@@contentlacking5950why is it called orange juice? It's not yellow at all, it's orange.
@pjmmhe Жыл бұрын
How exciting indeed
@nadavegan9 ай бұрын
I am not a math person, but I love Andy's attitude and could watch his videos all day.
@shivakrishna47548 ай бұрын
You are not a math person that's why you don't know why he took so much time 😂😂
@thisidiot43705 ай бұрын
@@shivakrishna4754 what is bro yapping about
@supayambaek9 ай бұрын
GOOD GOD, EVERYTHING WAS A TRIANGLE ALL ALONG
@A_Loyalist7 ай бұрын
Always is.
@Tasarran7 ай бұрын
@@A_Loyalist Always was...
@Heronoobie7 ай бұрын
Always has been.
@AshKash1576 ай бұрын
Always will be...@@Heronoobie
@epic_divyanshu9 ай бұрын
the type of questions you bring perfectly match my grade level. thanks. i can solve some tough probs now
@detroitstudios3979 ай бұрын
which grade r u tho?
@epic_divyanshu9 ай бұрын
@@detroitstudios397 10th India
@detroitstudios3979 ай бұрын
@@epic_divyanshu well im 8th india
@epic_divyanshu9 ай бұрын
@@detroitstudios397 nice. icse?
@itachu.9 ай бұрын
I'm in grade 12 , can't say about the calculations but the observations are really good
@leoncromwell14426 ай бұрын
bro is so underrated, keep up the good work man appreciate it a lot
@c.jishnu3783 ай бұрын
For the people who are wondering, If you look at the point of contact between the green circle and the 36circle's circumference, there can be a perpendicular radius of the green circle drawn there. There can also be a perpendicular radius of the 36circle that can be drawn, since both are perpendicular to the same point, they coincide. I got this after a while of thinking and my brain is now tired.
@francescomusica2 ай бұрын
I was wondering exactly for this explanation, than you!!
@hcgreier60378 ай бұрын
Nice problem! I took a general approach to get R for arbitrary half circles with radius r. It goes as follows: x² + R² = (r-R)² x² + R² = r² - 2rR + R² → x = √(r² - 2rR) y² + (r - R)² = (r + R)² y² + r² - 2rR + R² = r² + 2rR + R² y² = 4rR → y = 2√(rR) Now as y = r + x, we get 2√(rR) = r + √(r² - 2rR) 2√(rR) - r = √(r² - 2rR) 4rR - 4r√(rR) + r² = r² - 2rR 6rR = 4r√(rR) |r>0 (6/4)R = √(rR) (3/2)R = √(rR) |² (9/4)R² = rR |R>0 (9/4)R = r therefore R = 4r/9 In your case r = 18 (half of 36), so R = 4·18/9 = 8
@neelabhjodutta27596 ай бұрын
Yeah Generally it might be a bit hard to understand but it is simpler if you understand your terms!🤌🏼🤌🏼🤌🏼
@lukerdill14759 ай бұрын
Man I love this guys videos! Stumbled upon them a few days ago now I cant stop lol
@mhwlasagna8119 ай бұрын
I wish you were my math teacher, you are so patient with the explainations and it is crystal clear, thanks !
@mandah05209 ай бұрын
I always liked math and it was the one subject I was good at in school but it has been years since i sat down and solved a math problem. It was fun to solve the problem along with you. Subscribed
@BenDRobinson8 ай бұрын
This puzzle was fun for me because - seeing all those tangent circles - I went off and did it with a circle inversion, which I always think is such a beautiful trick when it works. Although TBH it didn't magically make this into a quick easy problem.
@muriloamorim27317 ай бұрын
What is a circle inversion? edit: ok i looked it up and it's really cool. Thank you for commenting that. One more question: Your inversions were based on what circle? I imagine you defined a new circle with center on the bottom left corner and radius equal to 36.
@BenDRobinson7 ай бұрын
I was hoping someone would be curious enough to learn about it! It's pretty unusual to get a chance to use it, but it's nice when it does 'cos it's so neat@@muriloamorim2731
@tiagoloprete7 ай бұрын
@@muriloamorim2731 i'm curious too, hoping we'll get an answer :p found out about inversion today and spent half an afternoon learning about it
@muriloamorim27317 ай бұрын
@@tiagoloprete It's a really nice concept, isn't it? Very fun to play around with. Glad you also enjoyed learning it! Did you try the inversion i suggested (based on a circuference centered on the bottom left corner and radius equal to 36) or any other inversion? With the inversion i suggested it was relatively easy to show that the distance between the bottom left corner and the leftmost point of the green circle is 24. Let me know if you agree/disagree or if you need help in any way with the inversion. One last thing: your name sounds Brazilian.. are you? (I am)
@barryomahony498329 күн бұрын
This was a good one. I was going down the same road with the two triangles and it was getting ugly, so I was thinking maybe it wasn't the right approach. Then I played the first few seconds of the video and you said it was a bear, so I just put my head down and pushed through. For semicircles of arbitrary radius A, the solution is R=8A/18.
@aa1ww3 ай бұрын
Thanks for the work you put in to fashion each clear and concise attack you document. You're doing very good work indeed.
@oscarcastaneda53105 ай бұрын
Hola Andy, It can be shown that for any such figure exactly 4.5 R's constitute the length of the given radius. From this we have that the length of R is 36/4.5 = 8. Thank you so much for this problem which provided a rough challenge from the directions I took. The challenge plus you enthusiasm are much welcome in problem solving departments in education these days : )
@amiryavand Жыл бұрын
It was great, Thanks for solving these kind of problems 👍
@maantjemol Жыл бұрын
How exciting! Where do you find these problems?
@b5fremdet9 ай бұрын
I wanna know too!
@mrbutish9 ай бұрын
Math books, math guides, 8th grade onwards, try IMO olympiad guides as well
@johnneri36468 ай бұрын
His website
@jasperg997 ай бұрын
I would love to know your process of thinking of a way of solving. Itd be great if you can explain how to approach these mathematical problems!
@matthewkendrick82809 ай бұрын
I feel how my classmates feel when I explain something and they say “I don’t understand”
@mkbismuth8299 ай бұрын
Where the f do you get these beautiful questions????
@ianmoore55027 ай бұрын
True
@charliebirdnba6 ай бұрын
Loved the ending thought process! Great work
@jerrypolverino60256 ай бұрын
This took me a very long time. I finally got it although I went around and around in a very convoluted solution. Your method was far more simple than mine. Please explain slower! I have trouble keeping up with your explanations, and it’s hard to stop the video at the right moments. Please pause a little between operations. Please! My age is the square root of 5,929.
@kenhaley43 ай бұрын
Hey! Me too! 1947 was a good year, huh?
@aa1ww3 ай бұрын
You might consider a youtube feature under the gear icon where you can slow the video down to half or even a quarter of speed without changing the pitch of the voice (it's really an amazing algorithm, i.e. "phase vocoder" .... isn't that exciting). Apologies if you were already aware of the availability of this feature.
@artemis51684 ай бұрын
I feel like I should be eating handfuls of paste after watching this. I stared at this for 20 minutes trying to get somewhere, and Andy explains it in less than 7 minutes. If I ever feel the need to feel dumb, this is where I come.
@nghialam16819 ай бұрын
Where do you get these interesting geometry problems?
@mudetz7 ай бұрын
As an engineer I can confidently state that R < 36
@brelocks7 ай бұрын
on 5:40 you could divide both sides by 9R to get 8=R
@vgetters36839 ай бұрын
U deserve a lot subscribers Keep going
@Antiwasserstoff8 ай бұрын
Love these videos. I subscribed, its worth it
@TheAmbiguousMice9 ай бұрын
Tried to think of a solution in my head: Couldn’t 💀
@Tasarran7 ай бұрын
I did know we were going to be constructing triangles, does that get me any points?
@homayoonalimohammadi90788 ай бұрын
When you did draw a line from the center of the left semi circle to the collision point of the green circle and the left semi circle, how did you guarantee that the line crosses the center of the green circle?
@GaneshNayak8 ай бұрын
Exactly my question as well
@quincycostello67268 ай бұрын
hold on i just realized you're right
@toni98108 ай бұрын
By definition, at any point, the circumference is perpendicular to the line that connects the center to that point of the circumference. When both circumferences are tangential in one point, they are parallel in that point, so their perpendiculars in that point are collinear, and pass through the center of both circles
@vidaroni8 ай бұрын
@@toni9810 Ahh, indeed! That makes total sense. Thanks!
@ounobaga18298 ай бұрын
@toni9810 i really wanna understand this can someone explain more simpler 🥲
@filipeoliveira70018 ай бұрын
How do you know the center of the semicircle, the center of the green circle, and the point of tangency between those two circles are colinear points?
@dimitrisdimitriadis49137 ай бұрын
The semicircle and the small circle share a tangent. This means that the two radiuses (radii?) are 1) parallel (both perpendicular to the same tangent) and 2) share a point (intersection with the tangent). If they are both parallel and share a point then they belong to the same line, they are collinear.
@filipeoliveira70017 ай бұрын
@@dimitrisdimitriadis4913 thank you!
@rudrodeepchatterjee7 ай бұрын
The line joining the centres of two circles (that touch each other) pass through the point of contact.
@filipeoliveira70017 ай бұрын
@@rudrodeepchatterjee got it
@jimimmler91105 ай бұрын
If I watch all these videos a million times I’ll be able to do them too without even thinking about it.
@nandisaand52873 ай бұрын
I was totally stumped by that first part, solvin for X in terms of R
@madly3315 Жыл бұрын
4:14 how do you know the red portion is half of 36?
@WhiiteCheddar Жыл бұрын
His first line he creates starts at the middle point of the 36 line. The X side of the triangle extends up from that point. The red portion extends down from that point.
@awaist11 ай бұрын
radius
@Rybz9 ай бұрын
lol I actually thought for a bit he got the problem wrong after I read this cause I went to check and his center of the circle should be on the same horizontal plane as the intersection of the left and bottom circles in the middle of the pic, and his center is slightly more down. but its just the drawing that is imprecise aha
@carpenterhillstudios83276 ай бұрын
Eventhough your speed is Interstate, I am able to follow. Had you been my algebra-trig teacher and said "How exciting" a couple of times, I'd be so much more facile. But, here you are on KZbin and here I am a geometer without too much of algebra or trig, and yet curious. Let's see where this goes.
@pro.cuber_09 ай бұрын
What was the point of the yellow circle then? was it just to distract us from directly applying this method? or is there an easier way to do this problem using the yellow circle?
@jaredf62058 ай бұрын
I’m not sure. The radius of the yellow circle is going to be some long decimal while the math for the radius of the green circle involved no decimals at all, they don’t seem too easily connected.
@bjarnesegaard57015 ай бұрын
GOod esplanations with out jumping crucial steps.. Good job - I enjoyed it :)
@deniseockey62046 ай бұрын
how would you solve for the radius of the other circle?
@dragonrings147 ай бұрын
No joke, I looked at it and immediately thought "well it has to be slightly smaller than a quarter of 36 so I bet it is 8" and it just so happened that my hunch was right.
@JK-jt3lr6 ай бұрын
At 72R = 9R^2 you could just divide by 9R on both sides, resulting in 8 = R
@barryomahony498329 күн бұрын
I'm thinking the yellow circle is a separate problem (much easier). It's radius is 18*(1-1/√2).
@foxlies01063 ай бұрын
really nice. I tried to do myself got stuck of course. thanks.
@alirezatorab55469 ай бұрын
Good question for my 15 year old students exam
@tortinwall8 ай бұрын
I made a start but I just went off at a tangent.
@jubeiiiiii8 ай бұрын
Its like a 14 15 year old Knowledge that's needed but a few l'oreille years to find the way to get into it
@CowboyBillUSA7 ай бұрын
45 years ago when I was 17, I could have solved this problem. Now I am just old and stupid. Nice work youngster!
@Siddhartha.Chatterjee22 ай бұрын
Right after 42 seconds, I was able to do it... My only doubt was if it is possible for a segment from centre of the semicircle to the circumference also passing through the centre of the smaller circle
@mrbookends9 ай бұрын
6 min is "potentially too long" for people? Amazing we're still a competitive country at this point.....
@gfen1x29 ай бұрын
why center of a green circle, "endpoint" and point of a vertical half radius is on the same line?
@chrishelbling38794 ай бұрын
Outstanding.
@zeynabbagirova6 ай бұрын
Could someone please do "how exciting" compilation 😂
@shreyasgowda089 ай бұрын
Me being a doctor watching this at 2Am. This is just awesome.
@the_andrewest_andrew4 ай бұрын
now this was sooo good... and it took youtube only 7 months to recommend it to me 😂😂
@JamesEducationalChannel20 күн бұрын
Hi good job on solving the problem but pls correct me if I’m wrong when u got 72R=9Rsquared could u of just divided by R to get 72 =9R then divided by 8 to get 9=R
@JTKmix9 ай бұрын
When you are at 72R = 9R^2, why not divide both sides by 9R? You end up getting R=8 and the whole thing is a little simpler.
@cod3r_9 ай бұрын
I guess this way you should imply BEFORE solving that R cannot be 0, because you cannot divide by 0. And that can be not the right way to solve this type of questions, because this way you can lose some of the answers/
@GabBR1259 ай бұрын
@@cod3r_It's geometry there's only one real solution. When you divides like the guy up there said, you get 8R = R², you divide R in both sides and you get R = 8.
@ellazychavito92228 ай бұрын
have to be careful as if the solution is zero you cant divide by the variable
@GabBR1258 ай бұрын
@@ellazychavito9222 yeah, but you can't have 0 meters (I forgot how you guys say the general form of unities of size). My comment still correct.
@GabBR1258 ай бұрын
@@ellazychavito9222 the point here is that you need your answer to be positive because it is geometry.
@didles1237 ай бұрын
Regarding the line at 0:30. How do we know it goes through the center of the green circle? I wouldn't have assumed that, so I'm a bit disappointed that it wasn't explained.
@Zeuseus66096 ай бұрын
The straight part of the left semicircle is forming a tangent line across the leftmost point of the circle. By definition, any line drawn perpendicular to the tangent line at the point it touches a circle will pass through the centre of the circle, because the part of the circle that touches the line is parallel to the line. Been a while since i did geometry, but hope that helps at least get the broad strokes across, i think he explains it more in some of his other vids where he uses that principle, think he skimmed over it here due to the time constraint.
@Helleb-hd8cj4 ай бұрын
I did it different. I used sohcahtoa, pythagoras theorem, b²-4ac, and the quadratic formula without using Y and I got a similar amswer to you
@Stan76702 ай бұрын
How do you know the radius you drew of the semicircle goes through the center of the green circle?
@johnfm695 ай бұрын
When you got to 36(2R)=9R^2, why did bother subtracting 72R and factoring? Just divide both rides by R to get 72=9R, which gives R=8.
@Zopeee3 ай бұрын
Since there must be 2 values for R, since its R² (R³ would be 3 R⁴ 4 and so on) just dividing by R would make it that you no longer see one of the two values(it doesnt realy matter anyway here, but it might have so better look at all the answers)
@FlintStryker7 ай бұрын
Clever! How, though, do you know that the line segments starting at the origins of the two large semi-circles go through the center of the green circle. I'm glitching on that point. Thanks!
@Ayvengo213 ай бұрын
5:41 you could just divide by 9R and so you will get that R = 8 because R can't be 0
@samschellhase88316 ай бұрын
How do you know that the second hypotenuse is R+18? How do you know it bisects the exact point that the circles are tangent to each other?
@hoduonggiabao5386 ай бұрын
Same question
@kit01348 ай бұрын
In the first part of this problem, how do you know the line from the tangent point of the green circle going through the green circle's center also goes through the center of the semicircle?
@tunneloflight8 ай бұрын
A line drawn from the center of a circle to its radius forms a right angle to a tangent line at any point on the circle. So two circles in contact (whether inside or outside) results in the same tangent line at the point of contact. Since the two lines from the two centers to the contact point form right angles at the contact point, both centers and the contact must be on a common straight line through the centers and the contact point.
@ChickenGeorgeClooney14 күн бұрын
Went to solve this on my own before watching the video, and was proud to find the answer was 9(2-sqrt2), until i came to the video and realized I found the radius of the YELLOW circle, not the green one.
@Robplayswithdragons6 ай бұрын
i dunno why but when you said the radius was r+18 i laughed saying ah the problem is rated R :P
@daniell74139 ай бұрын
How do you know the red portion is starts at the midpoint of the semicircle?
@zenedhyr76128 ай бұрын
x is line between center of semicircle and outer center of green circle.
@sanketbhagwat27179 ай бұрын
Hi! I throughly enjoyed the process of solving this problem with you :) I just wanted to know why did you go with a quadratic equation in the last part (9r2 - 72r = 0), couldnt we have solved it directly by : 9r2 = 72r ( cancelling 9r from both side) We get r=8.
@vojtinraketak30549 ай бұрын
dang you smarter than him
@sethb1249 ай бұрын
While that works for solving this particular problem where we only want positive solutions, that won't always work. The way he did it gave us 2 solutions, 0 and 8. For this problem, 0 wasn't a valid solution, but there are lots of problems where you don't want to get rid of that solution. Be careful dividing by variables because that usually removes solutions.
@chrishelbling38794 ай бұрын
When you draw the orange radius, length 18, how do you know it touches the tangency point of the 36 semi circle & the green circle? Or is it coincidence, or close, but meaning that it doesn't matter?
@c.jishnu3783 ай бұрын
If you look at the point of contact between the green circle and the 36circle's circumference, there can be a perpendicular radius of the green circle drawn there. There can also be a perpendicular radius of the 36circle that can be drawn, since both are perpendicular to the same point, they coincide. I got this after a while of thinking and my brain is now tired.
@arthurtheboy97539 ай бұрын
How exciting! I love this guy!
@JOnatanKERtis8 ай бұрын
I wouldn't have the nerves. I would just draw and measure with a ruler...
@sandraschenkel32749 ай бұрын
This was a very nice problem!! I enjoyed it A LOT!!
@MrMike31377 ай бұрын
This is why i was a mathlete. Yes...how exciting
@R.NarenSingh7 ай бұрын
How does a line from centre of semicircle to green circle is coincidental to centre of green circle
@CarameliaM3 ай бұрын
This may sound like philosophical bullshit, but your math videos actually help me cope with my executive dysfunction from ADHD - I "just" need to break down every task/problem into small enough parts that I can solve. Everything can be broken down into smaller steps and at some point the step is small enough for me to know the solution. Thank you :-)
@alfonso98053 ай бұрын
The next level question, Find the radius of the yellow circle
@barryomahony498327 күн бұрын
Its radius is 18*(1-1/√2)
@jondor6548 ай бұрын
Nice one , lazy query , is the yellow radius solvable .
@MrFrmartin7 ай бұрын
thinking outside the box..err.. circle, one this one
@pirotehs8 ай бұрын
I am confused with just one aspect. How do You know that first line Andy draw connect "center" of big circle with point where big circle touches green circle? And, no matter how small green circle is, If You draw line from center of vertical line to point where where both circles touch, it will always go through center of green circle?
@jeremy-bahadirli8 ай бұрын
Good question. The green circle and the large semicircle are touching on the edge. That means the green circle and the large semicircle have the same tangent line at that point. The black line Andy drew is perpendicular to this tangent line of both circles. Since the tangent line is the same among both circles, and the black line is drawn perpendicular to it, it will by definition extend through the center of both the green circle and large semicircle.
@jondor6548 ай бұрын
Am I right to assume that mostly these are minimal length heuristics , with no equals .
@Heng01265 ай бұрын
x is not equal to y - 18. Because both horizontal tangents are not the same. So y is less than x+18.
@charlescox2905 ай бұрын
I'm looking at the diagram, but it doesn't say it is drawn to scale. How do we know those are semicircles?
@timjackson75384 ай бұрын
Loved it
@why_nur9 ай бұрын
bro almost forgot to say how exciting
@Noel-u3m5 ай бұрын
That was just great
@Boredperson3608 ай бұрын
that yellow circle will not haunt me xD
@colteningram56035 ай бұрын
Why can't you replace x² with 36(9-R) for the first equation? I'm not trying to be critical, I'm just curious
@ernestlyernest6 ай бұрын
How do you know that the centre of green circle, Center of semi circle, and point where curved surfaces of green circle and semicircle touched are all in the same line?
@c.jishnu3783 ай бұрын
If you look at the point of contact between the green circle and the 36circle's circumference, there can be a perpendicular radius of the green circle drawn there. There can also be a perpendicular radius of the 36circle that can be drawn, since both are perpendicular to the same point, they coincide. I got this after a while of thinking and my brain is now tired.
@tunneloflight8 ай бұрын
Since the yellow circle is there and since this problem is all about circles, I rather thought you would feel compelled to answer the four other obvious questions: 1) What is the radius of the yellow circle (and how does that compare to the green circle and the orange circles)? 2) Is a line through the centers of the green and yellow circles parallel to the vertical base of the left orange semicircle? 3) If there were a second matching green circle, would the line through their two centers pass through the intersection of the two orange circles? 4) Does a circle exist that could touch the contact points of the pairs of green and orange circles? And if so, what is its radius?
@dimitrisdimitriadis49137 ай бұрын
Spoilers below Btw, for the rest of the answers, assume 2a=36 (I solve this type of exercises parametrically, it creates better insights than numerically) So for example I got R=a*4/9 (which is 8 if you substitute) 1) The yellow radius r1 is found by drawing the radius of the left orange semicircle, and the linear segment between the bottom left of the drawing where the diameters intersect and the center of the drawing, where the circles intersect, and realizing there's a ton of 90 and 45 degree angles. r1=a*(1-1/sqrt(2)) 2) From 1) and all those 45 degree angles it follows that the distance between the center of the yellow circle and the leftmost vertical line is a/2. The distance of the center of the green circle from the same line is 4a/9 (it's just its radius). So it's not parallel. 3) Because of symmetry, that line you're describing is at a 45 degree angle with the two orange diameters. The same is true of a linear segment drawn between the top left corner of the drawing and the center of the drawing where the circles intersect. So your question becomes equivalent to "is the center of the green circle on that linear segment?" and the answer is no (pretty easy to prove) 4) touch as in share a tangent? I'll reply later, g2g
@pauldowney92926 ай бұрын
I could not see an algebra solution. Did it graphically. The center of the circle is found as you start at zero for R and increse it. You have 3 curves that eventually meet at a single point as R approaches 8. The 3 curves are x=R, the upper curve circle as the radius is 18-R and the lower circle as the radius is 18+R. Did it quick and dirty on a TI-84. Equation 1, the upper circle ... sqrt((18-R)squared-X squared)) +18.... equation 2, the lower circle .... sqrt(18+R)squared-(X-18)squared).... equation 3 is just a vertical line for x=R ..... (X-R)*10000. Think of as R gets bigger the alowable center position of the circle is restricted by needing to be R distance from the y axis and R distance from the upper circle and R distance from the lower circle. The allowable center point is inside the 3 curves and as R increase you get one allowable point as R gets its maximum value of 8.
@k0walsk5 ай бұрын
Just so exciting
@amysleftelbow42539 ай бұрын
GREAT JON ANDREW!!! WOOOOOOOOO LETS GO BABYYYYY
@JaharNarishma5 ай бұрын
I did not solve this. Could be that I try solving them in my head, could be that I did not know how to approach this and would need a lot of exploratory algebra.
@f666855 ай бұрын
Pretty good
@hoduonggiabao5386 ай бұрын
How do you prove the hypotenuse is R+18? What if there's a small gap between radius R and semicircle?
@c.jishnu3783 ай бұрын
If you look at the point of contact between the green circle and the 36circle's circumference, there can be a perpendicular radius of the green circle drawn there. There can also be a perpendicular radius of the 36circle that can be drawn, since both are perpendicular to the same point, they coincide. I got this after a while of thinking and my brain is now tired.
@JudithOpdebeeck8 ай бұрын
wen you got to 72R=9R^2 m first tougt was to just divide both sides by R, giving 72=9R, so R=72/9=8
@ajamessssss9 ай бұрын
I have only one doubt. Please help me. How do we know that the red part below x is equal to the radius of the circle? The x may or may not overlap with the radius. I believe don't know that for sure.
@sykroza9 ай бұрын
0:26
@ajamessssss9 ай бұрын
@@sykroza what's that?
@sykroza9 ай бұрын
@@ajamessssss he made a line starting from the center of the semi circle which became the hypotenuse of the triangle with one side as x. Therefore, the red part below the x starts from the center down to the edge of the semi circle and is equal to the radius. Is that what you were asking?
@GabBR1259 ай бұрын
When he drew the line from the center of the green circle to the bottom semi-circle
@ajamessssss9 ай бұрын
@@sykroza Yes. Thank you.
@jprospero6 ай бұрын
What's the radius of the orange circle? 😛
@franciszekkowalski1735 Жыл бұрын
5:40 you can just divide both sides by 9R
@leuischoi817011 ай бұрын
In an academic or formal setting, You need to express that R has multiple possible solutions (including imaginary or irrational numbers)
@ahmetumutyemen31909 ай бұрын
Man who called Andy teaching basic math in 6 minutes
@sebastianorellana82010 ай бұрын
Excitante
@fatatalano3239 ай бұрын
I have a question that why the red line part in the end is 18 so certainly