Anagrams | Strings | EASY

[@galepraveen]

bool areAnagrams(string& s1, string& s2) { if(s1.size() != s2.size()) return false; vector freq(26, 0); for(auto& ch : s1) freq[ch - 'a'] += 1; for(auto& ch : s2) freq[ch - 'a'] -= 1; for(auto& num : freq){ if(num != 0) return false; } return true; }