1]

Aha, this reminds me of the famous √9, √16, √(9+16)=√25 triangle!

[@Anmol_Sinha]

Got the 7³th like!

[@lasxtirien2761]

why sqrt(3) + sqrt(4) should equal sqrt (7)? (sqrt(3))^2 + (sqrt(4))^2 should equal (sqrt (7))^2 lol))

[@musicforeveryone7960]

C=7

[@lorenzomarabini6200]

what about square root of square root of 3 squared + square root of 4 squared?

[@Monero_Monello]

if you mean sqrt((sqrt(3))^2+(sqrt(4))^2) then it's still sqrt(7)

[@prod_EYES]

That's basically 3^(½) + 4

[@Bestmix22]

Why you always hold the pokeball lol

[@undsamuel]

I didn't understand why to explain sqrt(3)+sqrt(4) is not equal to sqrt(7). It's like explaining that 3+4 is not equal to 5...

[@kirllosatef1522]

Yeah me too didn't understand why he did this!

[@jimmyaesthetics6942]

its his just algebra channel which is very basic, if you think you are way too over leveled for this check his main channel or other advanced channels, this channel is important for starters like us who dont know anything

[@SuperYoonHo]

Wow that was awesome!!!

[@zotungaesthete5189]

I got 5

[@SuperYoonHo]

u should wait a min... 3 mins later... hmm you should make just geometry

[@niceguy999918]

Ok so I just add 3 and 4 and get 7?

[@aasif7258]

if √3+√4 is not equal or greater than √7 then these three sides won't make a triangle.

[@MichaelRothwell1]

√3+√4 is not equal to √7, but it is indeed greater than √7, so we do get a triangle. Proof: (√3+√4)²=3+2√3√4+4=7+2√3√4>7 So (taking the non-negative square root of each side), √3+√4>√7. Of course, this result and proof work for any (right-angled) triangle with sides √a, √b, √(a+b) where a, b>0.

[@lainardj2906]

@@MichaelRothwell1 I have never been this confused because when I used calculator √3+√4>√7 but according to your proof (which is correct) this is false why?

[@lainardj2906]

Oh nvm I got it the hypotenuse is always greater than the sides not the sum of sides.

[@chritophergaafele8922]

😂😂😂 the red c

[@willie333b]

7

[@nurrohmadi7852]

ix=9 solve for x

[@8ubb1egum]

10

[@white9763]

x=9/i

[@sharufun209]

Don't try to fool others. Take geometry box and draw a right angled triangle with base sqrt4 and side sqrt3 and join the hypotenues and measure it and then say whatever you want. Don't make jimmicks with numbers. First understand the rule and talk.

[@NawabiSigma]

What's that thing in you hand?

[@militantpacifist4087]

Poké ball. Alakazam is controlling him from the inside of that Poké ball.

[@DudeBroVideos]

Technically supposed to be a microphone but he has a pokeball cover over it

[@panachaiklaemonkol5669]

that’s pokeball everyone know that thing

[@NawabiSigma]

@@panachaiklaemonkol5669 I know that bro

[@sayansarkar5878]

Why you have a pokeball in your hand?😚😅

[@ThatSword]

I still don't understand what's neat about it...

[@BulentBasaran]

start with the simplest right triangle: a=b=1. Then c=✓2 Next set b=✓2. Then c=✓3 Next set a=✓2 and b=✓3. Then c=✓5 Likewise, we can get to the square root of any integer just by drawing such triangles. I find that neat, too.

[@ThatSword]

​@@BulentBasaran wanna see another cool thing? take a = sqrt of 0.5 and be = sqrt of 0.5. and c=1. you can basically do it to any square root and there is nothing really special about it, maybe it's just me idk but i had that idea already a long time ago in my head and it didn't really suprise me lmao

[@BulentBasaran]

@@ThatSword Now you know why some find it neat: it is a new idea for them. And that knowledge is a new idea for you. Isn't it?

[@ThatSword]

@@BulentBasaran imma be real with u, it's not really a new idea for me haha

[@BulentBasaran]

@@ThatSword I understand. It's easy to forget ;-)

[@niceguy999918]

The c would be 4 because it is the same length as the line with the 4. Why is the short line a 3?

[@sunnywang4582]

this is wrong answer is 5

[@lukepeeroo5737]

Type it in a calculator root 4 squared + root 3 squared and then square root the answer

[@dimitriskontoleon6787]

By far the easiest problem you have slove. Come on...

[@vivada2667]

hello dimitris