I have 1 cookie and i want to split it evenly between 0 people. Wtf i dont have anyone to split it with that makes it undefined

thanks

Ugh I wish I had you as my algebra and calculus professor! You explain everything so well: as someone interesting in science pedagogy, it’s so nice to see 🔥

1:44: tan⁻¹ (“inverse tangens”) isn't good, because it could also be interpreted as 1/tan, which is cot. Better use arctan (“arcus tangens”) instead. “arctan(inf)” is actually your input in WolframAlpha to get 90° without using superscript signs.

"There was $1 in a room, and everyone in the room split the money. Not a single person was in the room. How much money did everyone get?" Ta-Da!

A : 99 mod 100, so 3 mod 4. Not a square. B : squares cannot end with 3 in base 10. C : maybe ? D : see A E : ends with an odd number of zeroes : not a square So C is the correct answer

bro said "thats just life" what has he gone through 😭😭🙏

I think you made a mistake in „happy“ sequence for 6…. 29 Is 85, not 40…..

Saw the 25 and thought it was the best option.

The solution is so dumb (x-1)² is always positive so it is not a value we care abt (assuming he is talking abt real numbers since he drew a numberline when doing the solution) so that implies that (X+1)/X >0 Then u can quickly discuss (x-1)=0

Can I get a proof or something that squares can't end in 3? Bc hand waving it as "try and find a counter example" isn't really satisfying

16 and 9

You should mention the result of the care-number-analysis is only valid because (x+1)(x+2), as a function of x, is continuous.

so -1±i√3=2 ?

I know this may sound stupid But technically every number can be expressed as a²+0² So all of these could be the answer Also what if the numbers are like- (Sqrt15)²+(1)²= 16 Thus the question is totally wrong and illogical. Some conditions such as a should be a non zero integer etc should be applied

-2.

This is actually a horrible question!! A young pupil with no idea about divisibility by nine and important knowledge about squares, just chose c because it ends in 225 which is a square!!!

Неужели все америкосы такие? Дискриминантом легчайше решить, зачем в какой-то таблице всё усложнять 🤦

t-shirt: =1/4

Aaaand, who says that multiplying 2 'negatives' makes a positive (multiplying 2 'positives' also makes a positive, lol) .....or that infinity exists, .......(or that adding the same numbers to two piles of any substance in the world will have the exact same effect, making the 'equal' sign a reality in the first place)? Math is a social construct and a social contract in ways. It's meant to give its students a sense of balance and fairness in the world. Teaching kids about spark gaps that increase electricity by 1000's of times by just adding air seems more beneficial, but, .....I lost hope in 'math' long ago.

If you believe they put a man on the moon, a man on the moon, ....(lyrics to a song, but I writing them here to explain that if you believe that, then you've lost your child to propaganda in all its illustrious colors already).

1 isn't the same as 1^0.5. This is why people hate mathematicians.

🔥🔥🔥🔥🔥

in physics, it's simply infinity

Answer has to be C) 649,485,225 . A) 99,999,999 = (10^8 - 1) = (10^4 - 1)*(10^4 + 1) = 9999*10001 , hence it cannot be a perfect square (its square root is between 9999 and 10000). B) 123,333,333 cannot be a perfect square, because perfect squares don't end in the digit '3'. D) 713,291,035 cannot be a perfect square, because perfect squares don't end in '35' (the square of an integer that ends in the digit '5', will end in '25'; the square of an integer that doesn't end in the digit '5', won't end in the digit '5'). E) 987,654,000 cannot be a perfect square, because perfect squares don't end in an odd number of 0s. Verifying that C is indeed a perfect square: 649,485,225 625,000,000 = (25,000)^2 ------------------- 24,485,225 / 50,000 = 488 ≈ 500 (25,500)^2 = (25,000 + 500)^2 = 25,000^2 + 2*500*25,000 + 500^2 = 625,000,000 + 25,000,000 + 250,000 = 650,250,000 650,250,000 649,485,225 -------------------- 764,775 / 51,000 ≈ 15 (25,485)^2 = (25,500 - 15)^2 = 25,500^2 - 2*15*25,500 + 15^2 = 650,250,000 - 765,000 + 225 = 650,250,000 - 764,775 = 649,485,225 ==> 649,485,225 = (25,485)^2

so arctan( undefined ) = pi/2, got it!

If the independent term has too many factors, this can be quite hard, as you must check every combination of two factors 4 times each, as they can also have switched signs and switched places in the cross. The solution of the system of equations is a=(Ac-C)/(c-d) and b=(C-Ad)/(c-d). A and C are the coefficients of x^3 and x, and c and d are the top and bottom numbers at the right cross which are factors of the independent term. Substitute directly into a to eliminate more quickly those in which a is not a in integer. If a is an integer, obtain b and check the last condition

you should be able to calculate whether useful quantum computers will ever be developed....the limiting factor is noise and we know how much noise there is and how much each unit of noise reduces quantum integrity with respect to accuracy.....it should be a straightforward matter to compute whether noise will ever be sufficiently mastered to permit reliable useful quantum computing beyond the toy stage

Thanks to BPRP, this guy is now a meme, and in so doing, has thusly achieved internet immortality!!

L(z) = a(1)z + a(2)z^2 + a(3)z^3 + ... = ∑(n=1 to ∞) a(n)z^n L(z) = z + L(z^1 + z^2 + z^3 + ...) = z + L(z/(1-z))

It seems to me like: it is wrong bcause is wrong..

I'm totally disturbed by the way you solved that quadratic equation. I'm so used to X1,X2= (-b+-sqrt(b^2-4ac))/2a.

😵‍💫

Say the price of gas is $5/gal and you have $100, you can buy 100/5=25 gal of gas. If the price is $1/gal, you can buy 100 gal. If price was $0.50/gal-->200 gal, but if gas is free, ie. $0/gal, that $100 can buy an infinite amount of gas and you'd still have the $100, therefore undefined.

special pleading

No wonder most kids hate maths! Its just bloody so twisted!

Why can’t you get X^2 - x > 1 - 1/x ?

Why can’t you get X^2 - x > 1 - 1/x ?

2:30 why do a and b need to be whole numbers? Is there a rule for that?

So this is very basic. When you use a square root you have to outcomes, positive and negative. So if you multiple -1 per the negative you get 2=2

What

sqrt(k*1000) can give a perfect square for k=10

Norte americanos sao estúpidos, olha o tipo de discussão q eles tem. Falar q um professor deveria ser demitido ou até mesmo trocar a criança de escola por uma discussão sem sentido e q nunca vai ser posto em prática

Dont care about anything except for how he explained moving x from right part of the equation to the left part with the opposite sign 😭

Hello. I’m trying to get super smart but I don’t know where to start, can someone help me out?

You little...... You just made my easy going mind full of un-necessary possibilites about solving a single F***in problem. Now I cant unwatch this thing

I followed the same approach but just let √x be a and √y be b for ease

(x−1)(x−3)(x2−2x+4) by long division

X^6............. then (x^6........)(☠☠☠☠☠☠)

It doesn't work for sqrt(-i * -i) either. What's the general rule - when does sqrt(ab)=sqrt(a)sqrt(b) ?