An Interesting Log Equation

[@omsonar7219]

Just put x=1/2 and y=1/2

[@morixesjehsnkigsbn]

😃😂😂

[@yashmishra1391]

Yu need to give general solution

[@sandhuekam14]

Baaki soln?

[@sumitdas2385]

Inke muh pe ek chappal mara Jaye plz....@Om Sonar.......yha jee and Olympiad ke aspirants aate he Govt school ke bache nhi

[@sumitdas2385]

R.H.S 0 ho jayega gadhe........

[@PS-mh8ts]

Perhaps it's easier to express x in terms of y as follows: x+y=x/y gives xy+y²=x Transposing, we get: x=y²/(1-y) In parametric form, this can be (t²/(1-t), t) Because x has to be positive (because we should be able to take log x, and log x is defined only when x is positive), we must choose for t a positive value less than 1. A sample: y=1/3 x=1/6 (when t=1/3) There are infinitely many solutions.

[@jagadeesh4869]

Here you are giving -ve values for 'y' which isn't possible

[@ashu5404]

​@@jagadeesh4869 how?

[@jagadeesh4869]

@@ashu5404 sorry my bad, I read that less than 1 as less than 0

[@slimshadyff7848]

Bro you just ruined it 😩❣️

[@ashu5404]

@@jagadeesh4869 ok , no problem

[@imsounak19]

For this special eqn we get for any value of x y is in the form φ-1( k) for some constant k For ex if x = 4 means k= 4 y= φ-1(4) We can say this because for x= 1 y= √5-1/2 or φ-1 How cool is that!!

[@byomkeshbiswal3666]

I have a question Le O(0,0),A(6,0) and B(3,root3) be the vertices of triangle OAB.Let R be the region consisting of all those points P inside triangle OAB which satisfy d(P,OA)=

[@Arnav2322]

I followed the below steps:- Log(x+y) = logX -logY Assuming X = 1, y = 1

[@IsolveProblems-jb4uk]

So you mean 1+1=1? Very good

[@Motivation_Quotes5731]

Nice video🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉

[@rohitbharti1183]

Sir mja a gya,Thank your sir 😁😁

[@darshans672]

pura video dekha bhi hai tune

[@rohitbharti1183]

Bhai oye pura dekha h tbhi to bol ra hu.aur tu mujhe kya bol ra h tu to pehle pura dekh namune

[@anmolgupta5539]

Ese hi videos ke liye hi to channel Subscribe kiya tha 🔥🔥

[@systembosska]

Magician is back with new magic 😇

[@uttambaba-sx1km]

Sir aap nda ke Imp chapters ka basic se Kara Dijiye please...dar LG rha h....2D,3D, vector, probability and statistics bs itne chapters Kara Dijiye please sir🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@aamanali3464]

Sir higher mathematics ki video banaye.

[@syedmdabid7191]

There's far difference between an identity and an equation. Log( m×n) = log m + log n ( An identity or formula) but Log(m+n) = log m ---log n( An equation)

[@ronak3990]

Badiya 👌👌👌

[@Shortnote6299]

Sir koi series start kijiye, iit jee walo ke liye

[@abcdjain6850]

SIr I would be entering class 10 this april, you teach really good. I go to allen. I will top after seing your video :)

[@rithwikrajasekhara1524]

can we use taylors series to find a solution and use the implicit functions differentiation for just finding the value of loge x + y ?

[@03abhadilipdas94]

lmfao that’s so stupid it became funny

[@TechToppers]

That's an interesting method, but I don't think its worth a shot... First of all you will issues with radius of convergence for the taylor series since taylor expansion for natural log isn't convergent for all values of x. This is just a rubbish method in my opinion. Just focus more on log properties...

[@sukhmanpreetsingh9537]

Sir make a video on mock theta function (introduction)

[@varun1702]

Sir please upload videos of questions of JEE advanced level thinking 🙏✍️

[@SameerKhan-bi7wo]

Mind blowing questions 🥰🥰

[@milindsarkar6961]

Maza aga aya sir. Thank you.

[@honestadministrator]

x + y = x/y A trivial solution is x=y = 1/2 In general x = k y y (k +1) = k, y = k / ( k+1) , x = k^2 /(k+1), k is not 0

[@arghamaji8234]

It is the same as: X+Y=X/Y 1/2 satisfies this.

[@6055shivanshtekam]

Multiply both side by zero

[@syed3344]

💀

[@shamsunnesha4570]

Sir logarithmic and exponential series par Ek video

[@vaibhavjain4066]

Sir why y can't be negative?

[@vikashkumar96314]

Wah wah irskad

[@dixit....family...wonders110]

Sir pls bring KBS again Kaun banega Shaharyaar💖💖

[@shubhidixit909]

Yesss sir pls

[@nishantpanda848]

Sir boards ke liye series laaiye na🥺🙏🏻❤️

[@ujjwalghosh389]

Thank you sir

[@lalikantkumar-vz9cm]

Sir Aap Bsc ki maths prasandhaiye please

[@ABCDEFGH4567-8]

This equation has also unique integral solution. x=-4 and y=2

[@ABHIGAMING-yo9my]

Log me negative nhi aata

[@AniketKumar-lw6su]

@@ABHIGAMING-yo9my If we go in the complex world then it is a solution

[@ABCDEFGH4567-8]

@@ABHIGAMING-yo9my in complex analysis , solution of this expression exist.

[@adityamanohar2564]

Love your videos sir❤

[@gamerverse3405]

Sir please upload regular video of class 12(new video) for 2023 24 board

[@kushagrakatarexi-arn682]

Sir bring the big problem that you were solving please 🙏 🙂

[@siddharthsingh9386]

Thank you

[@adilrizvi9077]

Thanks

[@bhargavgarah2006]

Any no.s x=p²/(1+p) y=p/(1+p) where x,y are not integers

[@TechnoCoderz369]

X=0.73 Y=1.98

[@changethiswhenyouareok]

Sir make a video on zeta function

[@avinash_mrj]

Sir there is a question for you pls make a video on it question [ the length of the circumference of a circle always bear a constant ratio to its diameter] pls sir make a video on it 🙏

[@niraliniranjan2372]

Usi ratio ko pie kehte hai

[@g.d.243]

Sir x=y^2/1-y. Hoga ya nehi hoga

[@g.d.243]

Isse bhi ta qs solve ho raha he (from 3rd raw of the solution).

[@g.d.243]

?

[@hindgamer5880]

Mja aya❤️❤️

[@niteshchandra2796]

Another simple approach: log(x+y)=logx-logy=log(x/y) This will be possible if, x+y=x/y x>0 ( as log is defined only for positive real numbers) y>0 (as log is defined only for positive real number) If x> 0, y>0; x+y>0 Let's look at equality first, Assuming there exists x and y belonging to real numbers, that satisfy the equation, Then there exist a real number k such that: x+y= x/y=k That means x= ky And x+y=k That means ky+y=k Or y=k(1+k) Further, x=ky=k^2/(1+k) Hence, solution of equation x+y=x/y : For any real no k, (x,y)=(k^2/(1+k), k/(1+k)) Let's take cares of inequalities now: for y>0, k/(1+k)>0 I.e k>0 or k 0 k^2/(1+k)>0 I.e k> -1 Hence for both x,y>0, k>0 Hence solution of log(x+y)=logx-logy: (x,y)=(k^2/(1+k),k/(1+k)) where k is a postive real number

[@bluexwave5930]

Y= -x±√x²+4x/2 (x, y) >0 √x²+4x > x So Y= -x+√x²+4x/2

[@mrnovaxindividual-11]

Sir Ap Please Arihant or Cengage Full Book Solution Series Start Ki Jiye🙏🏻🙏🏻

[@ishikashaw209]

Sir put x -4 and y 2

[@nilaybhostekar1074]

Sir good question

[@syedmdabid7191]

Log (m + n) = log m--- log n ( An equation)

[@prakharverma7115]

Sir aap toh apne pyaar ho

[@soumyadeepBindhani...]

Sir , bohot bodia

[@yash1826]

X should be greater than 1 as well

[@rajneeshyadav4001]

1st to watch ❤️

[@monujhembrom9279]

Wa wa😂

[@walkerwalker8895]

I was able to solve it !!!!!!!

[@Flame_6969]

5:19 correction √x²=|x| not x

[@HarshSoni-yn2jy]

😊

[@amitkumardas6703]

If x0,0

[@Vip.cx2]

X=y= 2n/4n n belong to N

[@Aniruddha_can_solve]

Which book

[@Ratneshkumar-cs3vx]

Let x=1 and y=1💀

[@drashtieducationchanderi-Dsl]

Sir mujhe aap se math padna hai offline sir main mp se hoon main mptet grade 1main disqualified ho gaya mere 73no hain 2no se rah gaya mujhse logon ko kafi ummiden thi lekin maine sabko nirash kiya hai ab main kafi dipression main aa gaya hoon mujhe mathematics ka teachar Banna hai plaesr sir meri help karen main jeevan bhar aapka abhari rahunga

[@rinijn]

First comment

[@2fingernoobgamer806]

X,y=0

[@chandrabhan0311]

🌹🇮🇳🙏🙌

[@syedmdabid7191]

It's ain't an identity. It's an equation.

[@mukulrana6754]

Sir boards le liye kuch krdo 11 ko board hai 😭

[@nikhilmahajan3044]

Sir jaldi apne hair badhao aur aajao munna bhai ke style mein😎

[@yashjaunpur]

Sybermath copy

[@dishantjain8723]

Why sir look like @thugesh to me

[@mohammadirfan219]

Kya timepass kar rahe ho sir

[@sanjayadhikari7022]

Copied from sybermath you tube channel 😅

[@dj.2958]

😂

[@AdityaKumar-gv4dj]

🤣

[@AdityaKumar-gv4dj]

Syber math big fan

[@Koinhi-fj9tf]

🫡

[@aabidhussain7819]

Unnecessary question.

[@dj.2958]

your teaching stylle is not .

[@MathematicalPool]

Kahi se ek faltu ka questions utha liye jiska koi level hi nahi hai aur usko lekar itna jyada time waste karwate hai ye teaching nahi drama karna jante hai ekdum bakwas.

[@natureinitsbest6551]

Kya pagalpanti hai yeh....matlb kuch bhi

[@1971teji]

Fukraa

[@nemesiscr9966]

ye saab karke publicity gain karna chahte ho kam ki baat batao