Angle of Twist of Shaft with Torsion

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The Ryder Project

Күн бұрын

This video demonstrates how to calculate the angle of twist for a shaft which has multiple applied torques.

Пікірлер: 30

@phillipyt8876 3 жыл бұрын

Best explanations on shafts so far. Thanks so much!

@user-vt5kw3hb7f Жыл бұрын

Thank you for this! You really explained it well! I am really at loss on the internal torque, but you explained it clearly with the fbd and td. Thanks again!

@lolasykes4212 4 жыл бұрын

GREAT VIDEO. You taught me in 12 mins what my lecturer couldnt teach in 2 hours.

@mattbibby1164 2 жыл бұрын

That was really helpful, thank you.

@davesamson3992 Жыл бұрын

I'm glad that this kind of video exist, compared to my prof, it easy to understand

@wilfredthomas6601 3 жыл бұрын

Thousands of gratitude. Actually you helped me to achieve 2$ in 12 min

@GODARADEEPANSHU Жыл бұрын

THANK YOU MAAM .LOVE FROM INDIA 🇮🇳🇮🇳

@hamoodkathem2510 3 жыл бұрын

Hello Teacher , Thanks for your helpful videos and it’s help me a lot . I really appreciate your efforts that you are putting to help students who are have some difficulties like me :( . I’m sorry for my English ,it’s my second language . Thanks a lot Prof ❤️❤️❤️❤️❤️❤️ The words aren’t helping me to describe to you how I appreciate it :( I’m going to share the videos with my colleagues that all what can I do to thank you 🙏

@gilmaralberto6720 3 жыл бұрын

Amazing. Thanks .

@kaursingh637 Жыл бұрын

madam - excellent - excellent - excellent = concepts cleared - thank u -india

@craig7878 Ай бұрын

Hi, Could you please explain the use of the right-hand rule? Can we simply decide the direction of the x-axis as we want? Additionally, can we define the thumb’s direction (inwards or outwards) as positive based on our preference? I’m a bit uncertain about how we establish these definitions and under what conditions they apply. Thank you.

@user-qm8dz8dn7h 3 жыл бұрын

thank you

@imranhossainraju7510 Жыл бұрын

thanks .

@An__Aspirant__ 5 жыл бұрын

Good

@AqibAli-lq7ki 3 жыл бұрын

The diameter d=100mm, The diameter of BC d2=100mm. Me = 3.14 kN·m, The allowable shear stress [] = 60MPa. Draw the internal torque diagram and point out the dangerous section ； Try to determine and check strength condition; Check stiffness condition.

@aumlanislamrupak2486 8 ай бұрын

❤❤❤

@user-nz8sh3ep8y 4 жыл бұрын

what if problem asked to find the angle of twist on D

@theryderproject5053 4 жыл бұрын

You would need to be asked the angle of twist relative to some other point. For example, twist at D relative to A. Then you would just look to calculate the twist in the sections between the two points. (In the existing wording of the question, it infers to look relative to the fixed point).

@shannaidu6645 3 жыл бұрын

The torque @ TBC is to be negative 20N.m since you defined clockwise torque as positive. Right?

@theryderproject5053 3 жыл бұрын

From about 2.20 I talked about the sign convention I applied. To be honest it doesn't really matter which way you apply the signs just as long as you're consistent.

@shannaidu6645 3 жыл бұрын

@@theryderproject5053 my apologies in advance if I sound ridiculous... my concern here is that you have defined clockwise torque @B as positive. In that case, how is torque @ section BC defined as positive again? Is that not inconsistency given the sign convention you defined? Another concern would be if torque @BC is determined as positive, the final answer for angle of twist is affected hence i wanna be sure? Thank you for your prompt response.

@theryderproject5053 3 жыл бұрын

@@shannaidu6645 The torque diagram at 4.40 is where the torque in each section comes from. I have continued the sign convention here (the one discussed earlier) where the torque applied at B is positive. Does that answer your question?

@shannaidu6645 3 жыл бұрын

@@theryderproject5053 ur torque diagram makes complete sense. but im using the sectioning method . having a tough time tryin to relate the both of them.

@theryderproject5053 3 жыл бұрын

@@shannaidu6645 is the sectioning method where you take a cut through a section and then calculate the internal torque at that point? If so, it should be equivalent - just apply the process of drawing a FBD with the internal unknown and then use equilibrium to solve for it.