Andrew Tate solves Math Olympiad problem | Beginner level

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[@MathWisdom42]

In the last problem it is x^4 not x^3 so it becomes (x^4 + 1)/x >= 2x , sorry for the mistake

[@philippepare280]

As x is strictly positive, we can multiply both sides by x, giving us that x^4 +1 >=2x^2, form this subtract 2x^2 form both sides leaving us with x^4-2x^2+1>= 0 this can be simplified into (x^2-1)^2 >=0 this is always true as x^2 is always greater then zero

[@MathWisdom42]

Good job. You proved AM-GM for two members, you can actually apply it directly@@philippepare280

[@Max-ki6df]

I was wondering because for 4/3 it's: 91/36>= 8/3=96/36 that doesn't sound correct

[@Salmanul_]

Do a linear algebra matrix question. Andrew tate talks about matrices.

[@SigmaMale7868]

😂

[@perpetualearner1]

Underrated comment fr

[@s1373r]

He talks about "The Matrix"

[@MathWisdom42]

This is happening

[@manuelrios6230]

what rank would it be ?

[@funicon3689]

this isn't just playing with numbers, it's strategic warfare

[@MathemadicaPrinkipia]

damn I actually felt like an alpha for a min😂😂😂

[@pixelpeelygaming]

Here is my attempt at solving the last problem: Multiply both sides by x so that we have: x^4+1>=2x^2 Now move x^2 to the left side such that we get: x^4-2x^2+1>=0 Split the middle term into two terms with coefficients that sum to -2 and multiply to +1: x^4-x^2-x^2+1>=0 Factor by grouping: x^2(x^2-1)-(x^2-1)>=0 Factor out (x^2-1): (x^2-1)(x^2-1)>=0 Simplify: (x^2-1)^2>=0 Since any real number squared is greater than or equal to zero, this inequality must be true for all x on the real domain. Please let me know if I made a mistake, as it is very likely that I did; I don't have very much experience with proofs and would love to learn.

[@alaeddinesabbagh7784]

That's an original way of doing it. Well done, you can actully do it in a simpler way using AM-GM for two real positive numbers.

[@MathWisdom42]

good one !

[@avdomahmutovic4039]

How did you get x^4 after multiplying by x?

[@pixelpeelygaming]

@@avdomahmutovic4039 Look at the pinned comment on the video, which states that x^3 should actually be x^4

[@cro_lok2363]

You did it wrong. When dealing with these kinds of inequalities you should check for when x is negative. You basically completely cross out that possibility. It should look something like this : (x^4+1)/x>=2x^2,(x^4-2x^2+1)/x>=0. From where you get all real positive numbers with the interval method. I apologize for my bad English

[@philosophieoverdose9332]

Hello, thank you soo much for this materiel, please can you offer more videos like that,we need it a lot , 🙏🙏 Keep going sir, my greetings

[@jameswoodcock7004]

How did the matrices find me on youtube algorithm? Just when i thought i had escaped...

[@ГалсанУчуров]

For the first provlem we can transform it to a + b^2 + b/a - 3b >= 0 We can multiply it by a since a > 0 a^2 + ab^2 + b - 3ab >= 0 Now I want to transform some part of left hand side into a quadratic form a^2 + ab^2 + b^2 - b^2 + b - 2ab - ab >=0 a^2 - 2ab + b^2 + ab^2 - b^2 + b - ab >= 0 (a-b)^2 + b^2(a-1) + b(1-a) >= 0 Now I notice that (a-b)^2 is always non-negative, therefore we have to prove that the remaining part is non-negative b(1-a) is the same as -b(a-1) which means that we have to prove that b^2(a-1) - b(a-1) >= 0 b^2(a-1) >= b(a-1) But here I have the issue because for 0

[@MathWisdom42]

@user-ee4tz1zf4o your are close but not quite there. Even though what you have done is correct, the path you took does not lead you to the answer, you have to think of something else. A direct answer would be to apply AM-GM like mentioned in the video.

[@oogabooga685]

this is a very creative and productive use of AI

[@liamk2]

I don't think I fit the target audience of Andrew Tate but if calling things "battle tools" helps people get into math, I'm all for it!

[@testx0170]

For the final problem: Rearrange (since positive) x^4+1≥2x^2, now rearrange again, and we have x^4-2x^2+1≥0, but this is trivial since (x^2-1)^2≥0 for all x, equality holds when x^2=1, hence x=1

[@MathWisdom42]

Well done!

[@alitraore1496]

Isn't the degree of the numerator equal to 3? It should be x^3+1 => 2x^2, right?

[@testx0170]

@@alitraore1496 check the pinned comment

[@keyan1219]

@@alitraore1496 pinned comment

[@ShadowReaper-pu2hx]

No wonder this guy’s always talking about matrices-he does Olympiad math.

[@richardrobertson1886]

When I looked at this my first thought was a proof by induction. Start by noting a isn’t 0. Then if we take b=0 as the base case I can see conceptually the induction hypothesis of b=n+1 could be messy, but I think it would still work.

[@MathWisdom42]

you can't apply induction on real numbers.

[@supratikghoshal5561]

AI (Andrew Intelligence)

[@user-qr4jf4tv2x]

a world where Andrew Tate is teaching math we would have flying cars

[@AyaanFarasanims]

How did you make this? Is there a text to speech website that has voices of famous people?

[@amithkumars562]

yes how??

[@redgrengrumbholdt2671]

AI

[@AyaanFarasanims]

@@redgrengrumbholdt2671 Yeah but which AI

[@ayan4167]

Since (x^2-1)^2 >=0 Because square of any real number gives a positive value. So, x^4 - 2x^2 + 1 >= 0 x^4 + 1 >= 2x^2 Now since x>0 so, (x^4 + 1)/x >= 2x At x=1 LHS=RHS

[@MathWisdom42]

Nice one ! if you enjoyed that one you must like this too : kzbin.info/www/bejne/nIqul2ine82qY6c&lc=Ugy3FxscSnwsNDweOKV4AaABAg

[@husnimuttaqin4636]

when andrew see this. "GEEKS BRUH" 🤣🤣🤣🤣🤣🤣🤣🤣🤣

[@adamazouar]

AI is getting scary

[@iftekharalambhuiyan5457]

Thanks Mr.Tate

[@NobOdy-zg9so]

Blud does NOT know that a and b should be positive real numbers to apply AM-GM🙏🙏😭

[@alaeddinesabbagh7784]

good point, but it was mentioned

[@Wilhelm-mg1jf]

Bro that's what literally what was in the problem

[@Wilhelm-mg1jf]

Bro that's what literally what was in the problem

[@abhirupkundu2778]

? are u blind

[@kth333]

Bro that's what literally what was in the problem

[@bilalkhares4932]

Ngl this would probably get kids interested.

[@Derek_Bell]

Andrew Tate wouldnt know what an implicit variable was if it fell for his cam girl scam

[@ashutoshganguly1805]

how did you make this?

[@Klarpimier]

Andrew Tate finally using the one braincel he has

[@ayan6535]

Why did it took me to solve it in 10 sec 😂... Sorry I m an indian

[@martincichy9495]

The wisdom of artificial intelligence.

[@kylebroussard5952]

*I love the internet ❤*

[@ryang7759]

not bad for a guy who doesn’t read books

[@CuriousCyclist]

If g was a numerator, it would be..

[@MathWisdom42]

top g !

[@NoumenalSoup]

"Arithmetic" as an adjective should be pronounced differently.

[@centryll1313]

00:01

[@yvngrxxd9078]

can we not do this just by deduction?

[@MathWisdom42]

what do you mean?

[@tamasburik9971]

This is incredible

[@HowardARoark]

That was cool !

[@tharunsankar4926]

Based

[@nephronpie8961]

Like this Andrew Tate better

[@mathophile1912]

Shame on the audience that they give more views to a math video involving the name Andrew Tate rather than Ramanujan

[@arkoarko9559]

First time on Internet? Jesus.

[@bool1337]

where are ramanujan ai dubbed videos?

[@JashDoshi]

sounds ai

[@ryannoonan5518]

No intonation though. But accent is decent Ig

[@IntisharIftiHashem]

isnt this ai

[@arthurgold7239]

So funny, aren’t you data scientist ? 😮

[@miro_gra2706]

das crazy

[@ClutchBankz]

Sounds like Ai

[@ohiorizzler1434]

andytate the ohio rizzler! such a sussy baka, from ohio!!!

[@finmat95]

That's why i hate math.

[@sabbirahamed7902]

Fake voice... Made by AI...🙂

[@indiefansexplode]

Andrew Tate is a weirdly good math teacher

[@PlanetNumeracy]

haha

[@paulthompson9668]

@@PlanetNumeracy I love ChatGPT

[@21.huulinh11]

we got Andrew Tate solved a Math Olympiad problem before gta6

[@io2068]

Ai is insane😂

[@io2068]

@iro4201 shut up.🙄 . Go live on mars.

[@radMisc]

if you thought his "Real world" discord was fire, wait until you see his "Real numbers" one

[@ArokSam]

AI Andrew tate

[@Simon-fu8sd]

No this was actually him! are you dumb?

[@davidc4408]

Hiw they do this AI with Andrew Tate voice?

[@_comrade_ivan_]

My idea of the solution. a + b² + b/a ≥ 3b can be transformed to ab² + (1-3a)b + a² ≥ 0 a>0 and b>0, so ab² > 0. Also, a²>0. If (1-3a)b would be ≥ 0 also, then the sum ab² + (1-3a)b + a² would be ≥ 0. But (1-3a)b≥0 only if a≤1/3. So I decided to determine under what values of _a_ this polynomial is ≥ 0. Consider ab² + (1-3a)b + a² as a quadratic polynomial with respect to b. If the polynomial is ≥ 0, then it has 0 or 1 root (not 2), therefore its discriminant is ≤ 0. D = (3a-1)²-4a³ D = -4a³ + 9a² - 6a + 1 So, if ab² + (1-3a)b + a² ≥ 0, then D≤0 -4a³ + 9a² - 6a + 1 ≤ 0 The usual strat for solving 3rd degree polynomial equations is to guess one of the root, which, in this case, is conveniently appeared to be a=1. Then use long polynomial division to factorize that. -(a-1)²(4a-1) ≤ 0 a∈[0.25;+∞) So. If a∈(0; 0.25), then ab², (1-3a)b and a² are positive, therefore their sum ab² + (1-3a)b + a² is positive. If a∈[0.25;+∞), then ab² + (1-3a)b + a² has 0 or 1 roots, therefore ab² + (1-3a)b + a² is positive for all values of a,b or negative for all values of a,b. You can check that by randomly testing one of its values. For example, if a=2 and b=2, ab² + (1-3a)b + a² is 2. Therefore it's positive ∀b>0 and a≥0.25.

[@_comrade_ivan_]

I've realized that it's too complex when 70% of this comment was done 😅. Finished it bc just didn't want that time to go to waste.

[@j.kl8903]

do you study math@@_comrade_ivan_

[@Bangaudaala]

I mean, cant complain, im literally learning Polynomials rn

[@animalnt]

the andrew tate teens needed

[@even6978]

the good ending andrew tate

[@umariqbal7557]

Nahh, how is this andrew tate more charismatic and wise than the real one?

[@ManjulaMathew-wb3zn]

(x^2-1)^2>=0 x^4-2x^2+1>=0 x^4+1>=2x^2 Since x is positive dividing both sides by x doesn’t change inequality. (x^4+1)/x >=2x and equality happens when x=1

[@saileshkumarsaila5241]

casually you are watching tv, reading novel or playing suddenly you come to see this question a+b^2+b/a_>3b does this maths makes any sense our education system support to understand anything properly?

[@thebizzarepotato5169]

perfect

[@dadu6711]

if this is begginer level then im fucked

[@bobmichael8735]

How do you use Andrew tate's Voice?

[@MathWisdom42]

Check Mr beast working on a math Olympiad problem : kzbin.info/www/bejne/r5jPY2dmjpiboNk

[@srinivasvijaybabu8912]

Just make it x^3+(1/x)>=2x and by Am-Gm,( x^3+(1/x))/2>=sqrt(x^2) which means that x^3+(1/x)>= 2x and equality holds when x^4=1 which means x =1.

[@soyalguien335yt4]

x^3 + (1/x) is not equal to (x^3 + 1) so your solution is not true. Multiply both sides by x (x is not equal to 0) and you get x^3 -2x +1 >=0, you can get the roots of the equation by using rufinni with x=1 and the second grade equation formulla. You get that that equation is negative between the interval of 1 and 1.618, you can verify that if you put x=1.1 on the original question, it is not true

[@josecarlosferreira4942]

Warriors of wisdom 😂😂😂😂

[@rajatavaghosh1913]

AI generated...Fake :)

[@doyathink49]

is this AI generated?

[@pauselab5569]

the solution feels a little random though it is probably what you are expected to use in a math test especially considering that AM-GM inequalities are taught in school. a more intuitive solution: divide by b since b>0. a/b+b+a>/= 3 now we use the partial derivative test to find the minima. set both to 0, solve and you get the same answer.

[@Lolwutdesu9000]

Except it's a/b + b + 1/a, champ.

[@archangecamilien1879]

Isn't this false if a=-2000 and b=1?...Lol...I mean, or I'm just miscalculating...

[@MathWisdom42]

check the pinned comment, it says : it is x^4 not x^3 so it becomes (x^4 + 1)/x >= 2x , sorry for the mistake

[@Matthew_Ssali]

Nice ai

[@words007]

I know for a fact chess grandmaster MMA fighter and internet (CONTROVERSIAL 😂😂) personality Andrew Tate is not remotly aware of mathmatics but AI is master of us all this video kinda prpves it.

[@JeanNepoMunezero]

I laughed alot

[@deependrasinghis_ronaldo]

which AI tool are you using ? can you create one like Robert Downey Jr. is solving this ?

[@hedu5303]

Wow!! I am pretty impressed

[@erlandson3141]

He better mention the Hoffman paccking puzzle.

[@lordsneed9418]

lol

[@Playerone1287]

Lol

[@JoseManuel-is4yc]

Where’s that next video? I find the inecuation shown at the end is wrong

[@alaeddinesabbagh7784]

check the pinned comment, it says : it is x^4 not x^3 so it becomes (x^4 + 1)/x >= 2x , sorry for the mistake

[@gauravbharwan6377]

😂😂😂awesome

[@Toto-cm5ux]

Why Andrew Tate? It's cringe 😬